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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter - I : Introduction to powers of 10"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_9 Page No.  9"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 24,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The addition of 170*10**3 and 23*10**4 =4.00E+05\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Add 170*10**3 and 23*10**4. Express the final answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 170*10**3#       # Variable 1\n",
+    "B = 23*10**4#        # Variable 2\n",
+    "\n",
+    "C = A+B#\n",
+    "print 'The addition of 170*10**3 and 23*10**4 =%0.2E'%C"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_10 Page No.  9"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 25,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The substraction of 250*10**3 and 1.5*10**6 =1.25E+06\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Substract 250*10**3 and 1.5*10**6. Express the final answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 1.5*10**6#       # Variable 1\n",
+    "B = 250*10**3#       # Variable 2\n",
+    "\n",
+    "C = A-B#\n",
+    "print 'The substraction of 250*10**3 and 1.5*10**6 =%0.2E'%C"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_11 Page No.  10"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 26,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The multiplication of 3*10**6 by 150*10**2 =4.50E+10\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Multiply 3*10**6 by 150*10**2. Express the final answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 3*10**6#         # Variable 1\n",
+    "B = 150*10**2#       # Variable 2\n",
+    "\n",
+    "C = A*B#\n",
+    "print 'The multiplication of 3*10**6 by 150*10**2 =%0.2E'%C"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_12 Page No.  10"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 27,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The division of 5.0*10**7 by 2.0*10**4 =2.50E+03\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Divide 5.0*10**7 by 2.0*10**4. Express the final answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 5.0*10**7#       # Variable 1\n",
+    "B = 2.0*10**4#       # Variable 2\n",
+    "\n",
+    "C = A/B#\n",
+    "print 'The division of 5.0*10**7 by 2.0*10**4 =%0.2E'%C"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_13 Page No.  10"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 28,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The reciprocal of 10**5 =1.00e-05\n",
+      "i.e 10**-5\n",
+      "The reciprocal of 10-3 = 1.00e+03\n",
+      "i.e 10**3\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Find the reciprocals for the following powers of 10: (a) 10**5 (b) 10**-3.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 10**5#       # Variable 1\n",
+    "B = 10**-3#      # Variable 2\n",
+    "\n",
+    "C = 1./A#\n",
+    "print 'The reciprocal of 10**5 =%0.2e'%C\n",
+    "print 'i.e 10**-5'\n",
+    "\n",
+    "D = 1./B#\n",
+    "print 'The reciprocal of 10-3 = %0.2e'%D\n",
+    "print 'i.e 10**3'"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_14 Page No.  11"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 29,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The square of 3.0*10**4 =9.00E+08\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Square 3.0*10**4. Express the answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 3.0*10**4#       # Variable 1\n",
+    "\n",
+    "B = A*A#\n",
+    "print 'The square of 3.0*10**4 =%0.2E'%B"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_15 Page No.  11"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 30,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The squareroot of 4*10**6 = 2.00E+03\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import sqrt\n",
+    "# Find the squareroot of 4*10**6. Express the answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 4*10**6#       # Variable 1\n",
+    "\n",
+    "B = sqrt(A)#\n",
+    "print 'The squareroot of 4*10**6 = %0.2E'%B"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_16 Page No.  12"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 31,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The squareroot of 90*10**5 =3.00E+03\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import sqrt\n",
+    "# Find the squareroot of 90*10**5. Express the answer in scientific notation.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 90*10**5#       # Variable 1\n",
+    "\n",
+    "B = sqrt(A)#\n",
+    "print 'The squareroot of 90*10**5 =%0.2E'% B"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. I_17 Page No.  12"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 32,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The multiplication of 40*10**-3 by 5*10**6 =200000.00\n",
+      "i.e 200.000*10**03 OR 200E03\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Show the keystrokes for multiplying 40*10**-3 by 5*10**6.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "A = 40*10**-3#       # Variable 1\n",
+    "B = 5*10**6#         # Variable 2\n",
+    "\n",
+    "C = A*B#\n",
+    "print 'The multiplication of 40*10**-3 by 5*10**6 =%0.2f'%C\n",
+    "print 'i.e 200.000*10**03 OR 200E03'"
+   ]
+  }
+ ],
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+  "kernelspec": {
+   "display_name": "Python 2",
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+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
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+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
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+}