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Diffstat (limited to 'Machine_Design_by_U.C._Jindal/Ch30.ipynb')
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diff --git a/Machine_Design_by_U.C._Jindal/Ch30.ipynb b/Machine_Design_by_U.C._Jindal/Ch30.ipynb deleted file mode 100755 index 335560f0..00000000 --- a/Machine_Design_by_U.C._Jindal/Ch30.ipynb +++ /dev/null @@ -1,210 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:55c40faafb847932f0fdcda855b3af16f1a2e4ef45941baaf0d7ee692a22c20c" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Ch:30 Chain drive" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 30-1 - Page 778" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "from __future__ import division\n", - "from math import sqrt, pi\n", - "n1=17#\n", - "n2=51#\n", - "C=300#\n", - "p=9.52#\n", - "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", - "x=(Ln-((n2+n1)/(2)))**2#\n", - "y=8*(((n2-n1)/(2*pi))**2)#\n", - "z=Ln-((n1+n2)/2)#\n", - "C=(p/4)*(z+(sqrt(x-y)))\n", - "\n", - "\n", - " # printing data in scilab o/p window\n", - "print \"C is %0.2f mm \"%(C)#\n", - " " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "C is 300.00 mm \n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 30-2 - Page 778" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "from math import tan\n", - "G=4#\n", - "n1=17#\n", - "n2=n1*G#\n", - "N1=2300#\n", - "Kc=1.2# #from table 30-2\n", - "p=12.7# #fom table 30-1\n", - "D1=p*n1#\n", - "D2=p*n2#\n", - "phi=2*10.6#\n", - "x=tan(phi/2)# #phi/2 = 10.6deg, from table 30-3\n", - "Da1=(p/x)+(0.6*p)#\n", - "Da2=(p/x*4)+(0.6*p)#\n", - "Cmin=Kc*((Da1+Da2)/2)#\n", - "Ln1=(2*Cmin/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/Cmin))#\n", - "Ln1=80#\n", - "print \"Ln is %0.0f \"%(Ln1)#" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Ln is 80 \n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 30-3 - Page 779" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "N1=1000#\n", - "N2=500#\n", - "P=2.03*10**3# #from table 30-8\n", - "K1=1.26#\n", - "Ks=1#\n", - "#let Pc be the power transmitting capacity of the chain\n", - "Pc=P*K1/Ks#\n", - "p=9.52#\n", - "n1=21#\n", - "n2=42#\n", - "V=n1*p*N1/(60*10**3)#\n", - "#Let the chain tension be T\n", - "T=Pc/V#\n", - "#Let the breaking load be BL\n", - "BL=10700#\n", - "FOS=BL/T#\n", - "C=50*p#\n", - "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", - "L=Ln*p#\n", - "Pc=Pc*10**-3#\n", - "print \" Pc is %0.2f KW \"%(Pc)#\n", - "print \"\\n V is %0.3f m/s \"%(V)#\n", - "print \"\\n T is %0.1f N \"%(T)#\n", - "print \"\\n FOS is %0.2f \"%(FOS)#\n", - "print \"\\n L is %0.2f mm \"%(L)#\n", - "\n", - "#The difference in the value of L and T is due to rounding-off the values." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Pc is 2.56 KW \n", - "\n", - " V is 3.332 m/s \n", - "\n", - " T is 767.6 N \n", - "\n", - " FOS is 13.94 \n", - "\n", - " L is 1254.01 mm \n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 30-5 - Page 780" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "G=2#\n", - "P=5000#\n", - "Ks=1.7#\n", - "Pd=P*Ks#\n", - "K2=1.7#\n", - "p=15.88#\n", - "n1=17#\n", - "n2=n1*G#\n", - "D1=n1*p#\n", - "D2=n2*p#\n", - "C=40*p#\n", - "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n", - "L=Ln*p#\n", - "print \"L is %0.2f mm \"%(L)#\n", - "#The difference in the value of L is due to rounding-off the values." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "L is 1678.25 mm \n" - ] - } - ], - "prompt_number": 4 - } - ], - "metadata": {} - } - ] -}
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