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+{
+ "metadata": {
+  "name": "Chapter_6"
+ }, 
+ "nbformat": 2, 
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h1>Chapter 6: Level<h1>"
+     ]
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.1,Page Number:370<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''output current of two wire pressure transmitter'''", 
+      "", 
+      "#(a)", 
+      "", 
+      "# variable declaration", 
+      "p=1.5                      # pressure applied", 
+      "a=4.0                      # mA corresponds to 0 kg/cm^2", 
+      "b=20.0                     # mA corresponds to 2 kg/cm^2", 
+      "", 
+      "#calculation", 
+      "wh=(((b-a)/2)*p)+a", 
+      "", 
+      "#result", 
+      "print('(a)just at the bottom level of the tank')", 
+      "print('Water head applied to the transmitter =%d mA'%wh)", 
+      "", 
+      "#(b)", 
+      "", 
+      "#calculation", 
+      "wh2=(((b-a)/2)*p)+2*a", 
+      "", 
+      "#result", 
+      "print('\\n\\n(b)5m below the bottom of the tank')", 
+      "print('Water head applied to the transmitter =%d mA' %wh2)", 
+      "", 
+      "#(c)", 
+      "", 
+      "#calculation", 
+      "wh3=(((b-a)/2)*p)", 
+      "", 
+      "#result", 
+      "print('\\n\\n(c)5m above the bottom of the tank')", 
+      "print('Water head applied to the transmitter =%d mA'%wh3)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "(a)just at the bottom level of the tank", 
+        "Water head applied to the transmitter =16 mA", 
+        "", 
+        "", 
+        "(b)5m below the bottom of the tank", 
+        "Water head applied to the transmitter =20 mA", 
+        "", 
+        "", 
+        "(c)5m above the bottom of the tank", 
+        "Water head applied to the transmitter =12 mA"
+       ]
+      }
+     ], 
+     "prompt_number": 1
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.2, Page Number:371<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''water level and current at different positions'''", 
+      "", 
+      "#(a)", 
+      "", 
+      "#variable declaration", 
+      "b=20.0             # Maximum output", 
+      "a=4.0              # minimum output ", 
+      "op=16.0            # output in mA", 
+      "", 
+      "#calculation", 
+      "p=(op-a)*2/(b-a)", 
+      "p_h=p*10.0", 
+      "h=p_h-2-5", 
+      "", 
+      "#result", 
+      "print('(a)\\nh = %dm'%h)", 
+      "", 
+      "#(b)", 
+      "", 
+      "#variable declaration", 
+      "p1=1                # pressure applied", 
+      "", 
+      "#calculation", 
+      "t_op=((b-a)/2)*p1+4", 
+      "", 
+      "#result", 
+      "print('\\n(b)\\nTransmitter output =%d mA'%t_op)", 
+      "", 
+      "#(c)", 
+      "", 
+      "#variable declaration", 
+      "p2=0.5                    # applied pressure", 
+      "", 
+      "#calculation", 
+      "t_op1=((b-a)/2)*p2+4", 
+      "", 
+      "#result", 
+      "print('\\n(c)\\nTransmitter output =%d mA'%t_op1)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "(a)", 
+        "h = 8m", 
+        "", 
+        "(b)", 
+        "Transmitter output =12 mA", 
+        "", 
+        "(c)", 
+        "Transmitter output =8 mA"
+       ]
+      }
+     ], 
+     "prompt_number": 2
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.3, Page Number: 372<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Differential pressure output at different levels'''", 
+      "", 
+      "#(a)", 
+      "", 
+      "#variable declaration", 
+      "b=20.0                  # Maximum output", 
+      "a=4.0                   # minimum output", 
+      "op=16.0                 # actual output   ", 
+      "wt_l1=25.0              # water level (i)", 
+      "", 
+      "#calculation", 
+      "t_op=((b-a)/100)*(100-75)+4", 
+      "", 
