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Diffstat (limited to 'Engineering_Physics_by_Rajendran/Chapter21.ipynb')
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diff --git a/Engineering_Physics_by_Rajendran/Chapter21.ipynb b/Engineering_Physics_by_Rajendran/Chapter21.ipynb new file mode 100755 index 00000000..c91130dc --- /dev/null +++ b/Engineering_Physics_by_Rajendran/Chapter21.ipynb @@ -0,0 +1,278 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:dd76b185872085137646ef650e27e3207f4aa1a0d590f7c3a0d53ab66156e953"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "21: Dielectric Materials"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.1, Page number 27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "a=0.629*10**-9; #lattice parameter(m)\n",
+ "alphaeK=1.26*10**-40; #electronic polarizability for K+(F/m**2)\n",
+ "alphaeCl=3.408*10**-40; #electronic polarizability for Cl-(F/m**2)\n",
+ "n=4; #number of atoms\n",
+ "epsilon0=8.854*10**-12;\n",
+ "\n",
+ "#Calculation\n",
+ "alphae=alphaeK+alphaeCl; #electronic polarizability for KCl(F/m**2)\n",
+ "N=n/(a**3); #number of dipoles(atoms/m**3)\n",
+ "epsilonr=(N*alphae/epsilon0)+1; #dielectric constant of KCl\n",
+ "\n",
+ "#Result\n",
+ "print \"dielectric constant of KCl is\",round(epsilonr,4)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "dielectric constant of KCl is 1.8474\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.2, Page number 27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "R=0.12*10**-9; #atomic radius of Se(m)\n",
+ "epsilon0=8.854*10**-12;\n",
+ "\n",
+ "#Calculation\n",
+ "alphae=4*math.pi*epsilon0*(R**3); #electronic polarizability of isolated Se(F/m**2)\n",
+ "\n",
+ "#Result\n",
+ "print \"electronic polarizability of isolated Se is\",round(alphae*10**40,4),\"*10**-40 F/m**2\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "electronic polarizability of isolated Se is 1.9226 *10**-40 F/m**2\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.3, Page number 28"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "alphae=0.35*10**-40; #electronic polarizability(F/m**2)\n",
+ "N=2.7*10**25; #number of atoms(atoms/m**3)\n",
+ "epsilon0=8.854*10**-12;\n",
+ "\n",
+ "#Calculation\n",
+ "a=N*alphae/(3*epsilon0);\n",
+ "epsilonr=(1+(2*a))/(1-a); #dielectric constant of Ne\n",
+ "\n",
+ "#Result\n",
+ "print \"dielectric constant of Ne is\",round(epsilonr,9)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "dielectric constant of Ne is 1.000106735\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.4, Page number 28"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "R=0.384*10**-9; #radius of Ar(m)\n",
+ "N=2.7*10**25; #number of atoms(atoms/m**3)\n",
+ "epsilon0=8.854*10**-12;\n",
+ "\n",
+ "#Calculation\n",
+ "alphae=4*math.pi*epsilon0*(R**3); #electronic polarizability of Ar(F/m**2)\n",
+ "a=N*alphae/(3*epsilon0);\n",
+ "epsilonr=(1+(2*a))/(1-a); #dielectric constant of Ar\n",
+ "\n",
+ "#Result\n",
+ "print \"dielectric constant of Ar is\",epsilonr\n",
+ "print \"answer given in the book is wrong\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "dielectric constant of Ar is 1.01933559019\n",
+ "answer given in the book is wrong\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.5, Page number 29"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "C=2*10**-6; #capacitance(F)\n",
+ "epsilonr=80; #permitivity of dielectric\n",
+ "V=1*10**3; #applied voltage(V)\n",
+ "\n",
+ "#Calculation\n",
+ "E1=(1/2)*C*V**2; #energy stored in capacitor(J)\n",
+ "C0=C/epsilonr; #capacitance when dielectric is removed(F)\n",
+ "E2=(1/2)*C0*V**2; #energy stored in capacitor with vacuum as dielectric(J)\n",
+ "E=1-E2; #energy stored in capacitor in polarizing the dielectric(J)\n",
+ "\n",
+ "#Result\n",
+ "print \"energy stored in capacitor is\",E1,\"J\"\n",
+ "print \"energy stored in capacitor in polarizing the dielectric is\",E,\"J\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "energy stored in capacitor is 1.0 J\n",
+ "energy stored in capacitor in polarizing the dielectric is 0.9875 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 21.6, Page number 30"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "N=5*10**28; #number of atoms(per m**3)\n",
+ "alpha=2*10**-40; #polarizability(Fm**2)\n",
+ "epsilon0=8.854*10**-12;\n",
+ "\n",
+ "#Calculation\n",
+ "P=N*alpha;\n",
+ "a=1-(P/(3*epsilon0));\n",
+ "EibyE=1/a; #ratio of internal field to applied field\n",
+ "\n",
+ "#Result\n",
+ "print \"ratio of internal field to applied field is\",round(EibyE,4)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "ratio of internal field to applied field is 1.6038\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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