diff options
Diffstat (limited to 'Engineering_Mechanics_by_Tayal_A.K./chapter17_5.ipynb')
| -rwxr-xr-x | Engineering_Mechanics_by_Tayal_A.K./chapter17_5.ipynb | 342 |
1 files changed, 342 insertions, 0 deletions
diff --git a/Engineering_Mechanics_by_Tayal_A.K./chapter17_5.ipynb b/Engineering_Mechanics_by_Tayal_A.K./chapter17_5.ipynb new file mode 100755 index 00000000..5049e924 --- /dev/null +++ b/Engineering_Mechanics_by_Tayal_A.K./chapter17_5.ipynb @@ -0,0 +1,342 @@ +{
+ "metadata": {
+ "name": "chapter17.ipynb"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 17: Kinetics Of A Particle : Impulse And Momentum"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17-1,Page no:460"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initilization of variables\n",
+ "\n",
+ "m=0.1 # kg # mass of ball\n",
+ "\n",
+ "# Calculations\n",
+ "\n",
+ "# Consider the respective F.B.D.\n",
+ "\n",
+ "# For component eq'n in x-direction\n",
+ "delta_t=0.015 # seconds # time for which the ball &the bat are in contact\n",
+ "v_x_1=-25 # m/s \n",
+ "v_x_2=40*cos(40*(pi/180)) # m/s\n",
+ "F_x_average=((m*(v_x_2))-(m*(v_x_1)))/(delta_t) # N\n",
+ "\n",
+ "# For component eq'n in y-direction\n",
+ "delta_t=0.015 # sceonds\n",
+ "v_y_1=0 # m/s\n",
+ "v_y_2=40*sin(40*(pi/180)) # m/s\n",
+ "F_y_average=((m*v_y_2)-(m*(v_y_1)))/(delta_t) # N\n",
+ "F_average=(F_x_average**2+F_y_average**2)**0.5 # N\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"The average impules force exerted by the bat on the ball is \",round(F_average,1),\"N\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The average impules force exerted by the bat on the ball is 408.6 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Examplle 17.17-2,Page No:461"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initiliation of variables\n",
+ "\n",
+ "m_g=3000 # kg # mass of the gun\n",
+ "m_s=50 # kg # mass of the shell\n",
+ "v_s=300 # m/s # initial velocity of shell\n",
+ "s=0.6 # m # distance at which the gun is brought to rest\n",
+ "v=0 # m/s # initial velocity of gun\n",
+ "\n",
+ "# Calculations\n",
+ "\n",
+ "# On equating eq'n 1 & eq'n 2 we get v_g as,\n",
+ "v_g=(m_s*v_s)/(-m_g) # m/s\n",
+ "\n",
+ "# Using v^2-u^2=2*a*s to find acceleration,\n",
+ "a=(v**2-v_g**2)/(2*s) # m/s^2\n",
+ "\n",
+ "# Force required to stop the gun,\n",
+ "F=m_g*-a # N # here we make a +ve to find the Force\n",
+ "\n",
+ "# Time required to stop the gun, using v=u+a*t:\n",
+ "t=(-v_g)/(-a) # seconds # we take -a to consider +ve value of acceleration\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"The recoil velocity of gun is \",round(v_g),\"m/s\"\n",
+ "print\"The Force required to stop the gun is \",round(F),\"N\" # Answer in textbook 62400 is wrong as a=20.833\n",
+ "print\"The time required to stop the gun is \",round(t,2),\"seconds\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The recoil velocity of gun is -5.0 m/s\n",
+ "The Force required to stop the gun is 62500.0 N\n",
+ "The time required to stop the gun is 0.24 seconds\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17-3,Page No:462"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initilization of variables\n",
+ "\n",
+ "m_m=50 # kg # mass of man\n",
+ "m_b=250 # kg # mass of boat\n",
+ "s=5 # m # length of the boat\n",
+ "v_r=1 # m/s # here v_r=v_(m/b)= relative velocity of man with respect to boat\n",
+ "\n",
+ "# Calculations\n",
+ "\n",
+ "# Velocity of man is given by, v_m=(-v_r)+v_b\n",
+ "\n",
+ "# Final momentum of the man and the boat=m_m*v_m+m_b*v_b. From this eq'n v_b is given as\n",
+ "v_b=(m_m*v_r)*(m_m+m_b)**-1 # m/s # this is the absolute velocity of the boat\n",
+ "\n",
+ "# Time taken by man to move to the other end of the boat is,\n",
+ "t=s/v_r # seconds\n",
+ "\n",
+ "# The distance travelled by the boat in the same time is,\n",
+ "s_b=v_b*t # m to right from O\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"(a) The velocity of boat as observed from the ground is \",round(v_b,3),\"m/s\"\n",
+ "print\"(b) The distance by which the boat gets shifted is \",round(s_b,3),\"m\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) The velocity of boat as observed from the ground is 0.167 m/s\n",
