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diff --git a/Hydraulics_Made_Easy_by_R._S._Dighe/ch4.ipynb b/Hydraulics_Made_Easy_by_R._S._Dighe/ch4.ipynb new file mode 100755 index 00000000..0747f48b --- /dev/null +++ b/Hydraulics_Made_Easy_by_R._S._Dighe/ch4.ipynb @@ -0,0 +1,994 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:98b9b2cc3c2bb837908ed50b11e73842e607c874a3e8f477bc1209f33ea8918d" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 4 : Flow of Water Through Orifices and Mouthpieces" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.1 Page No : 98" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "M = 31*10 \t\t#lbs\n", + "P = 3.6 \t\t#lbs\n", + "t = 60. \t\t#sec\n", + "g = 32.2 \t\t#ft/sec**2\n", + "H = 9. \t\t#ft\n", + "d = 1. \t\t#in\n", + "w = 6.24 \t\t#gallons\n", + "\t\t\n", + "#CALCULATIONS\n", + "v = P*g*t/M\n", + "V = math.sqrt(2*g*H)\n", + "Cv = v/V\n", + "V1 = math.pi*(d/12)**2*V*60*w/4\n", + "Cd = M/(10*V1)\n", + "Cc = Cd/Cv\n", + "Cr = (1/Cv**2)-1\n", + "\t\t\n", + "#RESULTS\n", + "print 'Coefficient of resistance = %.2f '%(Cr)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Coefficient of resistance = 0.15 \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.2 Page No : 100" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "M = 1.65 \t\t#lbs\n", + "Q = 31. \t\t#gallons per min\n", + "d = 1. \t\t#in\n", + "h = 4. \t\t#ft\n", + "t = 60. \t\t#sec\n", + "g = 32.2 \t\t#ft/sec**2\n", + "Q1 = 6.24 \t\t#gallons per min\n", + "c = 0.36\n", + "P = 3.6 # lbs\n", + "H = 9. \n", + "\n", + "#CALCULATIONS\n", + "v = P*g*t/(Q*10)\n", + "V = math.sqrt(2*g*H)\n", + "Cv = (v/V)\n", + "vf = V*math.pi*(d/12)**2*60*Q1/4\n", + "Cd = Q/vf\n", + "Cc = Cd/Cv\n", + "Cr = (1/Cv**2)-1\n", + "\n", + "#RESULTS\n", + "print 'velocity of jet = %.2f ft/sec'%(v)\n", + "print 'theoretical velocity of jet = %.2f ft/sec'%(V)\n", + "print 'Cv = %.2f '%(Cv)\n", + "print 'volume flow = %.2f gallons per minute'%(vf)\n", + "print 'Cd = %.2f '%(Cd)\n", + "print 'Cc = %.2f '%(Cc)\n", + "print 'Coefficient of resistance = %.2f '%(Cr)\n", + "\n", + "# Note : Answer for theoretical velocity is wrong in book. Please check." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "velocity of jet = 22.44 ft/sec\n", + "theoretical velocity of jet = 24.07 ft/sec\n", + "Cv = 0.93 \n", + "volume flow = 49.16 gallons per minute\n", + "Cd = 0.63 \n", + "Cc = 0.68 \n", + "Coefficient of resistance = 0.15 \n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.3 Page No : 101" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "x = 11.5 \t\t#in\n", + "y = 1.2 \t\t#in\n", + "H = 29. \t\t#in\n", + "q = 6.24 \t\t#gallons per minute\n", + "d = 1. \t\t#in\n", + "g = 32.2 \t\t#ft/sec**2\n", + "Q = 16. \t\t#gallons per min\n", + "\t\t\n", + "#CALCULATIONS\n", + "Cv = math.sqrt(x**2/(4*H*y))\n", + "Q1 = math.pi*(d/12)**2*math.sqrt(2*g*H/12)*q*60/4\n", + "Cd = Q/Q1\n", + "Cc = Cd/Cv\n", + "Cr = (1/Cv**2)-1\n", + "\t\t\n", + "#RESULTS\n", + "print 'Coefficient of resistance = %.2f '%(Cr)\n", + "\n", + "# rounding off error." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Coefficient of resistance = 0.05 \n" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.4 Page No : 102" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "x = 3.2 \t\t#ft\n", + "d = 8. \t\t#ft\n", + "W = 5.12 \t\t#lb\n", + "A = 1./144\n", + "H = 4. \t\t#ft\n", + "g = 32.2 \t\t#ft/sec**2\n", + "Q = 251.5 \t\t#lbs/min\n", + "w = 62.4 \t\t#lbs/ft**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "F = W*x/d\n", + "v = W*x*g*60/(d*Q)\n", + "V = math.sqrt(2*g*H)\n", + "Cv = v/V\n", + "Q1 = A*V*60*w\n", + "Cd = Q/Q1\n", + "Cc = Cd/Cv\n", + "\t\t\n", + "#RESULTS\n", + "print 'Cc = %.2f '%(Cc)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Cc = 0.61 \n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.5 Page No : 106" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "d = 8. \t\t#in\n", + "\t\t\n", + "#CALCULATIONS\n", + "Cd = 1/math.sqrt(1+((1./(8.