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diff --git a/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb b/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb deleted file mode 100755 index d9148952..00000000 --- a/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb +++ /dev/null @@ -1,393 +0,0 @@ -{ - "cells": [ - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Chapter 4 Operational Amplifier" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.1 Pg 79" - ] - }, - { - "cell_type": "code", - "execution_count": 6, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " closed loop gain of an op-amp is = 35.00\n", - " the input impedance Zin = 10.00 kohm \n", - " the output impedance Z0 = 0.020 ohm \n" - ] - } - ], - "source": [ - "from __future__ import division\n", - "# For an op-amp circuit find a) closed loop gain Acl b) input impedance Zin c) output impedance Zo\n", - "ro = 85 # # ohm\n", - "A = 150*10**3 # # ohm\n", - "R2 = 350*10**3 # # ohm # Feedback resistance\n", - "R1 = 10*10**3 # # ohm # Input resistance\n", - "\n", - "# a) closed loop gain\n", - "# ACL = abs(Vo/Vin) = abs(R2/R1)\n", - "ACL = abs(R2/R1) #\n", - "print ' closed loop gain of an op-amp is = %0.2f'%ACL# # 1/beta = ACL\n", - "beta = (1/ACL) #\n", - "\n", - "# b) the input impedance Zin\n", - "Zin = R1 #\n", - "print ' the input impedance Zin = %0.2f'%(Zin/1e3),'kohm '#\n", - "\n", - "# c0 the output impedance Z0\n", - "Z0 = (ro)/(1+(beta*A))#\n", - "print ' the output impedance Z0 = %0.3f'%Z0,' ohm '#" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.2 Pg 80" - ] - }, - { - "cell_type": "code", - "execution_count": 5, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The difference voltage is = 10.00 V \n", - " The open loop gain is = 2.00 \n" - ] - } - ], - "source": [ - "# Determine the differece voltage and open loop gain of an op-amp\n", - "V1 = -5 # # volt # input voltage\n", - "V2 = 5 # # volt\n", - "Vo = 20 # #volt # output voltage\n", - "\n", - "# the difference voltage is given by \n", - "Vd = V2-V1 #\n", - "print ' The difference voltage is = %0.2f'%Vd,' V '\n", - "\n", - "# open loop gain \n", - "A = (Vo/Vd)#\n", - "print ' The open loop gain is = %0.2f'%A,' '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.3 Pg 80" - ] - }, - { - "cell_type": "code", - "execution_count": 7, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The difference voltage is = 5.00 V \n", - " The open loop gain is = 4.00 \n" - ] - } - ], - "source": [ - "# Determine the differece voltage and open loop gain of an op-amp\n", - "V1 = -5 # # volt # input voltage\n", - "V2 = 0 # # volt # GND\n", - "Vo = 20 # #volt # output voltage\n", - "\n", - "# the difference voltage is given by \n", - "Vd = V2-V1 #\n", - "print ' The difference voltage is = %0.2f'%Vd,' V '\n", - "\n", - "# open loop gain \n", - "A = (Vo/Vd)#\n", - "print ' The open loop gain is = %0.2f'%A,' '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.4 Pg 81" - ] - }, - { - "cell_type": "code", - "execution_count": 8, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The difference voltage is = 5.00 V \n", - " The open loop gain is = 4.00 \n" - ] - } - ], - "source": [ - "# Determine the differece voltage and open loop gain of an op-amp\n", - "V1 = 0 # # volt # input voltage # GND\n", - "V2 = 5 # # volt \n", - "Vo = 20 # #volt # output voltage\n", - "\n", - "# the difference voltage is given by \n", - "Vd = V2-V1 #\n", - "print ' The difference voltage is = %0.2f'%Vd,' V '\n", - "\n", - "# open loop gain \n", - "A = (Vo/Vd)#\n", - "print ' The open loop gain is = %0.2f'%A,' '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.5 Pg 81" - ] - }, - { - "cell_type": "code", - "execution_count": 10, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The difference voltage is = -10.00 V \n", - " The open loop gain is = 2.00 \n" - ] - } - ], - "source": [ - "# Determine the differece voltage and open loop gain of an op-amp\n", - "V1 = 5 # # volt # input voltage # GND\n", - "V2 = -5 # # volt \n", - "Vo = -20 # #volt # output voltage\n", - "\n", - "# the difference voltage is given by \n", - "Vd = V2-V1 #\n", - "print ' The difference voltage is = %0.2f'%Vd,' V '\n", - "\n", - "# open loop gain \n", - "A = (Vo/Vd)#\n", - "print ' The open loop gain is = %0.2f'%A,' '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.6 Pg 82" - ] - }, - { - "cell_type": "code", - "execution_count": 7, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "The Closed loop gain of an inverting op-amp is = -2.50 \n", - "The |Ac| Closed loop gain of an inverting op-amp is = 2.50 \n", - "The output voltage of an inverting op-amp is = -25.00 V \n" - ] - } - ], - "source": [ - "from __future__ import division\n", - "# To find closed loop gain and output voltage Vo of an inverting op-amp\n", - "R1 = 10 # #kilo ohm # input resistance\n", - "R2 = 25 # # kilo ohm # feedback resistance\n", - "Vin = 10 # #volt # input voltage\n", - "\n", - "# Closed loop gain of an inverting op-amp\n", - "Ac = -(R2/R1) #\n", - "print 'The Closed loop gain of an inverting op-amp is = %0.2f'%Ac,' '\n", - "Ac = abs(Ac)#\n", - "print 'The |Ac| Closed loop gain of an inverting op-amp is = %0.2f'%Ac,' '\n", - "\n", - "# the output voltage of an inverting op-amp\n", - "Vo = -(R2/R1)*Vin #\n", - "print 'The output voltage of an inverting op-amp is = %0.2f'%Vo,' V '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.7 Pg 82" - ] - }, - { - "cell_type": "code", - "execution_count": 8, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The Closed loop gain of an non-inverting op-amp is = 3.50 \n", - " The output voltage of an non-inverting op-amp is = 35.00 V \n" - ] - } - ], - "source": [ - "# To find closed loop gain and output voltage Vo of an non-inverting op-amp\n", - "R1 = 10 # #kilo ohm # input resistance\n", - "R2 = 25 # # kilo ohm # feedback resistance\n", - "Vin = 10 # #volt # input voltage\n", - "\n", - "# Closed loop gain of an non-inverting op-amp\n", - "Ac = 1+(R2/R1) #\n", - "Ac = abs(Ac)#\n", - "print ' The Closed loop gain of an non-inverting op-amp is = %0.2f'%Ac,' '\n", - "\n", - "# the output voltage of an inverting op-amp\n", - "Vo = (1+R2/R1)*Vin #\n", - "print ' The output voltage of an non-inverting op-amp is = %0.2f'%Vo,' V '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.8 Pg 83" - ] - }, - { - "cell_type": "code", - "execution_count": 9, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - "The closed loop gain of differntial op-amp is = 2.50 \n", - "The output voltage of an non-inverting op-amp is= 50.00 V \n" - ] - } - ], - "source": [ - "# to find out closed loop gain and output voltage Vo\n", - "R1 = 10 # #kilo ohm # input resistance\n", - "R3 = 10 # #kilo ohm # input resistance\n", - "R2 = 25 # # kilo ohm # feedback resistance\n", - "R4 = 25 # # kilo ohm # feedback resistance\n", - "Vin2 = 10 # #volt # input voltage\n", - "Vin1 = -10 # #volt # input voltage\n", - "\n", - "# closed loop gain of differntial op-amp is given by\n", - "Ac = (R2/R1) #\n", - "Ac = abs(Ac)# \n", - "print 'The closed loop gain of differntial op-amp is = %0.2f'%Ac,' '\n", - "\n", - "# the output voltage of an non-inverting op-amp is given by\n", - "Vo = (R2/R1)*(Vin2-Vin1) #\n", - "print 'The output voltage of an non-inverting op-amp is= %0.2f'%Vo,' V '" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "## Example 4.9 Pg 84" - ] - }, - { - "cell_type": "code", - "execution_count": 10, - "metadata": { - "collapsed": false - }, - "outputs": [ - { - "name": "stdout", - "output_type": "stream", - "text": [ - " The upper voltage is = 2.86 V \n", - " The lower voltage is = -2.86 V \n" - ] - } - ], - "source": [ - "# Determine the non-inverting input voltage\n", - "R1 = 10 # #kilo ohm # input resistance\n", - "R2 = 25 # #kilo ohm # feedback resistance\n", - "Voh = 10 # # volt #output voltage\n", - "Vol = -10 # # volt # output voltage\n", - "\n", - "# upper voltage\n", - "V = (R1/(R1+R2)*Voh) #\n", - "print ' The upper voltage is = %0.2f'%V,' V '\n", - "\n", - "# Lower voltage\n", - "V = (R1/(R1+R2)*Vol) #\n", - "print ' The lower voltage is = %0.2f'%V,' V '" - ] - } - ], - "metadata": { - "kernelspec": { - "display_name": "Python 2", - "language": "python", - "name": "python2" - }, - "language_info": { - "codemirror_mode": { - "name": "ipython", - "version": 2 - }, - "file_extension": ".py", - "mimetype": "text/x-python", - "name": "python", - "nbconvert_exporter": "python", - "pygments_lexer": "ipython2", - "version": "2.7.9" - } - }, - "nbformat": 4, - "nbformat_minor": 0 -} |