+ "(b) The distance by which the boat gets shifted is 0.833 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17-5,Page No:464"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initilization of variables\n",
+ "\n",
+ "M=250 # kg # mass of the boat\n",
+ "M_1=50 # kg # mass of the man\n",
+ "M_2=75 # kg # mass of the man\n",
+ "v=4 # m/s # relative velocity of man w.r.t boat\n",
+ "\n",
+ "# Calculations \n",
+ "\n",
+ "# (a)\n",
+ "# Let the increase in the velocity or the final velocity of the boat when TWO MEN DIVE SIMULTANEOUSLY is given by eq'n,\n",
+ "deltaV_1=((M_1+M_2)*v)*(M+(M_1+M_2))**-1 # m/s\n",
+ "\n",
+ "# (b) # The increase in the velocity or the final velocity of the boat when man of 75 kg dives 1st followed by man of 50 kg\n",
+ "# Man of 75 kg dives first, So let the final velocity is given as\n",
+ "deltaV_75=(M_2*v)*((M+M_1)+M_2)**-1 # m/s\n",
+ "# Now let the man of 50 kg jumps next, Here\n",
+ "deltaV_50=(M_1*v)*(M+M_1)**-1 # m/s\n",
+ "# Let final velocity of boat is,\n",
+ "deltaV_2=0+deltaV_75+deltaV_50 # m/s\n",
+ "\n",
+ "# (c) \n",
+ "# The man of 50 kg jumps first,\n",
+ "delV_50=(M_1*v)*((M+M_2)+(M_1))**-1 # m/s\n",
+ "# the man of 75 kg jumps next,\n",
+ "delV_75=(M_2*v)*(M+M_2)**-1 # m/s\n",
+ "# Final velocity of boat is,\n",
+ "deltaV_3=0+delV_50+delV_75 # m/s\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"(a) The Final velocity of boat when two men dive simultaneously is \",round(deltaV_1,2),\"m/s\"\n",
+ "print\"(b) The Final velocity of boat when the man of 75 kg dives first and 50 kg dives second is \",round(deltaV_2,3),\"m/s\"\n",
+ "print\"(c) The Final velocity of boat when the man of 50kg dives first followed by the man of 75 kg is \",round(deltaV_3,3),\"m/s\" \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) The Final velocity of boat when two men dive simultaneously is 1.33 m/s\n",
+ "(b) The Final velocity of boat when the man of 75 kg dives first and 50 kg dives second is 1.467 m/s\n",
+ "(c) The Final velocity of boat when the man of 50kg dives first followed by the man of 75 kg is 1.456 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 30
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17-6,Page No:466"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initilization of variables\n",
+ "\n",
+ "m_m=70 # kg # mass of man\n",
+ "m_c=35 # kg # mass of canoe\n",
+ "m=25*1000**-1 # kg # mass of bullet\n",
+ "m_wb=2.25 # kg # mass of wodden block\n",
+ "V_b=5 # m/s # velocity of block\n",
+ "\n",
+ "# Calculations\n",
+ "\n",
+ "# Considering Initial Momentum of bullet=Final momentum of bullet & the block we have,Velocity of bullet (v) is given by eq'n,\n",
+ "v=(V_b*(m_wb+m))/(m) # m/s \n",
+ "\n",
+ "# Considering, Momentum of the bullet=Momentum of the canoe & the man,the velocity on canoe is given by eq'n\n",
+ "V=(m*v)*(m_m+m_c)**-1 # m/s\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"The velocity of the canoe is \",round(V,3),\"m/s\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The velocity of the canoe is 0.108 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 17.17-8,Page no:470"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "# Initilization of variables\n",
+ "\n",
+ "m=2 # kg # mass of the particle\n",
+ "v_0=20 # m/s # speed of rotation of the mass attached to the string\n",
+ "r_0=1 # m # radius of the circle along which the particle is rotated\n",
+ "r_1=r_0*0.5 # m\n",
+ "\n",
+ "# Calculations\n",
+ "\n",
+ "# here, equating (H_0)_1=(H_0)_2 i.e (m*v_0)*r_0=(m*v_1)*r_1 (here, r_1=r_0/2). On solving we get v_1 as,\n",
+ "v_1=2*v_0 # m/s\n",
+ "# Tension is given by eq'n,\n",
+ "T=(m*v_1**2)/r_1 # N\n",
+ "\n",
+ "# Results\n",
+ "\n",
+ "print\"The new speed of the particle is \",round(v_1),\"m/s\"\n",
+ "print\"The tension in the string is \",round(T),\"N\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The new speed of the particle is 40.0 m/s\n",
+ "The tension in the string is 6400.0 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 37
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |