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diff --git a/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb b/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb new file mode 100644 index 00000000..d9148952 --- /dev/null +++ b/Linear_Integrated_Circuit_by_M._S._Sivakumar/Ch4.ipynb @@ -0,0 +1,393 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 4 Operational Amplifier" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.1 Pg 79" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " closed loop gain of an op-amp is = 35.00\n", + " the input impedance Zin = 10.00 kohm \n", + " the output impedance Z0 = 0.020 ohm \n" + ] + } + ], + "source": [ + "from __future__ import division\n", + "# For an op-amp circuit find a) closed loop gain Acl b) input impedance Zin c) output impedance Zo\n", + "ro = 85 # # ohm\n", + "A = 150*10**3 # # ohm\n", + "R2 = 350*10**3 # # ohm # Feedback resistance\n", + "R1 = 10*10**3 # # ohm # Input resistance\n", + "\n", + "# a) closed loop gain\n", + "# ACL = abs(Vo/Vin) = abs(R2/R1)\n", + "ACL = abs(R2/R1) #\n", + "print ' closed loop gain of an op-amp is = %0.2f'%ACL# # 1/beta = ACL\n", + "beta = (1/ACL) #\n", + "\n", + "# b) the input impedance Zin\n", + "Zin = R1 #\n", + "print ' the input impedance Zin = %0.2f'%(Zin/1e3),'kohm '#\n", + "\n", + "# c0 the output impedance Z0\n", + "Z0 = (ro)/(1+(beta*A))#\n", + "print ' the output impedance Z0 = %0.3f'%Z0,' ohm '#" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.2 Pg 80" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The difference voltage is = 10.00 V \n", + " The open loop gain is = 2.00 \n" + ] + } + ], + "source": [ + "# Determine the differece voltage and open loop gain of an op-amp\n", + "V1 = -5 # # volt # input voltage\n", + "V2 = 5 # # volt\n", + "Vo = 20 # #volt # output voltage\n", + "\n", + "# the difference voltage is given by \n", + "Vd = V2-V1 #\n", + "print ' The difference voltage is = %0.2f'%Vd,' V '\n", + "\n", + "# open loop gain \n", + "A = (Vo/Vd)#\n", + "print ' The open loop gain is = %0.2f'%A,' '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.3 Pg 80" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The difference voltage is = 5.00 V \n", + " The open loop gain is = 4.00 \n" + ] + } + ], + "source": [ + "# Determine the differece voltage and open loop gain of an op-amp\n", + "V1 = -5 # # volt # input voltage\n", + "V2 = 0 # # volt # GND\n", + "Vo = 20 # #volt # output voltage\n", + "\n", + "# the difference voltage is given by \n", + "Vd = V2-V1 #\n", + "print ' The difference voltage is = %0.2f'%Vd,' V '\n", + "\n", + "# open loop gain \n", + "A = (Vo/Vd)#\n", + "print ' The open loop gain is = %0.2f'%A,' '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.4 Pg 81" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The difference voltage is = 5.00 V \n", + " The open loop gain is = 4.00 \n" + ] + } + ], + "source": [ + "# Determine the differece voltage and open loop gain of an op-amp\n", + "V1 = 0 # # volt # input voltage # GND\n", + "V2 = 5 # # volt \n", + "Vo = 20 # #volt # output voltage\n", + "\n", + "# the difference voltage is given by \n", + "Vd = V2-V1 #\n", + "print ' The difference voltage is = %0.2f'%Vd,' V '\n", + "\n", + "# open loop gain \n", + "A = (Vo/Vd)#\n", + "print ' The open loop gain is = %0.2f'%A,' '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.5 Pg 81" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The difference voltage is = -10.00 V \n", + " The open loop gain is = 2.00 \n" + ] + } + ], + "source": [ + "# Determine the differece voltage and open loop gain of an op-amp\n", + "V1 = 5 # # volt # input voltage # GND\n", + "V2 = -5 # # volt \n", + "Vo = -20 # #volt # output voltage\n", + "\n", + "# the difference voltage is given by \n", + "Vd = V2-V1 #\n", + "print ' The difference voltage is = %0.2f'%Vd,' V '\n", + "\n", + "# open loop gain \n", + "A = (Vo/Vd)#\n", + "print ' The open loop gain is = %0.2f'%A,' '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.6 Pg 82" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Closed loop gain of an inverting op-amp is = -2.50 \n", + "The |Ac| Closed loop gain of an inverting op-amp is = 2.50 \n", + "The output voltage of an inverting op-amp is = -25.00 V \n" + ] + } + ], + "source": [ + "from __future__ import division\n", + "# To find closed loop gain and output voltage Vo of an inverting op-amp\n", + "R1 = 10 # #kilo ohm # input resistance\n", + "R2 = 25 # # kilo ohm # feedback resistance\n", + "Vin = 10 # #volt # input voltage\n", + "\n", + "# Closed loop gain of an inverting op-amp\n", + "Ac = -(R2/R1) #\n", + "print 'The Closed loop gain of an inverting op-amp is = %0.2f'%Ac,' '\n", + "Ac = abs(Ac)#\n", + "print 'The |Ac| Closed loop gain of an inverting op-amp is = %0.2f'%Ac,' '\n", + "\n", + "# the output voltage of an inverting op-amp\n", + "Vo = -(R2/R1)*Vin #\n", + "print 'The output voltage of an inverting op-amp is = %0.2f'%Vo,' V '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.7 Pg 82" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The Closed loop gain of an non-inverting op-amp is = 3.50 \n", + " The output voltage of an non-inverting op-amp is = 35.00 V \n" + ] + } + ], + "source": [ + "# To find closed loop gain and output voltage Vo of an non-inverting op-amp\n", + "R1 = 10 # #kilo ohm # input resistance\n", + "R2 = 25 # # kilo ohm # feedback resistance\n", + "Vin = 10 # #volt # input voltage\n", + "\n", + "# Closed loop gain of an non-inverting op-amp\n", + "Ac = 1+(R2/R1) #\n", + "Ac = abs(Ac)#\n", + "print ' The Closed loop gain of an non-inverting op-amp is = %0.2f'%Ac,' '\n", + "\n", + "# the output voltage of an inverting op-amp\n", + "Vo = (1+R2/R1)*Vin #\n", + "print ' The output voltage of an non-inverting op-amp is = %0.2f'%Vo,' V '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.8 Pg 83" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The closed loop gain of differntial op-amp is = 2.50 \n", + "The output voltage of an non-inverting op-amp is= 50.00 V \n" + ] + } + ], + "source": [ + "# to find out closed loop gain and output voltage Vo\n", + "R1 = 10 # #kilo ohm # input resistance\n", + "R3 = 10 # #kilo ohm # input resistance\n", + "R2 = 25 # # kilo ohm # feedback resistance\n", + "R4 = 25 # # kilo ohm # feedback resistance\n", + "Vin2 = 10 # #volt # input voltage\n", + "Vin1 = -10 # #volt # input voltage\n", + "\n", + "# closed loop gain of differntial op-amp is given by\n", + "Ac = (R2/R1) #\n", + "Ac = abs(Ac)# \n", + "print 'The closed loop gain of differntial op-amp is = %0.2f'%Ac,' '\n", + "\n", + "# the output voltage of an non-inverting op-amp is given by\n", + "Vo = (R2/R1)*(Vin2-Vin1) #\n", + "print 'The output voltage of an non-inverting op-amp is= %0.2f'%Vo,' V '" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 4.9 Pg 84" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + " The upper voltage is = 2.86 V \n", + " The lower voltage is = -2.86 V \n" + ] + } + ], + "source": [ + "# Determine the non-inverting input voltage\n", + "R1 = 10 # #kilo ohm # input resistance\n", + "R2 = 25 # #kilo ohm # feedback resistance\n", + "Voh = 10 # # volt #output voltage\n", + "Vol = -10 # # volt # output voltage\n", + "\n", + "# upper voltage\n", + "V = (R1/(R1+R2)*Voh) #\n", + "print ' The upper voltage is = %0.2f'%V,' V '\n", + "\n", + "# Lower voltage\n", + "V = (R1/(R1+R2)*Vol) #\n", + "print ' The lower voltage is = %0.2f'%V,' V '" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.9" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |