summaryrefslogtreecommitdiff
path: root/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb
diff options
context:
space:
mode:
Diffstat (limited to 'Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb')
-rw-r--r--Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb185
1 files changed, 19 insertions, 166 deletions
diff --git a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb
index ba64d857..cda3a92c 100644
--- a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb
+++ b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb
@@ -18,7 +18,7 @@
},
{
"cell_type": "code",
- "execution_count": 2,
+ "execution_count": 1,
"metadata": {
"collapsed": false
},
@@ -119,31 +119,7 @@
"print\"Check for Ti(in °C)\"\n",
"Ti=T4-(Q*Ri)\n",
"print\"The value is same as given in the problem\"\n",
- "print\"Ti=\",Ti\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- " \n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Ti=\",Ti"
]
},
{
@@ -171,10 +147,6 @@
}
],
"source": [
- " \n",
- "\n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 2\"\n",
@@ -194,7 +166,7 @@
"#Q=(Ti-To)/((Lb/kb)+(L/ki)) so L=ki*(((Ti-To)/Q)-(Lb/kb))\n",
"print\"The thickness of insulating material L=ki*(((Ti-To)/Q)-(Lb/kb)) in m\"\n",
"L=ki*(((Ti-To)/Q)-(Lb/kb))\n",
- "print\"L=\",L\n"
+ "print\"L=\",L"
]
},
{
@@ -206,7 +178,7 @@
},
{
"cell_type": "code",
- "execution_count": 1,
+ "execution_count": 3,
"metadata": {
"collapsed": false
},
@@ -235,7 +207,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 4\"\n",
@@ -281,17 +252,7 @@
"print\"q2=\",q2\n",
"print\"Heat flux qo=q1+q2 in W/m**2 \"\n",
"qo=q1+q2\n",
- "print\"qo=\",qo\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"qo=\",qo"
]
},
{
@@ -329,7 +290,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 6\"\n",
@@ -372,9 +332,7 @@
"X=(2*10**3)-(4*10**5*x);\n",
"Q=-k*X/10**6\n",
"#A check for the above results can be made from an energy balance of the plate as |(q/A)|@x=0+|(q/A)|@x=0.02=qG*0.02\n",
- "print\"Q=\",Q\n",
- "\n",
- "\n"
+ "print\"Q=\",Q"
]
},
{
@@ -386,7 +344,7 @@
},
{
"cell_type": "code",
- "execution_count": 2,
+ "execution_count": 16,
"metadata": {
"collapsed": false
},
@@ -410,7 +368,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 9\"\n",
@@ -458,16 +415,7 @@
"Q=(T1-Tinf)/(((X)/(2*math.pi*L*k))+(1/(h*2*math.pi*r2*L)))\n",
"#It is important to note that Q increases by 5.2% when the insulation thickness increases from 0.002m to critical thickness. \n",
"#Addition of insulation beyond the critical thickness decreases the value of Q (The heat loss).\n",
- "print\"Q=\",Q\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Q=\",Q"
]
},
{
@@ -479,7 +427,7 @@
},
{
"cell_type": "code",
- "execution_count": 3,
+ "execution_count": 8,
"metadata": {
"collapsed": false
},
@@ -495,7 +443,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 10\"\n",
@@ -525,22 +472,7 @@
"#Therefore the thickness of insulation is given by t=r3-Do\n",
"print\"the thickness of insulation in metre is\"\n",
"t=r3-Do\n",
- "print\"t=\",t\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"t=\",t"
]
},
{
@@ -552,7 +484,7 @@
},
{
"cell_type": "code",
- "execution_count": 4,
+ "execution_count": 9,
"metadata": {
"collapsed": false
},
@@ -570,7 +502,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 11\"\n",
@@ -591,21 +522,7 @@
"print\"The temprature of wire at the centre in K is \"\n",
"To=Tw+((qG*ro**2)/(4*k))\n",
"#Note:The answer in the book is incorrect(value of D has been put instead of ro)\n",
- "print\"To=\",To\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"To=\",To"
]
},
{
@@ -655,10 +572,6 @@
}
],
"source": [
- "\n",
- " \n",
- " \n",
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 12\"\n",
@@ -730,12 +643,7 @@
"#the amount of ice in kG which melts during a 24 hour period is (mice)\n",
"print\"Therefore,the amount of ice(mice)in kG which melts during a 24 hour period is\"\n",
"mice=Qt/deltahf\n",
- "print\"mice=\",mice\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"mice=\",mice"
]
},
{
@@ -747,7 +655,7 @@
},
{
"cell_type": "code",
- "execution_count": 5,
+ "execution_count": 13,
"metadata": {
"collapsed": false
},
@@ -782,7 +690,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 13\"\n",
@@ -846,15 +753,7 @@
"Qinf=(h*P*k*A)**0.5*thetab\n",
"print\"We see that since k is large there is significant difference between the finite length and the infinte length cases\"\n",
"print\"However when the length of the rod approaches 1m,the result become almost same.\" \n",
- "print\"Qinf=\",Qinf\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Qinf=\",Qinf"
]
},
{
@@ -866,7 +765,7 @@
},
{
"cell_type": "code",
- "execution_count": 6,
+ "execution_count": 14,
"metadata": {
"collapsed": false
},
@@ -882,7 +781,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 14\"\n",
@@ -899,41 +797,7 @@
"#The thermal conductivity of Rod B iskB\n",
"print\"The thermal conductivity of Rod B kB in W/(m*K) is \"\n",
"kB=kA*(xB/xA)**2\n",
- "print\"kB=\",kB\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"kB=\",kB"
]
},
{
@@ -945,7 +809,7 @@
},
{
"cell_type": "code",
- "execution_count": 7,
+ "execution_count": 15,
"metadata": {
"collapsed": false
},
@@ -971,7 +835,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 2, Example 15\"\n",
@@ -1013,17 +876,7 @@
"#Heat loss from the plate is Qb\n",
"print\"Heat loss from the plate at 400K in W is\"\n",
"Qb=(N*(h*P*kal*A)**0.5*thetab*((math.cosh(m*L)-(thetaL/thetab))/(math.sinh(m*L))))+(((l*b)-(N*A))*h*thetab)+(l*b*h*thetab)\n",
- "print\"Qb=\",Qb\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Qb=\",Qb"
]
}
],
generated by cgit (git 2.34.1) at 2024-12-21 14:23:25 +0000