diff options
Diffstat (limited to 'Electronic_Principles_/Chapter_15_New.ipynb')
| -rw-r--r-- | Electronic_Principles_/Chapter_15_New.ipynb | 436 |
1 files changed, 436 insertions, 0 deletions
diff --git a/Electronic_Principles_/Chapter_15_New.ipynb b/Electronic_Principles_/Chapter_15_New.ipynb new file mode 100644 index 00000000..3e39f907 --- /dev/null +++ b/Electronic_Principles_/Chapter_15_New.ipynb @@ -0,0 +1,436 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "CHAPTER 15 Thyristors"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-1, Page 521"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.1.py\n",
+ "#The diode of figure 15-5 has a brekover voltage of 10 V. if Vin is increased to 15V, what is the ID?\n",
+ "\n",
+ "#Variable declaration\n",
+ "VB=10 #breakover voltage(V)\n",
+ "Vin=15 #input voltage(V)\n",
+ "R=100.0 #resistance (Ohm)\n",
+ "\n",
+ "#Calculation\n",
+ "#Vin>VB so diode breaks over\n",
+ "I1=1000*Vin/R #diode current ideally(mA)\n",
+ "I2=1000*(Vin-0.7)/R #diode current with second approx.(mA)\n",
+ "#To get more accurate answer, as per figure 15-3e , Voltage=0.9V when I=150mA\n",
+ "I3=1000*(Vin-0.9)/R #diode current more accurately(mA)\n",
+ "\n",
+ "#Result\n",
+ "print 'Diode current ideally ID1 = ',I1,'mA'\n",
+ "print 'Diode current with second approx. ID2 = ',I2,'mA'\n",
+ "print 'Diode current more accurately ID3 = ',I3,'mA'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Diode current ideally ID1 = 150.0 mA\n",
+ "Diode current with second approx. ID2 = 143.0 mA\n",
+ "Diode current more accurately ID3 = 141.0 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-2, Page 525"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.2.py\n",
+ "#The diode of figure 15-5 has Ih of 4 mA. Vin is increased to 15 V ,then decreased to open the diode. \n",
+ "#What is the input voltage that opens the diode?\n",
+ "\n",
+ "#Variable declaration\n",
+ "Ih=4*10**-3 #holding current(mA)\n",
+ "R=100.0 #resistance (Ohm)\n",
+ "Vs=15 #input voltage (V)\n",
+ "\n",
+ "#Calculation\n",
+ "Vin=0.7+(Ih*R) #new input voltage(V)\n",
+ "\n",
+ "#Result\n",
+ "print 'New input voltage Vin = ',Vin,'V'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "New input voltage Vin = 1.1 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-3, Page 525"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.3.py\n",
+ "#Figure 15-6a shows a sawtooth generator. \n",
+ "#when capacitor voltage reaches +10V, diode breaks over. \n",
+ "#What is RC time constant for capacitor charging? \n",
+ "#What is frequency of the sawtooth wave if its period is approximately 20% of time constant.\n",
+ "\n",
+ "#Variable declaration\n",
+ "R=2.0*10**3 #resistance (Ohm)\n",
+ "C=0.02*10**-6 #capacitance (F)\n",
+ "VB=10 #breakdown voltage(V)\n",
+ "\n",
+ "#Calculation\n",
+ "RC=R*C #Time constant(s)\n",
+ "T=0.2*RC #period (s)\n",
+ "f=T**-1 #frequency(Hz) \n",
+ "\n",
+ "#Result\n",
+ "print 'time constant RC = ',RC*10**6,'us'\n",
+ "print 'Period T = ',T*10**6,'us'\n",
+ "print 'Frequency = ',f/1000,'KHz'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "time constant RC = 40.0 us\n",
+ "Period T = 8.0 us\n",
+ "Frequency = 125.0 KHz\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-4, Page 531"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.4.py\n",
+ "#In figure 15-14 the SCR has a trigger voltage 0.75 V and trigger current 7mA. What is Vin that turns SCR on?\n",
+ "#If Ih is 6mA, what is supply voltage that turns it off?\n",
+ "\n",
+ "#Variable declaration\n",
+ "It=7*10**-3 #trigger current(mA)\n",
+ "R1=100.0 #resistance (Ohm)\n",
+ "R2=1*10**3 #resistance (Ohm)\n",
+ "Vt=0.75 #trigger voltage (V)\n",
+ "Ih=6*10**-3 #holding current(mA)\n",
+ "\n",
+ "#Calculation\n",
+ "Vin=Vt+(It*R2) #minimum input voltage(V)\n",
+ "VCC=0.7+(Ih*R1) #supply voltage for turning of SCR(V)\n",
+ "\n",
+ "#Result\n",
+ "print 'Minimum input voltage Vin = ',Vin,'V'\n",
+ "print 'supply voltage for turning of SCR VCC = ',VCC,'V'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Minimum input voltage Vin = 7.75 V\n",
+ "supply voltage for turning of SCR VCC = 1.3 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-5, Page 532"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.5.py\n",
+ "#What is peak output voltage? What is frequency of sawtooth wave if its period is approximately 20% of time constant?\n",
+ "\n",
+ "#Variable declaration\n",
+ "IGT=200*10**-6 #trigger current(mA)\n",
+ "VGT=1 #trigger voltage(V) \n",
