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diff --git a/Introduction_to_Electric_Drives_by_J._S._Katre/chapter1.ipynb b/Introduction_to_Electric_Drives_by_J._S._Katre/chapter1.ipynb new file mode 100755 index 00000000..07476ab0 --- /dev/null +++ b/Introduction_to_Electric_Drives_by_J._S._Katre/chapter1.ipynb @@ -0,0 +1,249 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:1ede18939970cf3dcd5883a4a0c1fb987d10a2324079f20686384266546536c0" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter1, Thyristors" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1.11.1 : page 1-29 " + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "#peak reverse recovery current\n", + "#given data :\n", + "itt=10 # time in micro seconds\n", + "qtt=150 #charge in micro colums\n", + "prrc=((2*qtt)/itt) #peak reverse recovery current in amperes\n", + "print \"Peak reverse recovery current = %0.f A\" %prrc" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Peak reverse recovery current = 30 A\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Examples 1.18.1: page 1-44" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from math import pi, sqrt, cos\n", + "#voltage of the capacitor\n", + "r=10 #in ohms\n", + "l=10 #/inductance in mH\n", + "c=10 #capacitance in micro farads\n", + "v=100 #in volts\n", + "t=((pi)/(sqrt((1/(l*10**-3*c*10**-6))-(r**2/(4*(l*10**-3)**2))))) # time in seconds\n", + "vc= v*(1-cos(t/(sqrt(l*10**-3*c*10**-6))*pi/180)) #in volts\n", + "print \"The capacitor voltage = %0.2f V\" %vc\n", + "#answer is wrong in the textbook" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The capacitor voltage = 0.15 V\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1.18.2: page 1-45" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from math import pi, sqrt, cos\n", + "#voltage of the capacitor\n", + "r=15 #in ohms\n", + "l=12 #/inductance in mH\n", + "c=8 #capacitance in micro farads\n", + "v=100 #in volts\n", + "t=((pi)/(sqrt((1/(l*10**-3*c*10**-6))-(r**2/(4*(l*10**-3)**2))))) # time in seconds\n", + "vc= v*(1-cos(t/(sqrt(l*10**-3*c*10**-6))*pi/180)) #in volts\n", + "print \"The capacitor voltage = %0.2f V\" %vc\n", + "#this question is not solved in the textbook" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The capacitor voltage = 0.16 V\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1.20.1: page 1-52" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "#Turn Off Time\n", + "#given data :\n", + "Vs=200 #in volts\n", + "R1=10 # in ohm\n", + "R2=R1 \n", + "C=5 # in micro-farad\n", + "Tc=(R1*C)/1.44 \n", + "print \"The Circuit Turn Off Time, Tc = %0.2f micro-sec\" %Tc" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The Circuit Turn Off Time, Tc = 34.72 micro-sec\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1.20.2: page 1-52" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "#Peak Current and turn off time\n", + "#given data :\n", + "Vs=200 #in volts\n", + "R1=10 # in ohm\n", + "R2=R1 \n", + "Vc=200 #in volts\n", + "C=10 # in micro-farad\n", + "I1=Vs/R1 \n", + "I2=(Vs+Vc)/R2 \n", + "It1=I1+I2 \n", + "print \"Peak Current, It1 = %0.2f A \" %It1\n", + "Tc=(R1*C)/1.44 \n", + "print \"The Circuit Turn Off Time, Tc = %0.2f micro-sec \" %Tc" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Peak Current, It1 = 60.00 A \n", + "The Circuit Turn Off Time, Tc = 69.44 micro-sec \n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1.21.1: page 1-59" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from math import pi\n", + "#L and C\n", + "#given data :\n", + "V=100 # in volts\n", + "Irm=40 # in A\n", + "tq=40 # in micro-sec\n", + "Del_t=(50/100)*tq # in micro-sec\n", + "C=(Irm*(tq+Del_t))/V \n", + "print \"Capacitance, C = %0.f micro-farad \" %C\n", + "L_min=(V/Irm)**2*C \n", + "print \"Minimum inductance, L_min = %0.f micro-Henry\" %L_min\n", + "T=2.5 # assume one cycle period in ms\n", + "L_max=((0.01*(T*10**-3)**2)/(pi**2*C*10**-6))*10**6 \n", + "print \"Maximum inductance, L_max = %0.2f micro-Henry \" %L_max" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Capacitance, C = 24 micro-farad \n", + "Minimum inductance, L_min = 150 micro-Henry\n", + "Maximum inductance, L_max = 263.86 micro-Henry \n" + ] + } + ], + "prompt_number": 6 + } + ], + "metadata": {} + } + ] +}
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