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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 23 : Alternating Current Circuits"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. 23_1 Page No. 715"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Total Impedence Zt = 38.18 Ohms\n",
+ "Current I = 0.00 Ampers\n",
+ "i.e 1.31 mAmps\n",
+ "Theta z = 45.00 Degree\n"
+ ]
+ }
+ ],
+ "source": [
+ "from math import sqrt,atan,pi\n",
+ "# A 27-Ohms R is in series with 54 Ohms\u0004 of Xl and 27 Ohms\u0004 of Xc. The applied voltage Vt is 50 mV. Calculate ZT, I, and Theta z.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "R = 27.# # Resistance=27 Ohms\n",
+ "Xl = 54.# # Inductive reactance=54 Ohms\n",
+ "Vt = 50.*10**-3# # Applied voltage=100 Volts\n",
+ "Xc = 27.# # Capacitive reactance=27 Ohms\n",
+ "\n",
+ "nXl = Xl-Xc# # Net Inductive reactance\n",
+ "R1 = R*R#\n",
+ "nXl1 = nXl*nXl#\n",
+ "\n",
+ "Zt = sqrt(R1+nXl1)#\n",
+ "print 'Total Impedence Zt = %0.2f Ohms'%Zt\n",
+ "\n",
+ "I = (Vt/Zt)#\n",
+ "print 'Current I = %0.2f Ampers'%I\n",
+ "print 'i.e 1.31 mAmps'\n",
+ "\n",
+ "Oz = atan(Xc/R)*180/pi\n",
+ "print 'Theta z = %0.2f Degree'%Oz"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. 23_2 Page No. 717"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The Total Current It = 0.00 Amps\n",
+ "i.e 2.55 mAmps\n",
+ "The Equivqlent Impedence Zeq = 19.64 Ohms\n",
+ "approx 19.61 Ohms\n",
+ "Theta z = -45.00 Degree\n"
+ ]
+ }
+ ],
+ "source": [
+ "from math import atan,pi,sqrt\n",
+ "# The following branch currents are supplied from a 50-mV source: Ir=1.8 mA# Il=2.8 mA# Ic=1 mA. Calculate It, Zeq, and Theta I.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "Va = 50.*10**-3# # Applied voltage=50m Volts\n",
+ "Ir = 1.8*10**-3# # Ir=1.8 mAmps\n",
+ "Il = 2.8*10**-3# # Ir=2.8 mAmps\n",
+ "Ic = 1.*10**-3# # Ic=1 mAmps\n",
+ "\n",
+ "nI = Il-Ic# # net current\n",
+ "Ir1 = Ir*Ir#\n",
+ "nI1 = nI*nI#\n",
+ "\n",
+ "It = sqrt(Ir1+nI1)#\n",
+ "print 'The Total Current It = %0.2f Amps'%It\n",
+ "print 'i.e 2.55 mAmps'\n",
+ "\n",
+ "Zeq = Va/It#\n",
+ "print 'The Equivqlent Impedence Zeq = %0.2f Ohms'%Zeq\n",
+ "print 'approx 19.61 Ohms'\n",
+ "\n",
+ "Oz = atan(-(nI/Ir))*180/pi\n",
+ "print 'Theta z = %0.2f Degree'%Oz"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}