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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:55c40faafb847932f0fdcda855b3af16f1a2e4ef45941baaf0d7ee692a22c20c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Ch:30 Chain drive"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "exa 30-1 - Page 778"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "from math import sqrt, pi\n",
+ "n1=17#\n",
+ "n2=51#\n",
+ "C=300#\n",
+ "p=9.52#\n",
+ "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
+ "x=(Ln-((n2+n1)/(2)))**2#\n",
+ "y=8*(((n2-n1)/(2*pi))**2)#\n",
+ "z=Ln-((n1+n2)/2)#\n",
+ "C=(p/4)*(z+(sqrt(x-y)))\n",
+ "\n",
+ "\n",
+ " # printing data in scilab o/p window\n",
+ "print \"C is %0.2f mm \"%(C)#\n",
+ " "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "C is 300.00 mm \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "exa 30-2 - Page 778"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from math import tan\n",
+ "G=4#\n",
+ "n1=17#\n",
+ "n2=n1*G#\n",
+ "N1=2300#\n",
+ "Kc=1.2# #from table 30-2\n",
+ "p=12.7# #fom table 30-1\n",
+ "D1=p*n1#\n",
+ "D2=p*n2#\n",
+ "phi=2*10.6#\n",
+ "x=tan(phi/2)# #phi/2 = 10.6deg, from table 30-3\n",
+ "Da1=(p/x)+(0.6*p)#\n",
+ "Da2=(p/x*4)+(0.6*p)#\n",
+ "Cmin=Kc*((Da1+Da2)/2)#\n",
+ "Ln1=(2*Cmin/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/Cmin))#\n",
+ "Ln1=80#\n",
+ "print \"Ln is %0.0f \"%(Ln1)#"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Ln is 80 \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "exa 30-3 - Page 779"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "N1=1000#\n",
+ "N2=500#\n",
+ "P=2.03*10**3# #from table 30-8\n",
+ "K1=1.26#\n",
+ "Ks=1#\n",
+ "#let Pc be the power transmitting capacity of the chain\n",
+ "Pc=P*K1/Ks#\n",
+ "p=9.52#\n",
+ "n1=21#\n",
+ "n2=42#\n",
+ "V=n1*p*N1/(60*10**3)#\n",
+ "#Let the chain tension be T\n",
+ "T=Pc/V#\n",
+ "#Let the breaking load be BL\n",
+ "BL=10700#\n",
+ "FOS=BL/T#\n",
+ "C=50*p#\n",
+ "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
+ "L=Ln*p#\n",
+ "Pc=Pc*10**-3#\n",
+ "print \" Pc is %0.2f KW \"%(Pc)#\n",
+ "print \"\\n V is %0.3f m/s \"%(V)#\n",
+ "print \"\\n T is %0.1f N \"%(T)#\n",
+ "print \"\\n FOS is %0.2f \"%(FOS)#\n",
+ "print \"\\n L is %0.2f mm \"%(L)#\n",
+ "\n",
+ "#The difference in the value of L and T is due to rounding-off the values."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Pc is 2.56 KW \n",
+ "\n",
+ " V is 3.332 m/s \n",
+ "\n",
+ " T is 767.6 N \n",
+ "\n",
+ " FOS is 13.94 \n",
+ "\n",
+ " L is 1254.01 mm \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "exa 30-5 - Page 780"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "G=2#\n",
+ "P=5000#\n",
+ "Ks=1.7#\n",
+ "Pd=P*Ks#\n",
+ "K2=1.7#\n",
+ "p=15.88#\n",
+ "n1=17#\n",
+ "n2=n1*G#\n",
+ "D1=n1*p#\n",
+ "D2=n2*p#\n",
+ "C=40*p#\n",
+ "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
+ "L=Ln*p#\n",
+ "print \"L is %0.2f mm \"%(L)#\n",
+ "#The difference in the value of L is due to rounding-off the values."
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "L is 1678.25 mm \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file