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diff --git a/Fluid_Mechanics_/Chapter6.ipynb b/Fluid_Mechanics_/Chapter6.ipynb new file mode 100644 index 00000000..c0425cb0 --- /dev/null +++ b/Fluid_Mechanics_/Chapter6.ipynb @@ -0,0 +1,136 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:779dd4cf4a63ec7ae3b3ee56b532415f0e7430caa393646786820e5bcc3483bb" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Chapter 6 : Dimensional Analysis and Dynamic Similitude" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 6.2 Page no 233" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Velocity of the flow\n", + "\n", + "# Given\n", + "\n", + "L = 10 # length scale lp/l\n", + "\n", + "# crue oil at 20 deg C\n", + "\n", + "rhop = 0.86*998.2 # density inn kg/m**3\n", + "\n", + "mup = 8*10**-3 # viscosity in Ns/m**2\n", + "\n", + "Vp = 2.5 # Velocity in m/s\n", + "\n", + "# water at 20 deg C\n", + "\n", + "rhom = 998.2 # density in kg/m**3\n", + "\n", + "mum = 1.005*10**-3 # viscosity in Ns/m**2\n", + "\n", + "# Solution\n", + "\n", + "Vm = Vp*L*(rhop/rhom)*(mum/mup) # velocity in m/s\n", + "\n", + "print \"Hence the model should be tested at a velocity of \",round(Vm,2),\"m/s. This velocity in the model is called corresponding velocity\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Hence the model should be tested at a velocity of 2.7 m/s. This velocity in the model is called corresponding velocity\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 6.3 Page no 233" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Mximum head on the crest and corresponding discharge for dynamically similar conditions\n", + "\n", + "# Given\n", + "\n", + "from __future__ import division\n", + "\n", + "from math import *\n", + "\n", + "l = 300 # length in ft\n", + "\n", + "Q = 100000 # discharge in cfs\n", + "\n", + "Cd = 3.8 # coefficient of discharge\n", + "\n", + "L = (1/50) # length scale\n", + "\n", + "# Solution\n", + "\n", + "Qm = 100000*(L)**(5/2) # model discharge in cfs\n", + "\n", + "print \"Maximum discharge, Qm = \",round(Qm,8),\"cfs\"\n", + "\n", + "H = (Q/(Cd*l))**(2/3) # height over spill way\n", + "\n", + "h = H*L*12 # head over spill model\n", + "\n", + "print \"Maximum head over crest = \",round(h,2),\"ft\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Maximum discharge, Qm = 5.65685425 cfs\n", + "Maximum head over crest = 4.74 ft\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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