+ "R1=900.0 #resistance (Ohm)\n",
+ "R2=100.0 #resistance (Ohm)\n",
+ "C=0.2*10**-6 #capacitance (F)\n",
+ "Vt=0.75 #trigger voltage (V)\n",
+ "Ih=6*10**-3 #holding current(mA)\n",
+ "R=1*10**3 #Resistance (Ohm) \n",
+ "\n",
+ "#Calculation\n",
+ "RTH=R1*R2/(R1+R2) #Thevenin resistance (Ohm)\n",
+ "Vin=VGT+(IGT*RTH) #input voltage needed to trigger(V)\n",
+ "Vp=10*Vin #Output voltage at SCR firing point(V)\n",
+ "RC=C*(R/2) #time constant (s)\n",
+ "T=RC*0.2 #period (s)\n",
+ "f=1/T #frequency (Hz)\n",
+ "\n",
+ "#Result\n",
+ "print 'peak output voltage Vpeak = ',Vp,'V'\n",
+ "print 'time constant RC = ',RC*10**6,'us'\n",
+ "print 'Period T = ',T*10**6,'us'\n",
+ "print 'Frequency = ',f/1000,'KHz'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "peak output voltage Vpeak = 10.18 V\n",
+ "time constant RC = 100.0 us\n",
+ "Period T = 20.0 us\n",
+ "Frequency = 50.0 KHz\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-6, Page 536"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.6.py\n",
+ "#Calculate supply voltage that turns on crowbar of figure 15-21.\n",
+ "\n",
+ "#Variable declaration\n",
+ "Vz=5.6 #breakdown voltage(V)\n",
+ "VGT1=0.75 #trigger voltage (V) \n",
+ "VGT2=1.5 #worst case maximum trigger voltage(V) \n",
+ "Vz2=6.16 #break down voltage with 10% tolerance (V)\n",
+ "\n",
+ "#Calculation\n",
+ "VCC1=Vz+VGT1 #supply voltage(V) \n",
+ "VCC2=VGT2+Vz2 #Over voltage (V)\n",
+ "\n",
+ "#Result\n",
+ "print 'supply voltage VCC1 = ',VCC1,'V'\n",
+ "print 'supply over voltage VCC2 = ',VCC2,'V'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "supply voltage VCC1 = 6.35 V\n",
+ "supply over voltage VCC2 = 7.66 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-7, Page 539"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.7.py\n",
+ "#Using figure 15-22a, find approximate firing angle & conduction angle when R=26KOhm\n",
+ "\n",
+ "import math # This will import math module\n",
+ "\n",
+ "#Variable declaration\n",
+ "C=0.1*10**-6 #capacitance (F)\n",
+ "f=60 #frequency (Hz)\n",
+ "R=26*10**3 #resistance(KOhm)\n",
+ "Vm=120 #input ac voltage(V)\n",
+ "\n",
+ "#Calculation\n",
+ "XC=(2*math.pi*f*C)**-1 #capacitive reactance(Ohm)\n",
+ "ZT=((R**2)+(XC**2))**0.5 #impedance (Ohm)\n",
+ "thetaz=math.atan2(-XC,R)*180/math.pi #angle (deg)\n",
+ "IC=Vm/ZT #Current through C(A)\n",
+ "VC=IC*XC #voltage across C(V)\n",
+ "thetac=180+thetaz #conduction angle(deg)\n",
+ "\n",
+ "#Result\n",
+ "print 'Capacitor reactance XC = ',round((XC/1000),2),'KOhm'\n",
+ "print 'impedance ZT = ',round((ZT/1000),2),'KOhm'\n",
+ "print 'firing angle = ',round(thetaz,2),'deg'\n",
+ "print 'Current through C, IC = ',round((IC*1000),2),'mA'\n",
+ "print 'voltage across C, VC = ',round(VC,2),'V'\n",
+ "print 'conduction angle = ',round(thetac,2),'deg'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Capacitor reactance XC = 26.53 KOhm\n",
+ "impedance ZT = 37.14 KOhm\n",
+ "firing angle = -45.57 deg\n",
+ "Current through C, IC = 3.23 mA\n",
+ "voltage across C, VC = 85.7 V\n",
+ "conduction angle = 134.43 deg\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-8, Page 546"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.8.py\n",
+ "#If the triac has fired, what is the approximate current through 22Ohm resistor?\n",
+ "\n",
+ "#Variable declaration\n",
+ "C=1*10**-6 #capacitance (F)\n",
+ "R1=22.0 #resistance (Ohm)\n",
+ "R2=82*10**3 #resistance(KOhm)\n",
+ "Vs=75 #input voltage(V)\n",
+ "\n",
+ "#Calculation\n",
+ "I=Vs/R1 #current through 22Ohm resistor (A)\n",
+ "\n",
+ "#Result\n",
+ "print 'current through 22Ohm resistor I = ',round(I,2),'A'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "current through 22Ohm resistor I = 3.41 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 15-9, Page 547"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Example 15.9.py\n",
+ "#diac has breakover voltage of 32V. \n",
+ "#If the triac has a trigger voltage of 1V and a trigger current of 10mA, what is the Vc that triggers the triac?\n",
+ "\n",
+ "#Variable declaration\n",
+ "Vdb=32.0 #diac break down voltage (V)\n",
+ "VTT=1 #triac trigger voltage(V)\n",
+ "\n",
+ "#Calculation\n",
+ "Vin=VTT+Vdb #input voltage for triggering triac\n",
+ "\n",
+ "#Result\n",
+ "print 'input voltage for triggering triac vin = ',Vin,'V'"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "input voltage for triggering triac vin = 33.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 27
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |