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diff --git a/Integrated_Circuits_by_Dr._Sanjay_Sharma/Ch_08.ipynb b/Integrated_Circuits_by_Dr._Sanjay_Sharma/Ch_08.ipynb new file mode 100644 index 00000000..65492a55 --- /dev/null +++ b/Integrated_Circuits_by_Dr._Sanjay_Sharma/Ch_08.ipynb @@ -0,0 +1,212 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter : 8 - CMOS Realization Of Inverters" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 8.2 : Page No - 333\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from sympy import symbols, solve, N\n", + "x= symbols('x')\n", + "#Given data\n", + "NMH= 1 # in V\n", + "VIH= 2 # in V\n", + "VTon= 0.5 # in V\n", + "VOL= 0.2 # in V\n", + "VDD= 3 # in V\n", + "KP= 30*10**-6 # in A/V**2\n", + "PD= 100*10**-6 # power dissipation in W\n", + "# Formula VIH= VTon +2*sqrt(2*VDD/(3*kn*RL))-1/(kn*RL) (i)\n", + "# Let x= 1/(kn*RL), putting the values in (i), we get\n", + "# x**2-5*x+2.25=0\n", + "expr = x**2-5*x+2.25\n", + "x , x1= solve(expr, x)\n", + "# Formula PD= VDD*(VDD-VOL)/(2*RL)\n", + "RL= VDD*(VDD-VOL)/(2*PD) # in \u03a9\n", + "print \"The value of RL = %0.1e \u03a9\" %RL\n", + "kn= 1/(x*RL) # in A/V**2\n", + "# Formula kn= KP*(W/L)\n", + "WbyL= kn/KP \n", + "print \"The value of (W/L)n = %0.2f\" %WbyL" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of RL = 4.2e+04 \u03a9\n", + "The value of (W/L)n = 1.59\n" + ] + } + ], + "prompt_number": 83 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 8.4 : Page No - 335\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Given data\n", + "unCox= 40 # in \u00b5A/V**2\n", + "upCox= 20 # in \u00b5A/V**2\n", + "Ln= 0.5 # in \u00b5m\n", + "Lp= 0.5 # in \u00b5m\n", + "Wn= 2.0 # in \u00b5m\n", + "Wp= unCox*Wn/upCox # in \u00b5m\n", + "print \"The value of Wp = %0.f \u00b5m\" %Wp" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of Wp = 4 \u00b5m\n" + ] + } + ], + "prompt_number": 84 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 8.5 : Page No - 337\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from sympy import symbols, solve, N\n", + "VOUT= symbols('VOUT')\n", + "# Given data\n", + "VTO= 0.43 # in V\n", + "VDD= 2.5 # in V\n", + "g=0.4 # value of gamma\n", + "W1= 0.375 \n", + "L1=0.25 \n", + "W2= 0.75 \n", + "L2=0.25 \n", + "#VDD-VOUT-VT= VDD-VOUT-(VTO+g*(sqrt(0.6+VOUT)-sqrt(0.6)))=0\n", + "#VOUT**2+VOUT*(2*A-g**2)+(A-0.6*g**2)=0, where\n", + "A=VTO-VDD-g*sqrt(0.6) # assumed\n", + "B= (2*A-g**2) # assumed\n", + "C=(A**2-0.6*g**2) #assumed\n", + " #VOUT= [1 B C] \n", + " #VOUT= roots(VOUT) # in V\n", + " #VOUT= VOUT(2) # in V\n", + "\n", + "\n", + "expr = VOUT**2+VOUT*(2*A-g**2+4.556)+(A-0.6*g**2)\n", + "VOUT= solve(expr, VOUT)\n", + "VOH= round(VOUT[1],4) # in V\n", + "print \"The value of VOH = %0.3f volts\" %VOH\n", + "Vout=(W1+3*L2)-(VDD-VTO)*(W2*L1/(W1*L2)-1)+ (VDD)/(VDD-VTO)\n", + "VOL= Vout # in V\n", + "print \"The value of VOL = %0.3f volts\" %VOL\n", + "Vth= (VDD+VTO-L1)/(VDD*VTO)*(1-W1*L2/(W2*L1))+(L1*L2/VDD)\n", + "print \"The value of Vth for circuit A = %0.3f volts\" %Vth\n", + "W4= 0.365 \n", + "L4=0.25 \n", + "W3= 0.75 \n", + "L3=0.15 \n", + "Vth=(L3*L4/VDD)+(VDD/(W3*L4*VDD))-(VDD)/(1-W4*L3/(W3*L4))-2*W4\n", + "print \"The value of Vth for circuit B = %0.3f volts\" %Vth\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of VOH = 1.766 volts\n", + "The value of VOL = 0.263 volts\n", + "The value of Vth for circuit A = 1.272 volts\n", + "The value of Vth for circuit B = 1.087 volts\n" + ] + } + ], + "prompt_number": 85 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 8.6 : Page No - 338\n" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "from sympy import symbols, solve, N\n", + "Vx= symbols('Vx')\n", + "\n", + "#Given data\n", + "VTO= 0.43 # in V\n", + "VDD= 2.5 # in V\n", + "g=0.5 # value of gamma\n", + "#VDD-Vx-VT= VDD-Vx-(VTO+g*(sqrt(0.6+Vx)-sqrt(0.6)))=0\n", + "#Vx**2+Vx*(2*A-g**2)+(A-0.6*g**2)=0, where\n", + "A=VTO-VDD-g*sqrt(0.6) # assumed\n", + "B= (2*A-g**2) # assumed\n", + "C=(A**2-0.6*g**2) #assumed\n", + "expr = Vx**2+Vx*(2*A-g**2+5)+(A-0.6*g**2)\n", + "err, Vx= solve(expr , Vx)\n", + "print \"The value of Vx =\",round(Vx,4),\"volts\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of Vx = 1.6991 volts\n" + ] + } + ], + "prompt_number": 86 + } + ], + "metadata": {} + } + ] +}
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