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-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:7c7e50fa2880e870c4aa1630bafd7d049a3cb3c4e646a0d88068a55be4a3d00f"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 16:INTRODUCTION TO PHASE AND CHEMICAL EQUILIBRIUM"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16.2:PG-681"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#ques2\n",
-      "#to determine change in gibbs free energy\n",
-      "\n",
-      "#1-H2\n",
-      "#2-O2\n",
-      "#3-H2O\n",
-      "\n",
-      "#at T=298 K\n",
-      "T1=298.0;#K\n",
-      "Hf1=0;#Enthalpy of formation of H2 at 298 K\n",
-      "Hf2=0;#Enthalpy of formation of O2 at 298 K\n",
-      "Hf3=-241826;#enthalpy of formation of H2O at 298 K in kJ\n",
-      "dH=2*Hf1+Hf2-2*Hf3;#Change in enthalpy in kJ\n",
-      "Sf1=130.678;#Entropy of H2 at 298 K n kJ/K\n",
-      "Sf2=205.148;#Entropy of O2 at 298 K in kJ/K\n",
-      "Sf3=188.834;#entropy of H2O at 298 K in kJ/K\n",
-      "dS=2*Sf1+Sf2-2*Sf3;#Change in entropy in kJ/K\n",
-      "dG1=dH-T1*dS;#change n gibbs free energy in kJ\n",
-      "print\" Change in gibbs free energy at\",T1,\"kelvin is\",round(dG1),\"kJ \"\n",
-      "#at T=2000 K\n",
-      "T2=2000.0;#K\n",
-      "Hf1=52942-0;#Enthalpy of formation of H2 at 2000 K\n",
-      "Hf2=59176-0;#Enthalpy of formation of O2 at 2000 K\n",
-      "Hf3=-241826+72788;#enthalpy of formation of H2O at 2000 K in kJ\n",
-      "dH=2*Hf1+Hf2-2*Hf3;#Change in enthalpy in kJ\n",
-      "Sf1=188.419;#Entropy of H2 at 2000 K n kJ/K\n",
-      "Sf2=268.748;#Entropy of O2 at 2000 K in kJ/K\n",
-      "Sf3=264.769;#entropy of H2O at 2000 K in kJ/K\n",
-      "dS=2*Sf1+Sf2-2*Sf3;#Change in entropy in kJ/K\n",
-      "dG2=dH-(T2*dS);#change n gibbs free energy in kJ\n",
-      "print\" Change in gibbs free energy at\",T2,\"kelvin is\",round(dG2),\" kJ \""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Change in gibbs free energy at 298.0 kelvin is 457179.0 kJ \n",
-        " Change in gibbs free energy at 2000.0 kelvin is 271040.0  kJ \n"
-       ]
-      }
-     ],
-     "prompt_number": 21
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex16.3:PG-683"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#ques3\n",
-      "#calculating equilibrium constant \n",
-      "\n",
-      "dG1=-457.166;#change in gibbs free energy at temp 298 K from example2 in kJ\n",
-      "dG2=-271.040;#change in gibbs free energy at temp 2000 K from example2 n kJ\n",
-      "T1=298;#K\n",
-      "T2=2000;#K\n",
-      "R=8.3145;#gas constant\n",
-      "K1=dG1*1000/(R*T1);\n",
-      "K2=dG2*1000/(R*T2);\n",
-      "print\" Equilibrium constant at \",T1,\"K = \",round(K1,2)\n",
-      "print\" Equilibrium constant at \",T2,\"K = \",round(K2,3)"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Equilibrium constant at  298 K =  -184.51\n",
-        " Equilibrium constant at  2000 K =  -16.299\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [],
-     "language": "python",
-     "metadata": {},
-     "outputs": []
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file