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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 18 : Capacitive Circuits"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. 18_1 Page No. 545"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Zt = 50.00 Ohms\n",
+      "I = 2.00 Ampers\n",
+      "Voltage Across Resistor = 60 Volts\n",
+      "Voltage Across Capacitive Reactance = 80.00 Volts\n",
+      "Theta z =-53.13 degree\n",
+      "Sum of Voltage Drop is Equal to Applied Voltage of 100V = 100.00 Volts\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import sqrt,pi,atan\n",
+    "# If a R=30ohms and Xc=40ohms are in series with 100V applied, find the following: Zt, I, Vr, Vc and Theta z. What is the phase angle between Vc and Vr with respect to I? Prove that the sum of the series voltage drop equals the applied voltage Vt\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "R = 30.#     # Resistance=30 Ohms\n",
+    "Xc = 40.#    # Capacitive Reactance=40 Ohms\n",
+    "Vt = 100.#   # Applied Voltage=100 Volts\n",
+    "\n",
+    "R1 = R*R#\n",
+    "Xc1 = Xc*Xc#\n",
+    "\n",
+    "Zt = sqrt(R1+Xc1)#\n",
+    "print 'Zt = %0.2f Ohms'%Zt\n",
+    "\n",
+    "I = (Vt/Zt)#\n",
+    "print  'I = %0.2f Ampers'%I\n",
+    "\n",
+    "Vr = I*R#\n",
+    "print  'Voltage Across Resistor = %02.f Volts'%Vr\n",
+    "\n",
+    "Vc = I*Xc#\n",
+    "print  'Voltage Across Capacitive Reactance = %0.2f Volts'%Vc\n",
+    "\n",
+    "Oz = atan(-(Xc/R))*180/pi\n",
+    "print  'Theta z =%0.2f degree'%Oz\n",
+    "\n",
+    "#Prove that the sum of the series voltage drop equals the applied voltage Vt\n",
+    "\n",
+    "Vt = sqrt((Vr*Vr)+(Vc*Vc))#\n",
+    "print  'Sum of Voltage Drop is Equal to Applied Voltage of 100V = %0.2f Volts'%Vt"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example No. 18_2 Page No.  548"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The Total Current = 0.05 Amps\n",
+      "i.e 50 mAmps\n",
+      "The Equivqlent Impedence = 1440.00 Ohms\n",
+      "i.e 1.44 kohms\n",
+      "The Value of Theta I = 53.13 degrees\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import sqrt,pi,atan\n",
+    "# A 30-mA Ir is in parallel with another branch current of 40 mA for Ic. The applied voltage Va is 72 V. Calculate It, Zeq and Theta \u0002I.\n",
+    "\n",
+    "# Given data\n",
+    "\n",
+    "Ir = 30.*10**-3#  # Current Ir=30 mA\n",
+    "Ic = 40.*10**-3#  # Current Ic=40 mA\n",
+    "Va = 72.#        # Applied Voltage=72 Volts\n",
+    "\n",
+    "A = Ir*Ir#\n",
+    "B = Ic*Ic#\n",
+    "\n",
+    "It = sqrt(A+B)#\n",
+    "print 'The Total Current = %0.2f Amps'%It\n",
+    "print 'i.e 50 mAmps'\n",
+    "\n",
+    "Zeq = Va/It#\n",
+    "print 'The Equivqlent Impedence = %0.2f Ohms'%Zeq\n",
+    "print 'i.e 1.44 kohms'\n",
+    "\n",
+    "Oi = atan(Ic/Ir)*180/pi\n",
+    "print 'The Value of Theta I = %0.2f degrees'%Oi"
+   ]
+  }
+ ],
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+}