**2/100)))-1)\n", + "area = math.pi/4 * (2./12)**2\n", + "Discharge = area * Cd * math.sqrt(2*32.2*4) \t\t\n", + "\n", + "#RESULTS\n", + "print 'Cd = %.2f '%(Cd)\n", + "print \"Discharge = %.1f cubic ft./sec.\"%Discharge\n", + "\n", + "# note : rounding off error. please check." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Cd = 0.80 \n", + "Discharge = 0.3 cubic ft./sec.\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.6 Page No : 109" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "d =2. \t\t#in\n", + "h = 6. \t \t#ft\n", + "H = 26. \t\t#ft\n", + "g = 32.2 \t\t#ft/sec**2\n", + "R = 6.\n", + "\t\t\n", + "#CALCULATIONS\n", + "v2 = math.sqrt(2*g*(H+h))\n", + "Q = math.pi*(d/12)**2*v2/4\n", + "v3 = math.sqrt(2*g*h)\n", + "r = v2/v3\n", + "d3 = math.sqrt(r*d**2)\n", + "v4 = math.sqrt(v2**2/R)\n", + "d4 = math.sqrt(d**2*(v2/v4))\n", + "\t\t\n", + "#RESULTS\n", + "print 'diameter = %.2f in'%(d4)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "diameter = 3.13 in\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.7 Page No : 111" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "r = 9./16\n", + "r1 = 7./16\n", + "h = 26. \t\t#ft\n", + "\t\t\n", + "#CALCULATIONS\n", + "r2 = 1/((r**2)+(0.25*r1**2))\n", + "H1 = h/(r2-1)\n", + "\t\t\n", + "#RESULTS\n", + "print 'maximu head of the tank = %.3f ft of water'%(H1)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "maximu head of the tank = 14.897 ft of water\n" + ] + } + ], + "prompt_number": 17 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.8 pageno : 114" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# variables\n", + "A = 30.*15 # sq ft\n", + "a = 2. # sq ft\n", + "H1 = 5. # ft\n", + "H2 = 0. \n", + "\n", + "# calculation\n", + "T = a*A*H1**(1./2)/(.62*a*8.02)\n", + "\n", + "# result\n", + "print \"Time of emptying pool : T = %.1f seconds\"%T\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time of emptying pool : T = 202.4 seconds\n" + ] + } + ], + "prompt_number": 21 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.9 Page No : 115" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "H1 = 9. \t\t#ft\n", + "A = 2. \t\t#ft**2\n", + "H2 = 4. \t\t#ft\n", + "d = 2.25 \t\t#in\n", + "t = 60. \t\t#sec\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "a = (d/12)**2\n", + "Cd = (2*A*(H1-H2)**0.5)/(t*a*math.sqrt(2*g))\n", + "\t\t\n", + "#RESULTS\n", + "print 'coefficient of dicharge = %.3f '%(Cd)\n", + "\n", + "\n", + "#ANSWER GIVEN IN THE TEXTBBOK IS WRONG..VERIFIED WITH CALCULATOR\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "coefficient of dicharge = 0.528 \n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.10 Page No : 115" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "d = 1. \t\t#ft\n", + "h1 = 10. \t\t#ft\n", + "h2 = 2. \t\t#ft\n", + "Cd = 0.6\n", + "g = 32.2 \t\t#ft/sec**2\n", + "t = 12.6\n", + "\t\t\n", + "#CALCULATIONS\n", + "A = math.pi*d**2/4\n", + "a = 1./144\n", + "T1 = (A/(a*Cd*math.sqrt(2*g)))*(1./3)*(h1**1.5-(h1-h2)**1.5-h2**1.5)+t\n", + "T2 = 2*A*(h2**0.5)/(Cd*a*math.sqrt(2*g))\n", + "T = T1+T2\n", + "\t\t\n", + "#RESULTS\n", + "print 'Total time = %.2f sec'%(T)\n", + "\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Total time = 127.32 sec\n" + ] + } + ], + "prompt_number": 10 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.11 Page No : 117" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "from scipy.integrate import quad\n", + "\n", + "#initialisation of variables\n", + "l = 600. \t\t#ft\n", + "w = 400. \t\t#ft\n", + "s = 1.