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diff --git a/Engineering_Physics/Chapter_6.ipynb b/Engineering_Physics/Chapter_6.ipynb new file mode 100755 index 00000000..76ec5aef --- /dev/null +++ b/Engineering_Physics/Chapter_6.ipynb @@ -0,0 +1,399 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 6: Electron Optics" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.1, Page 6.20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from math import sqrt\n", + "\n", + "# Given \n", + "V = 500 # voltage across the electrode in eV\n", + "m = 9e-31 # mass of electron in kg\n", + "e = 1.6e-19 # charge on an electron in coulomb\n", + "\n", + "#Calculations\n", + "E = e * V\n", + "v = sqrt((2 * e * V) / m)\n", + "p = m * v\n", + "\n", + "#Result\n", + "print \"Energy gained by electron = %.e J\\nSpeed of electron = %.2e meter/sec\\nMomentum of electron = %.2e kg-meter/sec\"%(E,v,p)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Energy gained by electron = 8e-17 J\n", + "Speed of electron = 1.33e+07 meter/sec\n", + "Momentum of electron = 1.20e-23 kg-meter/sec\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.2, Page 6.20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "v = 2.5e6 # speed of electron in meter/sec\n", + "B = 2e-4 # magnetic field in tesla\n", + "r = 1.76e11 # ratio of charge on electron to the mass of electron in C/kg\n", + "\n", + "#Calculations\n", + "a = (B * r * v)\n", + "\n", + "#Result\n", + "print \"Momentum of acceleration = %.2e meter/square sec.\"%a" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Momentum of acceleration = 8.80e+13 meter/square sec.\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.4, Page 6.21" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "# Given that\n", + "v = 5.2e6 # speed of electron in meter/sec\n", + "B = 1.3e-4 # magnetic field in tesla\n", + "r = 1.76e11 # ratio of charge on electron to the mass of electron in C/kg\n", + "E = 3.2e-12 # energy of the electron beam in J\n", + "M = 9e-31 # mass of an electron in kg\n", + "\n", + "R = v / (r * B)\n", + "v_ = sqrt((2 * E) / M )\n", + "\n", + "print \"Radius of circle traced by the beam = %.1f cm. \\nSpeed of beam in second case = %.2e meter/sec\"%(R*100,v_)\n", + "print \"Speed of beam in second case is greater than speed of light so we cannot use above formula.\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Radius of circle traced by the beam = 22.7 cm. \n", + "Speed of beam in second case = 2.67e+09 meter/sec\n", + "Speed of beam in second case is greater than speed of light so we cannot use above formula.\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.5, Page 6.22" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "V = 2.500e3 # voltage across the electrode in V\n", + "E = 3.6e4 # strength of electric field in V/m\n", + "B = 1.2e-3 # magnetic field in tesla\n", + "\n", + "#Calculation\n", + "r = (E / B)**2 / (2 * V)#calculation for ratio of the charge on an electron to the mass of an electron\n", + "\n", + "#Result\n", + "print \"Ratio of the charge on an electron to the mass of an electron = %.1e C/kg.\"%r" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Ratio of the charge on an electron to the mass of an electron = 1.8e+11 C/kg.\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.6, Page 6.23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from math import sqrt\n", + "\n", + "# Given \n", + "M = 9.1e-31 # mass of electron in kg\n", + "E = 1.6e-15 # energy of electron in J\n", + "B = 5e-5 # magnetic field in tesla\n", + "e = 1.6e-19 # charge on an electron in coulomb\n", + "\n", + "#Calculations\n", + "v = sqrt((2 * E) / M)\n", + "r = (M * v) / (e * B)\n", + "\n", + "#Result\n", + "print \"Larmoure radius = %.2f meter\"%r" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Larmoure radius = 6.75 meter\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.7, Page 6.23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "Mp = 1.67e-27 # mass of proton in kg\n", + "v = 3e5 # speed of proton in meter/sec\n", + "B = 5e-9 # magnetic field in tesla\n", + "e = 1.6e-19 # charge on a proton in coulomb\n", + "\n", + "#Calculation\n", + "r = (Mp * v) / (e * B)#calculation for Larmour radius\n", + "\n", + "#Result\n", + "print \"Larmour radius = %.2e meter\"%r" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Larmour radius = 6.26e+05 meter\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.8, Page 6.23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from math import sqrt, pi\n", + "\n", + "# Given \n", + "M = 6.68e-27 # mass of helium ion in kg\n", + "E = 1.6e-16 # energy of helium ion in J\n", + "B = 5e-2 # magnetic field in tesla\n", + "e = 1.6e-19 # charge on helium ion in coulomb\n", + "\n", + "#calculations\n", + "v = sqrt((2 * E) / M)#calculation for velocity\n", + "r = (M * v) / (e * B)#calculation for Larmour radius\n", + "A = pi * r**2#calculation for area traced by the trajectory of helium ion\n", + "\n", + "#Result\n", + "print \"Area traced by the trajectory of helium ion = %.3f square meter\"%A" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Area traced by the trajectory of helium ion = 0.105 square meter\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.9, Page 6.23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "E = 100 # strength of electric field in V/m\n", + "B = 1e-3 # magnetic field in tesla\n", + "\n", + "#Calculation\n", + "v = E / B\n", + "\n", + "#Result\n", + "print \"The drift of the guiding center = %.e m/sec\"%v" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The drift of the guiding center = 1e+05 m/sec\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.10, Page 6.24" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "v = 1e6 # velocity of ion beam in m/sec\n", + "B = 1 # magnetic field in tesla\n", + "\n", + "#Calculation\n", + "E = B * v\n", + "\n", + "#Result\n", + "print \"Internal electric field = %.e V/m\"%E" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Internal electric field = 1e+06 V/m\n" + ] + } + ], + "prompt_number": 10 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6.12, Page 6.24" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given \n", + "r = 1.1 # ratio of new number of turns to the initial number of turns\n", + "\n", + "#Calculation\n", + "r_ = (1 / r)**2\n", + "\n", + "#Result\n", + "print \"Ratio of the new focus length to the initial focus length = %.3f \"%r_" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Ratio of the new focus length to the initial focus length = 0.826 \n" + ] + } + ], + "prompt_number": 11 + } + ], + "metadata": {} + } + ] +}
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