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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 11 - Properties of Gases"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1 - Pg 172"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the volume of the appratus\n",
+      "#initialization of varaibles\n",
+      "P1=15. #psia\n",
+      "T1=80+460. #R\n",
+      "dm=3. #lb\n",
+      "T2=75+460. #R\n",
+      "P2=25. #psia\n",
+      "#calculations\n",
+      "mratio=P1*T2/(P2*T1)\n",
+      "m2=dm/(1-mratio)\n",
+      "V2=m2*55.16*T2/(P2*144.)\n",
+      "#results\n",
+      "print '%s %.1f %s' %(\"Volume of the apparatus =\",V2,\"cu ft\")\n",
+      "print '%s' %(\"The answer is a bit different due to rounding off error in textbook\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Volume of the apparatus = 60.6 cu ft\n",
+        "The answer is a bit different due to rounding off error in textbook\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2 - Pg 176"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate the specific heats at constant pressure and volume\n",
+      "#initialization of varaibles\n",
+      "R=48.3 #ft lb/lb R\n",
+      "k=1.4\n",
+      "#calculations\n",
+      "dc=R/778.\n",
+      "cp=k*dc/(k-1)\n",
+      "cv=cp/k\n",
+      "#results\n",
+      "print '%s %.3f %s' %(\"Specific heat at constant volume = \",cv,\"B/lb R\")\n",
+      "print '%s %.3f %s' %(\"\\n Specific heat at constant pressure = \",cp,\"B/lb R\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Specific heat at constant volume =  0.155 B/lb R\n",
+        "\n",
+        " Specific heat at constant pressure =  0.217 B/lb R\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3 - Pg 177"
+     ]
+    },
+    {
+     "cell_type": "raw",
+     "metadata": {},
+     "source": [
+      "This is a theoretical example."
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      " Example 4 - Pg 180"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate the enthalpy generated\n",
+      "#initialization of varaibles\n",
+      "import math\n",
+      "P1=100. #psia\n",
+      "P2=10. #psia\n",
+      "T1=140. +460 #R\n",
+      "g=1.4\n",
+      "cp=0.248\n",
+      "#calculations\n",
+      "dh=g*55.16*T1*(math.pow((P2/P1),((g-1)/g)) -1)/(g-1)*0.01286 #0.01286 is the conversion factor\n",
+      "T2=T1*math.pow((P2/P1),((g-1)/g))\n",
+      "dh2=cp*(T2-T1)\n",
+      "#results\n",
+      "print '%s %d %s' %(\"In method 1, Enthalpy = \",dh,\"Btu/lb\")\n",
+      "print '%s %.1f %s' %(\"\\n In method 2, Enthalpy =\",dh2,\"ft lb/lb\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "In method 1, Enthalpy =  -718 Btu/lb\n",
+        "\n",
+        " In method 2, Enthalpy = -71.7 ft lb/lb\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5a - Pg 186"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate the changes in Enthalpy and Specific Volume\n",
+      "#initialization of varaibles\n",
+      "import math\n",
+      "P1=100. #psia\n",
+      "T1=2000.+460 #R\n",
+      "P2=15. #psia\n",
+      "g=1.4\n",
+      "cp=0.24\n",
+      "#calculations\n",
+      "v1=53.34*T1/(P1*144.)\n",
+      "v2=53.34*T1*math.pow((P1/P2),(1/g)) /(P1*144)\n",
+      "T2=T1*P2*v2/(P1*v1)\n",
+      "dh=cp*(T2-T1)\n",
+      "dv=v2-v1\n",
+      "#results\n",
+      "print '%s %d %s' %(\"Change in enthalpy =\",dh,\"B/lb\")\n",
+      "print '%s %.1f %s' %(\"\\n Specific volume change = \",dv,\"cu ft/lb\")\n",
+      "print '%s' %(\"The answer is a bit different due to rounding off error in textbook\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Change in enthalpy = -247 B/lb\n",
+        "\n",
+        " Specific volume change =  26.2 cu ft/lb\n",
+        "The answer is a bit different due to rounding off error in textbook\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5b - Pg 186"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate the changes in Enthalpy and Specific Volume\n",
+      "#initialization of varaibles\n",
+      "import math\n",
+      "P1=100. #psia\n",
+      "T1=2000.+460 #R\n",
+      "P2=15. #psia\n",
+      "g=1.4\n",
+      "cp=0.276\n",
+      "cv=0.207\n",
+      "T2=1520. #R\n",
+      "#calculations\n",
+      "k=cp/cv\n",
+      "v1=53.34*T1/(P1*144)\n",
+      "v2=v1*math.pow((P1/P2),(1/k))\n",
+      "dh=cp*(T2-T1)\n",
+      "dv=v2-v1\n",
+      "#results\n",
+      "print '%s %d %s' %(\"Enthalpy change =\",dh,\"B/lb\")\n",
+      "print '%s %.1f %s' %(\"\\n Volume change =\",dv,\"cu t/lb\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Enthalpy change = -259 B/lb\n",
+        "\n",
+        " Volume change = 28.7 cu t/lb\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5c - Pg 186"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate the changes in Enthalpy and Specific Volume\n",
+      "#initialization of varaibles\n",
+      "import math\n",
+      "P1=100. #psia\n",
+      "T1=2000.+460 #R\n",
+      "P2=15. #psia\n",
+      "g=1.4\n",
+      "cp=0.276\n",
+      "cv=0.207\n",
+      "T2=1520. #R\n",
+      "#calculations\n",
+      "h1=634.4\n",
+      "pr1=407.3\n",
+      "pr2=pr1*P2/P1\n",
+      "print '%s' %(\"From table 1,\")\n",
+      "T2=1535. #R\n",
+      "h2=378.44\n",
+      "dh=h2-h1\n",
+      "v1=53.34*T1/(P1*144)\n",
+      "v2=53.34*T2/(P2*144.)\n",
+      "dv=v2-v1\n",
+      "#results\n",
+      "print '%s %.2f %s' %(\"Enthalpy change = \",dh,\"B/lb\")\n",
+      "print '%s %.1f %s' %(\"\\n Volume change =\",dv,\"cu ft/lb\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "From table 1,\n",
+        "Enthalpy change =  -255.96 B/lb\n",
+        "\n",
+        " Volume change = 28.8 cu ft/lb\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file