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--- a/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch8.ipynb
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-{
- "cells": [
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "# Chapter 8 Analog Multiplier"
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## Example 8.1 Pg 267"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 1,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "the output voltage of inverting amplifier (V2) is = 3.00 V\n"
-     ]
-    }
-   ],
-   "source": [
-    "from math import sqrt, pi\n",
-    "from __future__ import division\n",
-    "# to determine the output voltage of inverting amplifier (V2)\n",
-    "Vin = 18 # # V\n",
-    "V1 = -6 #  # V\n",
-    "\n",
-    "# in the op-amp due to the infinite i/p resiostance the input current is = 0\n",
-    "# i1+i2 = 0\n",
-    "# it gives relation\n",
-    "Vo = -Vin #\n",
-    "\n",
-    "# the output of multiplier is defined as\n",
-    "#Vo = K*V1*V2\n",
-    "\n",
-    "K = 1 # # we assume\n",
-    "\n",
-    "V2 = (Vo/(K*V1))#\n",
-    "print 'the output voltage of inverting amplifier (V2) is = %0.2f'%(V2),'V'"
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## Example 8.2 Pg 267"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 2,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "the output voltage of multiplier is = 225.00 V\n"
-     ]
-    }
-   ],
-   "source": [
-    "# to determine the output voltage of multiplier\n",
-    "Vin = 15 # # V\n",
-    "\n",
-    "# the output of multiplier is defined as\n",
-    "#Vo = K*V1*V2\n",
-    "# because of i/p terminal the circuit performs mathematical operation squaring\n",
-    "# i.e  V1 = V2 = Vin\n",
-    "K = 1 # # we assume\n",
-    "Vo = K*(Vin)**2#\n",
-    "print 'the output voltage of multiplier is = %0.2f'%(Vo),'V' "
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## Example 8.3 Pg 268"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 3,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "the output voltage of inverting amplifier is = 4.00  V \n",
-      "the output voltage of multiplier is = 16.00  V \n"
-     ]
-    }
-   ],
-   "source": [
-    "from math import sqrt, pi\n",
-    "# to determine the output voltage of multiplier and inverting amplifier\n",
-    "Vin = 16 #\n",
-    "# the output of the inverting amplifier\n",
-    "K =1 #   # we assume\n",
-    "Vos = sqrt(abs(Vin)/K) #\n",
-    "print 'the output voltage of inverting amplifier is = %0.2f'%(Vos),' V '\n",
-    "\n",
-    "# the output of the multiplier\n",
-    "Vo = K*Vos**2 #\n",
-    "print 'the output voltage of multiplier is = %0.2f'%(Vo),' V '"
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## Example 8.5 Pg 269"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 6,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "output voltage of RMS detector is = 10.00 V \n"
-     ]
-    }
-   ],
-   "source": [
-    "# output voltage of of RMS detector\n",
-    "Vin = 10 # \n",
-    "T = 1 #  # we assume that the charging and discharging period of capacitor\n",
-    "\n",
-    "# the output voltage of RMS detector\n",
-    "# Vo =sqrt(1/T*)integrate(Vin**2*(t),t,0,1 [,atol [,rtol]])  #\n",
-    "Vo = 10 #\n",
-    "print 'output voltage of RMS detector is = %0.2f'%(Vo),'V '"
-   ]
-  }
- ],
- "metadata": {
-  "kernelspec": {
-   "display_name": "Python 2",
-   "language": "python",
-   "name": "python2"
-  },
-  "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 2
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython2",
-   "version": "2.7.9"
-  }
- },
- "nbformat": 4,
- "nbformat_minor": 0
-}