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Diffstat (limited to 'Machine_Design_by_U.C._Jindal/Ch16.ipynb')
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diff --git a/Machine_Design_by_U.C._Jindal/Ch16.ipynb b/Machine_Design_by_U.C._Jindal/Ch16.ipynb deleted file mode 100755 index 6197d784..00000000 --- a/Machine_Design_by_U.C._Jindal/Ch16.ipynb +++ /dev/null @@ -1,438 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:01311d1278cad60b1c0d60099bb705f52b2b4566cc66cef72df1eddeb97f8ca1" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Ch:16 Power screws" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-1 - Page 450" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "from math import atan, pi, sqrt, tan\n", - "d=30#\n", - "W=20*10**3#\n", - "r1=8#\n", - "r2=16#\n", - "p=6#\n", - "u1=0.2#\n", - "u2=0.15#\n", - "dm=d-(p/2)#\n", - "alpha=atan(p/(pi*dm))#\n", - "phi=atan(u1)#\n", - "rm=(r1+r2)/2#\n", - "Ttr=W*((dm*tan(alpha+phi)/2)+(u2*rm))#\n", - "Ttr=Ttr*10**-3#\n", - "print \"Ttr is %0.3f Nm \"%(Ttr)#\n", - "#The answer to Ttr is slightly different than in the book due to rounding-off of values." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Ttr is 110.148 Nm \n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-2 - Page 451" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "from math import cos\n", - "d=50#\n", - "W=20*10**3#\n", - "r1=10#\n", - "r2=30#\n", - "p=7#\n", - "u1=0.12/cos(15*pi/180)#\n", - "u2=0.15#\n", - "dm=d-(p/2)#\n", - "alpha=atan(3*p/(pi*dm))#\n", - "phi=atan(u1)#\n", - "rm=(r1+r2)/2#\n", - "Tr=W*((dm*tan(alpha+phi)/2)+(u2*rm))#\n", - "Tr=Tr*10**-3#\n", - "Te=W*((dm*tan(phi-alpha)/2)+(u2*rm))#\n", - "Te=Te*10**-3#\n", - "n=dm/2*tan(alpha)/(dm*tan(alpha+phi)/2+(u2*rm))#\n", - "L=0.30#\n", - "Ph=Tr/L#\n", - "print \" Tr is %0.2f Nm \"%(Tr)#\n", - "print \"\\n Te is %0.3f Nm \"%(Te)#\n", - "print \"\\n n is %0.4f \"%(n)#\n", - "print \"\\n Ph is %0.2f N \"%(Ph)#\n", - "#The answers to Tr, Te and Ph is slightly different than in the book due to rounding-off of values." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Tr is 187.49 Nm \n", - "\n", - " Te is 51.691 Nm \n", - "\n", - " n is 0.3489 \n", - "\n", - " Ph is 624.96 N \n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-3 - Page 452" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "d=30#\n", - "W=5*10**3#\n", - "p=5#\n", - "rm=45/2#\n", - "u1=0.15/cos(14.5*pi/180)#\n", - "u2=0.15#\n", - "dm=d-(p/2)#\n", - "alpha=atan(p/(pi*dm))#\n", - "phi=atan(u1)#\n", - "Tr1=W*((dm*tan(alpha+phi)/2)+(u2*rm))#\n", - "Tr1=Tr1*10**-3#\n", - "n1=dm/2*tan(alpha)/(dm*tan(alpha+phi)/2+(u2*rm))#\n", - "T1=W*((dm*tan(phi-alpha)/2)+(u2*rm))#\n", - "T1=T1*10**-3#\n", - "n2=dm/2*tan(alpha)/(dm*tan(phi-alpha)/2+(u2*rm))#\n", - "u2=0.02#\n", - "Tr2=W*((dm*tan(alpha+phi)/2)+(u2*rm))#\n", - "Tr2=Tr2*10**-3#\n", - "n3=dm/2*tan(alpha)/(dm*tan(alpha+phi)/2+(u2*rm))#\n", - "Te=W*((dm*tan(phi-alpha)/2)+(u2*rm))#\n", - "Te=Te*10**-3#\n", - "n4=dm/2*tan(alpha)/(dm*tan(phi-alpha)/2+(u2*rm))#\n", - "print \" Tr1 is %0.3f Nm \"%(Tr1)#\n", - "print \"\\n n1 is %0.4f \"%(n1)#\n", - "print \"\\n T1 is %0.3f Nm \"%(T1)#\n", - "print \"\\n n2 is %0.4f \"%(n2)#\n", - "print \"\\n Tr2 is %0.3f Nm \"%(Tr2)#\n", - "print \"\\n n3 is %0.4f \"%(n3)#\n", - "print \"\\n Te is %0.3f Nm \"%(Te)#\n", - "print \"\\n n4 is %0.4f \"%(n4)#\n", - " \n", - " #The answer to T1 is misprinted in the book." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Tr1 is 31.456 Nm \n", - "\n", - " n1 is 0.1265 \n", - "\n", - " T1 is 23.307 Nm \n", - "\n", - " n2 is 0.1707 \n", - "\n", - " Tr2 is 17.156 Nm \n", - "\n", - " n3 is 0.2319 \n", - "\n", - " Te is 9.007 Nm \n", - "\n", - " n4 is 0.4418 \n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-4 - Page 453" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "d=28#\n", - "P=300#\n", - "L=180#\n", - "p=8#\n", - "r1=16#\n", - "r2=46#\n", - "rm=(r1+r2)/2#\n", - "u1=0.12#\n", - "u2=0.15#\n", - "dm=d-(p/2)#\n", - "alpha=atan(p/(pi*dm))#\n", - "phi=atan(u1)#\n", - "T=P*L#\n", - "F=T/((dm*tan(alpha+phi)/2)+(u2*rm))#\n", - "F=F*10**-3#\n", - "print \"F is %0.3f kN \"%(F)#" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "F is 7.299 kN \n" - ] - } - ], - "prompt_number": 4 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-5 - Page 453" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "d=25#\n", - "p=8#\n", - "F=392.4#\n", - "L=250#\n", - "l=p*2#\n", - "u=0.14#\n", - "dm=d-(p/2)#\n", - "alpha=atan(l/(pi*dm))#\n", - "phi=atan(u)#\n", - "T=dm*tan(alpha+phi)/2#\n", - "M=F*L#\n", - "P=M/T*10**-3#\n", - "print \"P is %0.1f kN \"%(P)#" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "P is 23.6 kN \n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-6 - Page 454" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "d=52#\n", - "W=2.2*10**3#\n", - "p=8#\n", - "r1=15#\n", - "r2=30#\n", - "rm=(r1+r2)/2#\n", - "u1=0.15/cos(14.5*pi/180)#\n", - "dm=d-(p/2)#\n", - "alpha=atan(p/(pi*dm))#\n", - "phi=atan(u1)#\n", - "Ts=W*dm*tan(alpha+phi)/2#\n", - "u2=0.12#\n", - "Tc=u2*W*rm#\n", - "T=10**-3*(Ts+Tc)#\n", - "N=40#\n", - "w=2*pi*N/60#\n", - "P=T*w*10**-3#\n", - "To=W*dm/2*tan(alpha)#\n", - "n=To/(T*10**3)#\n", - "print \"P is %0.2f KW \"%(P)#\n", - "print \"\\nn is %0.4f \"%(n)#" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "P is 0.07 KW \n", - "\n", - "n is 0.1659 \n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-7 - Page 455" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "alpha=atan(2*0.2/(pi*0.9))#\n", - "u1=0.15#\n", - "phi=atan(u1)#\n", - "P=200#\n", - "L=250#\n", - "Tt=P*L#\n", - "W=10*10**3#\n", - "u2=0.15#\n", - "x=Tt/W#\n", - "d=x/0.1716#\n", - "d=30#\n", - "p=6#\n", - "dr=0.8*d#\n", - "d=24#\n", - "p=5#\n", - "dr=d-p#\n", - "dm=d-(p/2)#\n", - "print \"d is %0.0f mm \"%(d)#\n", - "print \"\\np is %0.0f mm \"%(p)#" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "d is 24 mm \n", - "\n", - "p is 5 mm \n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "exa 16-8 - Page 456" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "FOS=3#\n", - "sigut=380#\n", - "Ta=0.577*sigut/FOS#\n", - "d=25#\n", - "Tus=460#\n", - "Ps=pi*d*Tus#\n", - "siga=127#\n", - "dr=sqrt(Ps*4/(pi*siga))#\n", - "d=30#\n", - "p=6#\n", - "dr=d-p#\n", - "dm=d-(p/2)#\n", - "u1=0.15#\n", - "alpha=atan(p*2/(pi*dm))#\n", - "phi=atan(u1)#\n", - "T=Ps*dm*tan(alpha+phi)/2#\n", - "T1=16*T/(pi*dr**3)#\n", - "sigc=4*Ps/(pi*dr**2)#\n", - "sigmax=sigc/2+sqrt((sigc/2**2)+(T1**2))#\n", - "Tmax=sqrt((sigc/2**2)+(T1**2))#\n", - "n=tan(alpha)/tan(alpha+phi)#\n", - "Uo=Ps/2#\n", - "Ui=Uo/n#\n", - "wav=pi/2#\n", - "wmax=2*wav#\n", - "I=Ui*2/wmax**2#\n", - "k=0.4#\n", - "Ir=0.9*I*10**-3#\n", - "m=Ir/k**2#\n", - "R=0.4#\n", - "rho=7200#\n", - "a=sqrt(m/(2*pi*R*rho))#\n", - "T=T*10**-3#\n", - "print \" T is %0.3f Nm \"%(T)#\n", - "print \"\\n n is %0.4f \"%(n)#\n", - "print \"\\n a is %0.5f mm \"%(a)#\n", - " \n", - "#The difference in the answers of T is due to rounding-off of values." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " T is 145.242 Nm \n", - "\n", - " n is 0.4751 \n", - "\n", - " a is 0.04894 mm \n" - ] - } - ], - "prompt_number": 8 - } - ], - "metadata": {} - } - ] -}
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