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+{
+ "metadata": {
+ "name": "Chapter_6"
+ },
+ "nbformat": 2,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h1>Chapter 6: Level<h1>"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.1,Page Number:370<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''output current of two wire pressure transmitter'''",
+ "",
+ "#(a)",
+ "",
+ "# variable declaration",
+ "p=1.5 # pressure applied",
+ "a=4.0 # mA corresponds to 0 kg/cm^2",
+ "b=20.0 # mA corresponds to 2 kg/cm^2",
+ "",
+ "#calculation",
+ "wh=(((b-a)/2)*p)+a",
+ "",
+ "#result",
+ "print('(a)just at the bottom level of the tank')",
+ "print('Water head applied to the transmitter =%d mA'%wh)",
+ "",
+ "#(b)",
+ "",
+ "#calculation",
+ "wh2=(((b-a)/2)*p)+2*a",
+ "",
+ "#result",
+ "print('\\n\\n(b)5m below the bottom of the tank')",
+ "print('Water head applied to the transmitter =%d mA' %wh2)",
+ "",
+ "#(c)",
+ "",
+ "#calculation",
+ "wh3=(((b-a)/2)*p)",
+ "",
+ "#result",
+ "print('\\n\\n(c)5m above the bottom of the tank')",
+ "print('Water head applied to the transmitter =%d mA'%wh3)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)just at the bottom level of the tank",
+ "Water head applied to the transmitter =16 mA",
+ "",
+ "",
+ "(b)5m below the bottom of the tank",
+ "Water head applied to the transmitter =20 mA",
+ "",
+ "",
+ "(c)5m above the bottom of the tank",
+ "Water head applied to the transmitter =12 mA"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.2, Page Number:371<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''water level and current at different positions'''",
+ "",
+ "#(a)",
+ "",
+ "#variable declaration",
+ "b=20.0 # Maximum output",
+ "a=4.0 # minimum output ",
+ "op=16.0 # output in mA",
+ "",
+ "#calculation",
+ "p=(op-a)*2/(b-a)",
+ "p_h=p*10.0",
+ "h=p_h-2-5",
+ "",
+ "#result",
+ "print('(a)\\nh = %dm'%h)",
+ "",
+ "#(b)",
+ "",
+ "#variable declaration",
+ "p1=1 # pressure applied",
+ "",
+ "#calculation",
+ "t_op=((b-a)/2)*p1+4",
+ "",
+ "#result",
+ "print('\\n(b)\\nTransmitter output =%d mA'%t_op)",
+ "",
+ "#(c)",
+ "",
+ "#variable declaration",
+ "p2=0.5 # applied pressure",
+ "",
+ "#calculation",
+ "t_op1=((b-a)/2)*p2+4",
+ "",
+ "#result",
+ "print('\\n(c)\\nTransmitter output =%d mA'%t_op1)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)",
+ "h = 8m",
+ "",
+ "(b)",
+ "Transmitter output =12 mA",
+ "",
+ "(c)",
+ "Transmitter output =8 mA"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.3, Page Number: 372<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Differential pressure output at different levels'''",
+ "",
+ "#(a)",
+ "",
+ "#variable declaration",
+ "b=20.0 # Maximum output",
+ "a=4.0 # minimum output",
+ "op=16.0 # actual output ",
+ "wt_l1=25.0 # water level (i)",
+ "",
+ "#calculation",
+ "t_op=((b-a)/100)*(100-75)+4",
+ "",
+ "#result",
+ "print('(a)\\nWater level=+25cm\\nTransmitter output = %d mA' %t_op)",
+ "",
+ "#(b)",
+ "",
+ "#calculation",
+ "wt_l2=-25.0 # water level (ii)",
+ "t_op2=((b-a)/100)*(100-25)+4",
+ "",
+ "#result",
+ "print('\\n(b)\\nWater level=-25cm\\nTransmitter output = %d mA' %t_op2)",
+ "",
+ "#(c)",
+ "",
+ "#Variable declaration",
+ "t_op3=12.0 # Transmitter output ",
+ "",
+ "#calculation",
+ "H=(100.0/(b-a))*(12-4) ",
+ "",
+ "#result",
+ "print('\\n(c)\\nHead Applied = %d cm\\nLevel corresponding to 50 cm head =0 cm' %H)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)",
+ "Water level=+25cm",
+ "Transmitter output = 8 mA",
+ "",
+ "(b)",
+ "Water level=-25cm",
+ "Transmitter output = 16 mA",
+ "",
+ "(c)",
+ "Head Applied = 50 cm",
+ "Level corresponding to 50 cm head =0 cm"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.4, Page Number: 373<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Displacer with spring balance'''",
+ "",
+ "#(a)",
+ "",
+ "#variable declaration",
+ "a=5.0*10**-4 #area",
+ "l=8.0 #length",
+ "dens=6.0*1000.0 #density",
+ "",
+ "#calculation",
+ "w=a*l*dens",
+ "",
+ "#result",
+ "print('(a)\\nWeight of the displacer if weighed in air = %d kg'%w)",
+ "",
+ "",
+ "#(i)",
+ "",
+ "#variable declaration",
+ "sbr1=23.0 # spring balance reading",
+ "",
+ "#calculation",
+ "wloss1=w-sbr1",
+ "L1=wloss1/(1000.0*a)",
+ "",
+ "#result",
