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diff --git a/Internal_Combustion_Engines_by_H._B._Keswani/ch14.ipynb b/Internal_Combustion_Engines_by_H._B._Keswani/ch14.ipynb new file mode 100755 index 00000000..e35ea36d --- /dev/null +++ b/Internal_Combustion_Engines_by_H._B._Keswani/ch14.ipynb @@ -0,0 +1,120 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:ba05265a254158c2105561a6062dfe30873e9384b5393c6f2ca64b6f28ed143f" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 14 : The Diesel Engine" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.1 Page no : 258" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\t\t\t\n", + "#Input data\n", + "r = 14.3\t\t\t\t\t#Compression ratio\n", + "c = 5\t\t\t\t\t#Fuel cutoff in percent of stroke\n", + "w = 0.006\t\t\t\t\t#Weight of charge in kg\n", + "T4 = 912\t\t\t\t\t#Final temperature in degree C abs\n", + "q = 8300\t\t\t\t\t#Heat in kcal\n", + "x = [0.258,0.000048]\t\t\t\t\t#Temperature expression is 0.258T+0.000048T**2, where T is in degree C abs\n", + "\n", + "\t\t\t\t\t\n", + "#Calculations\n", + "v4 = 1. #Assuming clearance volume as unity\n", + "v1 = 1.665\t\t\t\t\t#v1 from fig. 14.2 on page no. 352\n", + "T1 = (T4*v1)/v4\t\t\t\t\t#Temperature in degree C abs\n", + "qp1 = (x[0]*T1+x[1]*T1**2)\t\t\t\t\t#constant pressure heat of mixture at temperature T1 in kcal/kg\n", + "qp4 = (x[0]*T4+x[1]*T4**2)\t\t\t\t\t#constant pressure heat of mixture at temperature T4 in kcal/kg\n", + "qre = (qp1-qp4)\t\t\t\t\t#Heat required by the mixture in kcal/kg\n", + "wf = (w*qre)/q\t\t\t\t\t#Weight of oil in kg\n", + "\n", + "\t\t\t\t\t\n", + "#Output\n", + "print 'The weight of oil that must be injected is %3.6f kg'%(wf)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The weight of oil that must be injected is 0.000164 kg\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.2 Page no : 261" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\t\t\t\n", + "#Input data\n", + "r = 14\t\t\t\t\t#Compression ratio\n", + "p = 1.2\t\t\t\t\t#Induction pipe pressure in kg/cm**2\n", + "bp = 0.65\t\t\t\t\t#Exhaust back pressure in kg/cm**2\n", + "Tc = 87+273\t\t\t\t\t#Charge temperature in K\n", + "Te = 850+273\t\t\t\t\t#Exhaust temperature in K\n", + "T1 = 111+273\t\t\t\t\t#Temperature at the beginning of compression in K\n", + "g = 1.2\t\t\t\t\t#Ratio of specific heats\n", + "\n", + "\t\t\t\t\t\n", + "#Calculations\n", + "Cw1 = ((bp*10**4)/Te)\t\t\t\t\t#specific heat in kJ/kg.K\n", + "Cw2 = ((p*10**4*(r-1))/Tc)\t\t\t\t\t#specific heat in kJ/kg.K\n", + "T3 = ((g*Te*Cw1+Cw2*Tc)/(Cw1*g+Cw2))\t\t\t\t\t#Temperature in K\n", + "t3 = T3-273\t\t\t\t\t#Temperature in degree C\n", + "rw = (Cw1/Cw2)\t\t\t\t\t#Ratio of specific heats\n", + "\n", + "\t\t\t\t\t\n", + "#Output\n", + "print 'The ratio of the mass residuals to fresh charge is %3.4f'%(rw)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The ratio of the mass residuals to fresh charge is 0.0134\n" + ] + } + ], + "prompt_number": 3 + } + ], + "metadata": {} + } + ] +}
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