\n", + "h = 20. \t\t#ft\n", + "d = 3. \t \t#ft\n", + "dh = 10. \t\t#ft\n", + "Cd = 0.7\n", + "g = 32.2 \t\t#ft/sec**2\n", + "k = 240000.\n", + "k1 = 2000.\n", + "k2 = 4.\n", + "\t\t\n", + "#CALCULATIONS\n", + "def f(x):\n", + " return (k/math.sqrt(x) + k1*math.sqrt(x) + k2*x**(3./2))\n", + "\n", + "T1 = 1./(Cd * math.pi/4 * 9 * 8.02) * quad(f,10,20)[0]\n", + "\t\t\n", + "#RESULTS\n", + "print 'Time taken for 10 feet fall = %.f sec'%(T1)\n", + "\n", + "# note : quad() gives accurate answer. so answer is slightly different." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time taken for 10 feet fall = 17846 sec\n" + ] + } + ], + "prompt_number": 31 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.12 Page No : 118" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "Cd = 0.6\n", + "H1 = 8. \t\t#ft\n", + "H2 = 3. \t\t#ft\n", + "l = 90. \t\t#ft\n", + "b = 30. \t\t#ft\n", + "g = 32.2 \t\t#ft/sec**2\n", + "A = 2. \t\t#ft**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "T1 = 2*l*b*(H1**0.5-(H1-H2)**0.5)/(Cd*math.sqrt(2*g)*A)\n", + "T2 = (l*b*2/10)*(2./3)*(H1-H2)**1.5/(Cd*math.sqrt(2*g)*A)\n", + "T = T1+T2\n", + "\t\t\n", + "#RESULTS\n", + "print 'Time it take to emptify the swimming bath = %.1f sec'%(T)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time it take to emptify the swimming bath = 750.1 sec\n" + ] + } + ], + "prompt_number": 32 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.13 Page No : 120" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "Cd = 0.8\n", + "g = 32.2 \t\t#f/sec**2\n", + "d = 3. \t\t#in\n", + "x = 6. \t \t#ft\n", + "l = 25. \t\t#ft\n", + "d1 = 8. \t\t#ft\n", + "\t\t\n", + "#CALCULATIONS\n", + "A = math.pi*(d/12)**2/4\n", + "T = (2*l/(Cd*A*math.sqrt(2*g)))*(-2./3)*((d1-x)**1.5-d1**1.5)\n", + "\t\t\n", + "#RESULTS\n", + "print 'Time it take to emptify the boiler = %.f sec'%(T+6)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time it take to emptify the boiler = 2100 sec\n" + ] + } + ], + "prompt_number": 13 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.14 Page No : 125" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "l = 30. \t\t#ft\n", + "w = 10. \t\t#ft\n", + "d = 4. \t\t#in\n", + "h1 = 10. \t\t#ft\n", + "h2 = 2. \t\t#ft\n", + "Cd = 0.97\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "A1 = w*3*l/4\n", + "A2 = l*w/4\n", + "A = math.pi*(d/12)**2/4\n", + "T = 2*A1*(math.sqrt(h1)-math.sqrt(h2))*10/(Cd*A*math.sqrt(2*g)*(l+w))\n", + "\t\t\n", + "#RESULTS\n", + "print 'Time it take to reduce the height = %.f sec'%(round(T,-1))\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time it take to reduce the height = 290 sec\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.15 Page No : 125" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "A1 = 1000. \t\t#ft**2\n", + "A2 = 1000. \t\t#ft**2\n", + "a = 2. \t\t#ft**2\n", + "H1 = 9. \t\t#ft\n", + "H2 = 4. \t\t#ft\n", + "Cd =0.8\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "T = a*1000*(math.sqrt(H1)-math.sqrt(H2))/(Cd*a**2*math.sqrt(2*g))\n", + "\t\t\n", + "#RESULTS\n", + "print 'Time it take to reduce the height = %.1f sec'%(T)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time it take to reduce the height = 77.9 sec\n" + ] + } + ], + "prompt_number": 35 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.16 Page No : 128" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "l = 70. \t\t#ft\n", + "b = 10. \t\t#ft\n", + "Hl = 10. \t\t#ft\n", + "H1 = 6. \t\t#ft\n", + "h1 = 4. \t\t#ft\n", + "h2 = 2. \t\t#ft\n", + "w = 2. \t\t#ft\n", + "h3 = 3. \t\t#ft\n", + "Cd = 0.6\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "t = (l*b)*(Hl+H1)/(Cd*h2*w*h1*math.sqrt(2*g*H1))\n", + "t1 = 2*l*b*math.sqrt(Hl)/(Cd*h2*w*h3*math.sqrt(2*g))\n", + "\t\t\n", + "#RESULTS\n", + "# 2nd ans is wrong in book\n", + "print 'Time of filling = %.2f sec'%(t)\n", + "print ' Time of emptying = %.2f sec'%(t1)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Time of filling = 59.35 sec\n", + " Time of emptying = 76.62 sec\n" + ] + } + ], + "prompt_number": 16 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.17 Page No : 129" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "from sympy import Symbol,solve\n", + "\t\t\n", + "#initialisation of variables\n", + "HL = 12.5 \t\t#ft\n", + "H1 = 10.5 \t\t#ft\n", + "Cd = 0.62\n", + "h = 4. \t\t#ft\n", + "l = 3. \t \t#ft\n", + "n = 2.\n", + "t = 5. \t\t #min\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "a1 = n*l*l\n", + "A = Symbol('A')\n", + "ans = solve( (2*A/(Cd*a1*26)) + 2*A*math.sqrt(H1)/(Cd*a1*8.02) - 300 )\n", + "A = ans[0]\n", + "\n", + "#RESULTS\n", + "print 'Area = %.f sq ft'%(A)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Area = 3783 sq ft\n" + ] + } + ], + "prompt_number": 41 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.18 Page No : 130" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "Cd = 0.62\n", + "g = 32.2 \t\t#ft/sec**2\n", + "l = 200. \t\t#ft\n", + "w = 25. \t\t#ft\n", + "a1 = 5. \t\t#ft**2\n", + "h = 20. \t\t#ft\n", + "\t\t\n", + "#CALCULATIONS\n", + "t = 2*l*w*math.sqrt(h-(h/a1))/(Cd*math.sqrt(2*g)*a1)\n", + "\t\t\n", + "#RESULTS\n", + "print 'tme rquired to fill the lock = %.f sec'%(t)\n", + "\n", + "# rounding off error" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "tme rquired to fill the lock = 1608 sec\n" + ] + } + ], + "prompt_number": 42 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.19 Page No : 130" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "L = 150. \t\t#ft\n", + "w = 20. \t\t#ft\n", + "t = 5. \t\t#min\n", + "h = 5. \t \t#ft\n", + "Cd = 0.6 \n", + "Hl = 9. \t\t#ft\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "T = 2*L*w*math.sqrt(Hl)/(Cd*t*60*math.sqrt(2*g))\n", + "\t\t\n", + "#RESULTS\n", + "print 'Area of sumberged slice = %.1f sq ft'%(T)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Area of sumberged slice = 12.5 sq ft\n" + ] + } + ], + "prompt_number": 19 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.20 Page No : 132" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "L = 3. \t\t#ft\n", + "H1 = 1.5 \t\t#ft\n", + "H2 = 0.75 \t\t#ft\n", + "Cd = 0.62\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "Q = 2*Cd*60*L*math.sqrt(2*g)*(H1**1.5-H2**1.5)/3\n", + "\t\t\n", + "#RESULTS\n", + "print 'Discharge per minute = %.1f cubic ft per minute'%(Q)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Discharge per minute = 709.1 cubic ft per minute\n" + ] + } + ], + "prompt_number": 20 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4.21 Page No : 134" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "\t\t\n", + "#initialisation of variables\n", + "Cd = 0.62\n", + "H1 = 6. \t\t#ft\n", + "H2 = 3. \t\t#ft\n", + "H = 4. \t\t#ft\n", + "g = 32.2 \t\t#ft/sec**2\n", + "\t\t\n", + "#CALCULATIONS\n", + "Q1 = 2*Cd*H*math.sqrt(2*g)*(H**1.5-H2**1.5)/3\n", + "Q2 = Cd*H*(H1-H)*math.sqrt(2*g*H)\n", + "Q = Q1+Q2\n", + "\t\t\n", + "#RESULTS\n", + "print 'Total discharge = %.f cuses'%(Q)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Total discharge = 117 cuses\n" + ] + } + ], + "prompt_number": 21 + } + ], + "metadata": {} + } + ] +}
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