+ "print('\\n(i)\\tL1=%dm'%L1)",
+ "",
+ "",
+ "#(ii)",
+ "",
+ "#variable declaration",
+ "sbr2=22.0 # spring balance reading",
+ "",
+ "#calculation",
+ "wloss2=w-sbr2",
+ "L2=wloss2/(1000.0*a)",
+ "",
+ "#result",
+ "print('\\n(ii)\\tL2=%dm'%L2)",
+ "",
+ "#(iii)",
+ "",
+ "#variable declaration",
+ "sbr3=21.0 # spring balance reading",
+ "",
+ "#calculation",
+ "wloss3=w-sbr3",
+ "L3=wloss3/(1000.0*a)",
+ "",
+ "#result",
+ "print('\\n(iii)\\tL3=%dm'%L3)",
+ "",
+ "#(b)",
+ "",
+ "#variable declaration",
+ "level=8.0 # level wen tank is full ",
+ "",
+ "#calculation",
+ "wt=a*level*1000.0",
+ "spring=w-wt",
+ "",
+ "#result",
+ "print('\\n(b):when the tank is full\\nSpring Balance reading = %d kg'%spring)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)",
+ "Weight of the displacer if weighed in air = 24 kg",
+ "",
+ "(i)\tL1=2m",
+ "",
+ "(ii)\tL2=4m",
+ "",
+ "(iii)\tL3=6m",
+ "",
+ "(b):when the tank is full",
+ "Spring Balance reading = 20 kg"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.5, Page Number: 374<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Buoyancy Force calculation'''",
+ "",
+ "#variable declaration",
+ "rho=1000.0 # density of water ",
+ "v=3.0 # displaced volume of water ",
+ "",
+ "#calculation",
+ "Bw=rho*v",
+ "",
+ "#Result",
+ "print('Buoyance Force(Bw) = %d kg'%Bw)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Buoyance Force(Bw) = 3000 kg"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.6, Page Number: 374<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Determination of displaced volume from Buoyancy Force'''",
+ "",
+ "#variable declaration",
+ "rho=1000.0 # density of water",
+ "Bw=5000.0 # Buoyancy Force",
+ "",
+ "#calculation",
+ "v=Bw/rho",
+ "",
+ "#result",
+ "print('V = %d m^3' %v)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "V = 5 m^3"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.7, Page Number: 374<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Determination of hydrostatic pressure in open tank'''",
+ "",
+ "#variable declaration",
+ "rho=1000.0 # density of water",
+ "h=10.0 # height of liquid",
+ "",
+ "#calculation",
+ "P=rho*h",
+ "",
+ "#result",
+ "print('P = %d kg/m^2 = %d kg/cm^2 '%(P,P/10000))"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "P = 10000 kg/m^2 = 1 kg/cm^2 "
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.8, Page Number: 374<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Determination of hydrostatic pressure in closed tank'''",
+ "",
+ "#variable declaration",
+ "rho=1000.0 # density of water",
+ "h=15.0 # height of liquid ",
+ "ex_p=1.0 # External pressure on liquid",
+ "",
+ "#calculation",
+ "P=(rho*h/10000.0)+ex_p",
+ "",
+ "#result",
+ "print('P = %.1f kg/cm^2' %P)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "P = 2.5 kg/cm^2"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.9, Page Number:374<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''Determination of height from hydrostatic pressure'''",
+ "",
+ "#variable declaration",
+ "rho=1000.0 # density of water",
+ "ex_p=0.5*10**4 # External pressure on liquid ",
+ "P=1.6*10**4 #(rho*h/10000)+ex_p",
+ "",
+ "#calculation",
+ "h=(P-ex_p)/1000.0",
+ "",
+ "#result",
+ "print('h = %d m' %h)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "h = 11 m"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "markdown",
+ "source": [
+ "<h3>Example 6.10, Page Number:375<h3>"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "'''calculation of level on the probe'''",
+ "",
+ "#variable declaration",
+ "c2=100.0*10**-6 # capacitance in capacitance probe",
+ "r1=10.0*10**3 # value of resistor in bride",
+ "r2=100.0*10**3 # value of resistor in bride",
+ "r3=50.0*10**3 # value of resistor in bride",
+ "",
+ "#calculation",
+ "Cx=r1*c2/r3",
+ "Cx=Cx*10**6",
+ "",
+ "#result",
+ "print('Cx = %d microFarad'%Cx)",
+ "c=5.0",
+ "",
+ "#calculation",
+ "l=Cx/c",
+ "",
+ "#result",
+ "print('\\nLevel on the probe = %dm'%l)"
+ ],
+ "language": "python",
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Cx = 20 microFarad",
+ "",
+ "Level on the probe = 4m"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ }
+ ]
+ }
+ ]
+} \ No newline at end of file
generated by cgit (git 2.34.1) at 2024-12-20 11:49:57 +0000