+      "#result", 
+      "print('(a)\\nWater level=+25cm\\nTransmitter output = %d mA' %t_op)", 
+      "", 
+      "#(b)", 
+      "", 
+      "#calculation", 
+      "wt_l2=-25.0            # water level (ii)", 
+      "t_op2=((b-a)/100)*(100-25)+4", 
+      "", 
+      "#result", 
+      "print('\\n(b)\\nWater level=-25cm\\nTransmitter output = %d mA' %t_op2)", 
+      "", 
+      "#(c)", 
+      "", 
+      "#Variable declaration", 
+      "t_op3=12.0             # Transmitter output ", 
+      "", 
+      "#calculation", 
+      "H=(100.0/(b-a))*(12-4) ", 
+      "", 
+      "#result", 
+      "print('\\n(c)\\nHead Applied = %d cm\\nLevel corresponding to 50 cm head =0 cm' %H)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "(a)", 
+        "Water level=+25cm", 
+        "Transmitter output = 8 mA", 
+        "", 
+        "(b)", 
+        "Water level=-25cm", 
+        "Transmitter output = 16 mA", 
+        "", 
+        "(c)", 
+        "Head Applied = 50 cm", 
+        "Level corresponding to 50 cm head =0 cm"
+       ]
+      }
+     ], 
+     "prompt_number": 3
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.4, Page Number: 373<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Displacer with spring balance'''", 
+      "", 
+      "#(a)", 
+      "", 
+      "#variable declaration", 
+      "a=5.0*10**-4                  #area", 
+      "l=8.0                         #length", 
+      "dens=6.0*1000.0               #density", 
+      "", 
+      "#calculation", 
+      "w=a*l*dens", 
+      "", 
+      "#result", 
+      "print('(a)\\nWeight of the displacer if weighed in air = %d kg'%w)", 
+      "", 
+      "", 
+      "#(i)", 
+      "", 
+      "#variable declaration", 
+      "sbr1=23.0                   # spring balance reading", 
+      "", 
+      "#calculation", 
+      "wloss1=w-sbr1", 
+      "L1=wloss1/(1000.0*a)", 
+      "", 
+      "#result", 
+      "print('\\n(i)\\tL1=%dm'%L1)", 
+      "", 
+      "", 
+      "#(ii)", 
+      "", 
+      "#variable declaration", 
+      "sbr2=22.0                  # spring balance reading", 
+      "", 
+      "#calculation", 
+      "wloss2=w-sbr2", 
+      "L2=wloss2/(1000.0*a)", 
+      "", 
+      "#result", 
+      "print('\\n(ii)\\tL2=%dm'%L2)", 
+      "", 
+      "#(iii)", 
+      "", 
+      "#variable declaration", 
+      "sbr3=21.0                # spring balance reading", 
+      "", 
+      "#calculation", 
+      "wloss3=w-sbr3", 
+      "L3=wloss3/(1000.0*a)", 
+      "", 
+      "#result", 
+      "print('\\n(iii)\\tL3=%dm'%L3)", 
+      "", 
+      "#(b)", 
+      "", 
+      "#variable declaration", 
+      "level=8.0                # level wen tank is full     ", 
+      "", 
+      "#calculation", 
+      "wt=a*level*1000.0", 
+      "spring=w-wt", 
+      "", 
+      "#result", 
+      "print('\\n(b):when the tank is full\\nSpring Balance reading = %d kg'%spring)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "(a)", 
+        "Weight of the displacer if weighed in air = 24 kg", 
+        "", 
+        "(i)\tL1=2m", 
+        "", 
+        "(ii)\tL2=4m", 
+        "", 
+        "(iii)\tL3=6m", 
+        "", 
+        "(b):when the tank is full", 
+        "Spring Balance reading = 20 kg"
+       ]
+      }
+     ], 
+     "prompt_number": 4
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.5, Page Number: 374<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Buoyancy Force calculation'''", 
+      "", 
+      "#variable declaration", 
+      "rho=1000.0                # density of water ", 
+      "v=3.0                     # displaced volume of water ", 
+      "", 
+      "#calculation", 
+      "Bw=rho*v", 
+      "", 
+      "#Result", 
+      "print('Buoyance Force(Bw) = %d kg'%Bw)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "Buoyance Force(Bw) = 3000 kg"
