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-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:15d0388b2c544d629a9ec990a9a36b6e26ea291bc7812312e5319e0c4bde1ab8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 7 - The second law"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 - Pg 112"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the entropy in parts ab,ac and efficiency\n",
-      "#Initialization of variables\n",
-      "import math\n",
-      "cv=0.175 #Btu/lbm R\n",
-      "R0=1.986\n",
-      "M=29\n",
-      "T2=1040 #R\n",
-      "T1=520 #R\n",
-      "#calculations\n",
-      "cp=cv+R0/M\n",
-      "sab=cv*math.log(T2/T1)\n",
-      "sac=cp*math.log(T2/T1)\n",
-      "dqab=cv*(T2-T1)\n",
-      "dqca=cp*(T1-T2)\n",
-      "dqrev=T2*(sac-sab)\n",
-      "eta=(dqab+dqrev+dqca)/(dqab+dqrev)*100\n",
-      "#results\n",
-      "print '%s %.4f %s' %(\"Entropy in ab part =\",sab,\"Btu/lbm R\")\n",
-      "print '%s %.4f %s' %(\"\\n Entropy in ac part =\",sac,\" Btu/lbm R\")\n",
-      "print '%s %.2f %s' %(\"\\n Efficiency =\",eta,\" percent\")\n",
-      "print '%s' %(\"The answers are a bit different due to rounding off error in textbook\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy in ab part = 0.1213 Btu/lbm R\n",
-        "\n",
-        " Entropy in ac part = 0.1688  Btu/lbm R\n",
-        "\n",
-        " Efficiency = 9.80  percent\n",
-        "The answers are a bit different due to rounding off error in textbook\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 115"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the change in entropy of the process\n",
-      "#Initialization of variables\n",
-      "import math\n",
-      "tc=32. #F\n",
-      "th=80. #F\n",
-      "mw=5 #lbm\n",
-      "mi=1 #lbm\n",
-      "P=14.7 #psia\n",
-      "cp=1\n",
-      "#calculations\n",
-      "t= (-144*mi+tc*mi+th*mw)/(mw+mi)\n",
-      "ds1=144/(tc+460)\n",
-      "ds2=cp*math.log((460+t)/(460+tc))\n",
-      "dsice=ds1+ds2\n",
-      "dswater=mw*cp*math.log((t+460)/(460+th))\n",
-      "ds=dsice+dswater\n",
-      "#results\n",
-      "print '%s %.4f %s' %(\"Change in entropy of the process =\",ds,\"Btu/R\")\n",
-      "print '%s' %(\"The answer is a bit different due to rounding off error in textbook\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Change in entropy of the process = 0.0192 Btu/R\n",
-        "The answer is a bit different due to rounding off error in textbook\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 - Pg 119"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate the change in available energy\n",
-      "#Initialization of variables\n",
-      "import math\n",
-      "cp=1\n",
-      "T2=60. #F\n",
-      "T1=100. #F\n",
-      "ta=32. #F\n",
-      "#calculations\n",
-      "dq=cp*(T2-T1)\n",
-      "ds=cp*math.log((460+T2)/(460+T1))\n",
-      "dE=dq-ds*(ta+460)\n",
-      "#results\n",
-      "print '%s %.1f %s' %(\"Change in available energy =\",dE,\"Btu/lbm\")\n",
-      "print '%s' %(\"The answer is a bit different due to rounding off error in textbook\")\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Change in available energy = -3.5 Btu/lbm\n",
-        "The answer is a bit different due to rounding off error in textbook\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file