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diff --git a/Engineering_Thermodynamics_by_P._K._Nag/ch6.ipynb b/Engineering_Thermodynamics_by_P._K._Nag/ch6.ipynb new file mode 100755 index 00000000..61336d7b --- /dev/null +++ b/Engineering_Thermodynamics_by_P._K._Nag/ch6.ipynb @@ -0,0 +1,322 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:284938688fc57eccf01fe20d1b336bc54ea30fa2a3b9197c8f73f3ff6a7b1e2c" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 6 : Second Law of Thermodynamics" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.1 Page No : 141" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 800.;\n", + "T2 = 30.;\n", + "\n", + "# Calculation\n", + "e_max = 1.-((T2+273)/(T1+273));\n", + "Wnet = 1. \t\t\t# in kW\n", + "Q1 = Wnet/e_max;\n", + "Q2 = Q1-Wnet;\n", + "\n", + "# Results\n", + "print \"Least rate of heat rejection is %.3f KW\"%Q2\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Least rate of heat rejection is 0.394 KW\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.2 Page No : 142" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = -15.+273;\n", + "T2 = 30.+273;\n", + "Q2 = 1.75; \t\t\t# in kJ/sec\n", + "\n", + "# Calculation\n", + "Q1 = Q2*T2/T1\n", + "W = Q1-Q2;\n", + "\n", + "# Results\n", + "print \"Least Power necessary to pump the heat out is\",round(W,2),\"kW\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Least Power necessary to pump the heat out is 0.31 kW\n" + ] + } + ], + "prompt_number": 10 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.4 Page No : 144" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "Q1 = 200.;\n", + "T1 = 373.15;\n", + "T2 = 273.16;\n", + "\n", + "# Calculation\n", + "Q2 = Q1*(T2/T1);\n", + "W = Q1-Q2;\n", + "e = W/Q1;\n", + "\n", + "# Results\n", + "print \"The heat rejected, the work done and the thermal effiency of the engine is %.3f J, %.1f J, %.1f respectively\"%(e,W,Q2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The heat rejected, the work done and the thermal effiency of the engine is 0.268 J, 53.6 J, 146.4 respectively\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.5 Page No : 144" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 873.;\n", + "T2 = 313.;\n", + "T3 = 253.;\n", + "Q1 = 2000.; \t\t\t# In joule\n", + "W = 360.; \t\t\t# in joule\n", + "\n", + "# Calculation\n", + "# Part (a)\n", + "e_max = round(1-(T2/T1),3);\n", + "W1 = e_max*Q1;\n", + "COP = T3/(T2-T3);\n", + "W2 = W1-W;\n", + "Q4 = COP*W2;\n", + "Q3 = Q4+W2;\n", + "Q2 = Q1-W1;\n", + "\n", + "# Results\n", + "print \"The heat rejection to the 40 degree reservior is\",round((Q2+Q3)),\"kJ\"\n", + "\n", + "# Part (b)\n", + "e_max_ = 0.4*e_max;\n", + "W1_ = e_max_*Q1;\n", + "W2_ = W1_-W;\n", + "COP_ = 0.4*COP;\n", + "Q4_ = COP_*W2_;\n", + "Q3_ = Q4_+W2_;\n", + "Q2_ = Q1-W1_;\n", + "\n", + "print \"Q4 = %.1f kJ\"%round(Q4_,1)\n", + "print \"Q3 = %.1f kJ\"%round(Q3_,1)\n", + "print \"Q2 = %.1f kJ\"%round(Q2_,1)\n", + "print \"The heat rejection to the 40 degree reservior is\",round((Q2_+Q3_)),\"kJ\"\n", + "\n", + "# note: answers are slightly different because of rounding off error. please check." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The heat rejection to the 40 degree reservior is 5528.0 kJ\n", + "Q4 = 257.7 kJ\n", + "Q3 = 410.5 kJ\n", + "Q2 = 1487.2 kJ\n", + "The heat rejection to the 40 degree reservior is 1898.0 kJ\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.7 Page No : 147" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 473.;\n", + "T2 = 293.;\n", + "T3 = 273.;\n", + "\n", + "# Calculation\n", + "MF = (T2*(T1-T3))/(T1*(T2-T3));\n", + "\n", + "# Results\n", + "print \" The multiplication factor is %.1f\"%MF\n", + "\n", + "# rounding off error." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The multiplication factor is 6.2\n" + ] + } + ], + "prompt_number": 22 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.8 Page No : 148" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 363.;\n", + "T2 = 293.;\n", + "W = 1.; \t\t\t# Kj/s\n", + "\n", + "# Calculation\n", + "e_max = 1.-(T2/T1);\n", + "Qmin = W/e_max ;\n", + "Qmin_ = Qmin*3600.;\n", + "E = 1880.; \t\t\t# in kJ/m2 h\n", + "Amin = Qmin_/E ;\n", + "\n", + "# Results\n", + "print \"Minimum area required for the collector plate %.0f m2\"%Amin\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Minimum area required for the collector plate 10 m2\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.9 Page No : 149" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "T1 = 1000.;\n", + "W = 1000.; \t\t\t# in W\n", + "K = 5.67e-08;\n", + "\n", + "# Calculation\n", + "Amin = (256.*W)/(27.*K*T1**4);\n", + "\n", + "# Results\n", + "print \"Area of the panel %.4f m^2\"%Amin\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Area of the panel 0.1672 m^2\n" + ] + } + ], + "prompt_number": 8 + } + ], + "metadata": {} + } + ] +}
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