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diff --git a/Grobs_Basic_Electronics_by_M_E_Schultz/Chapter16.ipynb b/Grobs_Basic_Electronics_by_M_E_Schultz/Chapter16.ipynb new file mode 100755 index 00000000..94af71c5 --- /dev/null +++ b/Grobs_Basic_Electronics_by_M_E_Schultz/Chapter16.ipynb @@ -0,0 +1,285 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 16 : Capacitance" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_1 Page No. 492" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Charge Stored = 1.00e-04 Columb\n", + "i.e 100*10**-6 Columbs\n" + ] + } + ], + "source": [ + "# How much charge is stored in a 2 uF capacitor connected across a 50-V supply?\n", + "\n", + "# Given data\n", + "\n", + "V = 50# # Voltage=50 Volts\n", + "C = 2*10**-6# # Capacitor=2 uFarad\n", + "\n", + "Q = C*V#\n", + "print 'The Charge Stored = %0.2e Coulomb'%Q\n", + "print 'i.e 100*10**-6 Coulombs'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_2 Page No. 492" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Charge Stored = 2.00e-03 Columb\n", + "i.e 2000*10**-6 Columbs\n" + ] + } + ], + "source": [ + "# How much charge is stored in a 40 uF capacitor connected across a 50-V supply?\n", + "\n", + "# Given data\n", + "\n", + "V = 50# # Voltage=50 Volts\n", + "C = 40*10**-6# # Capacitor=2 uFarad\n", + "\n", + "Q = C*V#\n", + "print 'The Charge Stored = %0.2e Coulomb'%Q\n", + "print 'i.e 2000*10**-6 Coulombs'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_3 Page No. 493" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Charge Stored = 4.00e-05 Columb\n", + "i.e 40*10**-6 Columbs OR 40 uColumb\n" + ] + } + ], + "source": [ + "# A constant current of 2 uA charges a capacitor for 20 s. How much charge is stored? Remember I=Q/t or Q=I*t.\n", + "\n", + "# Given data\n", + "\n", + "I = 2*10**-6# # Current=2 uAmps\n", + "t = 20# # Time=20 Sec\n", + "\n", + "Q = I*t\n", + "print 'The Charge Stored = %0.2e Coulomb'%Q\n", + "print 'i.e 40*10**-6 Coulombs OR 40 uCoulomb'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_4 Page No. 494" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Capacitance = 2.00e-06 Farad\n", + "i.e 2 uF\n" + ] + } + ], + "source": [ + "# The voltage across the charged capacitor is 20 V. Calculate C.\n", + "\n", + "#Given data\n", + "\n", + "V = 20# # Voltage=20 Volts\n", + "Q = 40*10**-6# # Charge=40 uCoulomb\n", + "\n", + "C = Q/V\n", + "print 'The Capacitance = %0.2e Farad'%C\n", + "print 'i.e 2 uF'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_5 Page No. 495" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Voltage across Capacitor = 500.00 Volts\n" + ] + } + ], + "source": [ + "# A constant current of 5 mA charges a 10 uF capacitor for 1 s. How much is the voltage across the capacitor?\n", + "\n", + "# Given data\n", + "\n", + "I = 5*10**-3# # Current=5 mAmps\n", + "t = 1# # Time=1 Sec\n", + "C = 10*10**-6# # Cap=10 uFarad\n", + "\n", + "Q = I*t#\n", + "\n", + "V = Q/C#\n", + "print 'The Voltage across Capacitor = %0.2f Volts'%V" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_6 Page No. 496" + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Capacitance = 1.77e-09 Farad\n", + "i.e 1700*10**-12 F OR 1770 pF\n" + ] + } + ], + "source": [ + "# Calculate C for two plates, each with an area 2 sqm, separated by 1 cm with a dielectric of air.\n", + "\n", + "# Given data\n", + "\n", + "c = 8.85*10**-12# # Constant=8.85 p\n", + "A = 2# # Area=2 sqm\n", + "d = 1*10**-2# # Distance=1 cm\n", + "K = 1 # Permeability=1\n", + "\n", + "C = K*c*(A/d)#\n", + "print 'The Capacitance = %0.2e Farad'%C\n", + "print 'i.e 1700*10**-12 F OR 1770 pF'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example No. 16_11 Page No. 514" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The Energy Stored = 0.23 Joules\n" + ] + } + ], + "source": [ + "# The high-voltage circuit for a color picture tube can have 30 kV across 500 pF of C . Calculate the stored energy.\n", + "\n", + "# Given data\n", + "\n", + "V = 30*10**3# # Voltage=30 kVolts\n", + "C = 500*10**-12# # Cap=500 pFarad\n", + "\n", + "E = 0.5*C*V*V\n", + "print 'The Energy Stored = %0.2f Joules'%E" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.9" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |