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Diffstat (limited to 'Materials_Science/Chapter08.ipynb')
-rwxr-xr-x | Materials_Science/Chapter08.ipynb | 179 |
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diff --git a/Materials_Science/Chapter08.ipynb b/Materials_Science/Chapter08.ipynb deleted file mode 100755 index 7ab3ee40..00000000 --- a/Materials_Science/Chapter08.ipynb +++ /dev/null @@ -1,179 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:34ae042b330defbf3a9166ffcdabea3a9847c3ed545aa16f3851917a2138bfe6"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter08:Deformation of Metals"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex8.1:pg-175"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Example 8.1: critical resolved shear stress of silver\n",
- " \n",
- "\n",
- "Ts=15;#tensile stress in Mpa\n",
- "d=[1,1,0];\n",
- "d1=[1,1,1];\n",
- "csda=((d[0]*d1[0])+(d[1]*d1[1])+(d[2]*d1[2]))/((math.sqrt(d[0]**2+d[1]**2+d[2]**2))*math.sqrt(d1[0]**2+d1[1]**2+d1[2]**2));#angle degree\n",
- "d2=[0,1,1];\n",
- "csdb=((d[0]*d2[0])+(d[1]*d2[1])+(d[2]*d2[2]))/((math.sqrt(d[0]**2+d[1]**2+d[2]**2))*math.sqrt(d2[0]**2+d2[1]**2+d2[2]**2));#angle degree\n",
- "t=Ts*csda*csdb;#critical resolved shear stress in MPa\n",
- "print round(t,2),\"= critical resolved shear stress in MPa\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "6.12 = critical resolved shear stress in MPa\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex8.2:pg-186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Example 8.2: yield strength of material\n",
- " \n",
- "import numpy.linalg as lin\n",
- "import math\n",
- "ys1=115;# yeild strength in MN/mm**2\n",
- "ys2=215;# yeild strength in MN/mm**2\n",
- "d1=0.04;#diamtere in mm\n",
- "d2=0.01;#diamtere in mm\n",
- "A=numpy.array([[2 ,10], [1 ,10]]);\n",
- "B=numpy.array([230,215]);\n",
- "x=lin.solve(A,B)\n",
- "si=x[0];# in MN/mm**2\n",
- "k=x[1];#\n",
- "d3=0.016;#in mm\n",
- "sy= si +(k/math.sqrt(d3));#yeild strength for a grain size in MN/mm**2\n",
- "print round(sy,2),\"=yeild strength for a grain size in MN/mm**2\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "173.11 =yeild strength for a grain size in MN/mm**2\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex8.3:pg-186"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "# Example 8.3: yield strength of material\n",
- "import numpy.linalg as lin\n",
- "import math\n",
- "ys1=120;# yeild strength in MN/mm**2\n",
- "ys2=220;# yeild strength in MN/mm**2\n",
- "d1=0.04;#diamtere in mm\n",
- "d2=0.01;#diamtere in mm\n",
- "A=numpy.array([[2 ,10], [1 ,10]]);\n",
- "B=numpy.array([240,220]);\n",
- "x=lin.solve(A,B)\n",
- "si=x[0];# in MN/mm**2\n",
- "k=x[1];#\n",
- "d3=0.025;#in mm\n",
- "sy= si +(k/math.sqrt(d3));#yeild strength for a grain size in MN/mm**2\n",
- "print round(sy,2),\"= yeild strength for a grain size in MN/mm**2\"\n",
- "\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "146.49 = yeild strength for a grain size in MN/mm**2\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Ex18.4:pg-193"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Example 8.4 : grain diameter\n",
- "import math \n",
- "\n",
- "#given data :\n",
- "N=9; # ASTM number\n",
- "m=8*2**N; # no. of grains [er square millimetre\n",
- "grain=1/math.sqrt(m);\n",
- "print round(grain,4),\"=the grain diameter(mm) \"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "0.0156 =the grain diameter(mm) \n"
- ]
- }
- ],
- "prompt_number": 2
- }
- ],
- "metadata": {}
- }
- ]
-}
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