+       ]
+      }
+     ], 
+     "prompt_number": 5
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.6, Page Number: 374<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Determination of displaced volume from Buoyancy Force'''", 
+      "", 
+      "#variable declaration", 
+      "rho=1000.0             # density of water", 
+      "Bw=5000.0              # Buoyancy  Force", 
+      "", 
+      "#calculation", 
+      "v=Bw/rho", 
+      "", 
+      "#result", 
+      "print('V = %d m^3' %v)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "V = 5 m^3"
+       ]
+      }
+     ], 
+     "prompt_number": 6
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.7, Page Number: 374<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Determination of hydrostatic pressure in open tank'''", 
+      "", 
+      "#variable declaration", 
+      "rho=1000.0           # density of water", 
+      "h=10.0               # height of liquid", 
+      "", 
+      "#calculation", 
+      "P=rho*h", 
+      "", 
+      "#result", 
+      "print('P = %d kg/m^2 = %d kg/cm^2 '%(P,P/10000))"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "P = 10000 kg/m^2 = 1 kg/cm^2 "
+       ]
+      }
+     ], 
+     "prompt_number": 7
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.8, Page Number: 374<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Determination of hydrostatic pressure in closed tank'''", 
+      "", 
+      "#variable declaration", 
+      "rho=1000.0               # density of water", 
+      "h=15.0                   # height of liquid ", 
+      "ex_p=1.0                 # External pressure on liquid", 
+      "", 
+      "#calculation", 
+      "P=(rho*h/10000.0)+ex_p", 
+      "", 
+      "#result", 
+      "print('P = %.1f kg/cm^2' %P)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "P = 2.5 kg/cm^2"
+       ]
+      }
+     ], 
+     "prompt_number": 8
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.9, Page Number:374<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''Determination of height from hydrostatic pressure'''", 
+      "", 
+      "#variable declaration", 
+      "rho=1000.0               # density of water", 
+      "ex_p=0.5*10**4           # External pressure on liquid     ", 
+      "P=1.6*10**4              #(rho*h/10000)+ex_p", 
+      "", 
+      "#calculation", 
+      "h=(P-ex_p)/1000.0", 
+      "", 
+      "#result", 
+      "print('h = %d m' %h)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "h = 11 m"
+       ]
+      }
+     ], 
+     "prompt_number": 9
+    }, 
+    {
+     "cell_type": "markdown", 
+     "source": [
+      "<h3>Example 6.10, Page Number:375<h3>"
+     ]
+    }, 
+    {
+     "cell_type": "code", 
+     "collapsed": false, 
+     "input": [
+      "'''calculation of level on the probe'''", 
+      "", 
+      "#variable declaration", 
+      "c2=100.0*10**-6          # capacitance in capacitance probe", 
+      "r1=10.0*10**3            # value of resistor in bride", 
+      "r2=100.0*10**3           # value of resistor in bride", 
+      "r3=50.0*10**3            # value of resistor in bride", 
+      "", 
+      "#calculation", 
+      "Cx=r1*c2/r3", 
+      "Cx=Cx*10**6", 
+      "", 
+      "#result", 
+      "print('Cx = %d microFarad'%Cx)", 
+      "c=5.0", 
+      "", 
+      "#calculation", 
+      "l=Cx/c", 
+      "", 
+      "#result", 
+      "print('\\nLevel on the probe = %dm'%l)"
+     ], 
+     "language": "python", 
+     "outputs": [
+      {
+       "output_type": "stream", 
+       "stream": "stdout", 
+       "text": [
+        "Cx = 20 microFarad", 
+        "", 
+        "Level on the probe = 4m"
+       ]
+      }
+     ], 
+     "prompt_number": 10
+    }
+   ]
+  }
+ ]
+}
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