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diff --git a/Electronic_Circuits_by_P._Raja/chapter7.ipynb b/Electronic_Circuits_by_P._Raja/chapter7.ipynb new file mode 100755 index 00000000..78dc3860 --- /dev/null +++ b/Electronic_Circuits_by_P._Raja/chapter7.ipynb @@ -0,0 +1,182 @@ +{ + "metadata": { + "name": "", + "signature": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Solved Examination Paper" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Exa 1.b - page 476" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "R1= 10 # in k\u03a9\n", + "R2= 10 # in k\u03a9\n", + "Rf= 50 # in k\u03a9\n", + "V= 2 # in V\n", + "V1= V*R1/(R1+R2) # in V\n", + "V01= -Rf/R1*V1 # in V\n", + "print \"The value of V1 = %0.f Volts\" %(V1)\n", + "print \"The value of V01 = %0.f Volts\" %(V01)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of V1 = 1 Volts\n", + "The value of V01 = -5 Volts\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Exa 2.a - page 479" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "V_P= -4 # in V\n", + "I_DSS= 10 # in mA\n", + "V_GS= 0 # in V\n", + "R_D= 1.8 # in k\u03a9\n", + "V_DD= 20 # in V\n", + "I_D= I_DSS*(1-V_GS/V_P)**2 # in mA\n", + "# Applying KVL to the circuit, we get V_DD= I_D*R_D+V_D\n", + "V_D= V_DD-I_D*R_D # in V\n", + "print \"The value of I_D = %0.f mA\" %(I_D)\n", + "print \"The value of V_D = %0.f Volts\" %V_D" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of I_D = 10 mA\n", + "The value of V_D = 2 Volts\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Exa 2.c - page 480" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "V_GS= 3 # in V\n", + "Vth= 1 # in V\n", + "unCox= 25 # in mA/V**2\n", + "unCox= unCox*10**-3 # in A/V**2\n", + "W=3 # in \u00b5m\n", + "L=1 # in \u00b5m\n", + "r_DS= 1/(unCox*W/L*(V_GS-Vth)) # in \u03a9\n", + "print \"The value of r_DS = %0.2f \u03a9 \" %r_DS" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of r_DS = 6.67 \u03a9 \n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Exa 3.b - page 481" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "I_CQ= 10 # in mA\n", + "I_CQ= I_CQ*10**-3 # in A\n", + "V_CQ= 5 # in V\n", + "V_CC= 10 # in V\n", + "R_C= 0.4 # in k\u03a9\n", + "R_C= R_C*10**3 # in \u03a9\n", + "V_BE= 0.075 # in V\n", + "V_BB= 0.175 # in V\n", + "beta=100 \n", + "beta_max=120 \n", + "beta_min= 40 \n", + "# Applying KVL we get, V_CQ= V_CC-I_C*(R_C+R_E)\n", + "R_E= (V_CC-V_CQ)/I_CQ-R_C # in \u03a9\n", + "print \"The value of R_E = %0.f \u03a9\" %( R_E)\n", + "I_B= I_CQ/beta # in A\n", + "R_B= (V_BB-V_BE)/I_B # in \u03a9\n", + "print \"The value of R_B = %0.f k\u03a9\" %(R_B*10**-3)\n", + "I_Cmax= beta_max*I_B # in A\n", + "I_Cmin= beta_min*I_B # in A\n", + "delta_I_CQ= I_Cmax-I_Cmin # in A\n", + "print \"The value of delta_I_C = %0.f mA\" %(delta_I_CQ*10**3)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of R_E = 100 \u03a9\n", + "The value of R_B = 1 k\u03a9\n", + "The value of delta_I_C = 8 mA\n" + ] + } + ], + "prompt_number": 7 + } + ], + "metadata": {} + } + ] +} |