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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:443594b95e4699aa829647ef6201862e165405ad0d20cad94e2fc280e9a33ca5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter8-Transient Analysis"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex13-pg8.16"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "##Transient analysis\n",
+      "##pg no - 8.17\n",
+      "##example no - 8.13\n",
+      "import math\n",
+      "import numpy\n",
+      "a=((10.*30.)/(10.+30.));\n",
+      "d=5./a;\n",
+      "b=0.;\n",
+      "c=5.*(20./30.);\n",
+      "print\"%s %.2f %s\"%(\"iL(0-) = \",d,\" A\");\n",
+      "print\"%s %.2f %s\"%(\"\\nvb(0-) = \", b,\"\");\n",
+      "print\"%s %.2f %s\"%(\"\\nva(0-) = \",c,\" V\");\n",
+      "print(\"Applying Kcl equations at t=0+\");\n",
+      "print(\"((va(0+)-5)/10)+(va(0+)/10)+(va(0+)-vb(0+))/20 = 0\");        ##equation 1\n",
+      "print(\"((vb(0+)-va(0+))/20)+((vb(0+)-5)/10)+(2/3) = 0\");            ##equation 2\n",
+      "##solving 1 and 2\n",
+      "M=numpy.matrix([[0.25, -0.05],[-0.05, 0.15]]);\n",
+      "N=numpy.matrix([[0.5], [-0.167]]);\n",
+      "\n",
+      "X=numpy.dot(numpy.linalg.inv(M),N);\n",
+      "print[X]\n",
+      "print(\"va(0+)= 1.9 A\");\n",
+      "print(\"vb(0+)= -0.477 A\");\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "iL(0-) =  0.67  A\n",
+        "\n",
+        "vb(0-) =  0.00 \n",
+        "\n",
+        "va(0-) =  3.33  V\n",
+        "Applying Kcl equations at t=0+\n",
+        "((va(0+)-5)/10)+(va(0+)/10)+(va(0+)-vb(0+))/20 = 0\n",
+        "((vb(0+)-va(0+))/20)+((vb(0+)-5)/10)+(2/3) = 0\n",
+        "[matrix([[ 1.90428571],\n",
+        "        [-0.47857143]])]\n",
+        "va(0+)= 1.9 A\n",
+        "vb(0+)= -0.477 A\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex14-pg8.17"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "##Transient analysis\n",
+      "##pg no - 8.17\n",
+      "##example no - 8.13\n",
+      "print(\"va(0+) = 5V\");\n",
+      "print(\"vb(0+) = 5V\");\n",
+      "print(\"vb(0+) = 5V\");\n",
+      "print(\"Writing KCL Equation at t=0+\");\n",
+      "print(\"0.25*va(0+) = 0.75\");\n",
+      "x=(0.75)/(0.25);\n",
+      "print\"%s %.2f %s\"%(\"va(0+) = \",x,\" V\");"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "va(0+) = 5V\n",
+        "vb(0+) = 5V\n",
+        "vb(0+) = 5V\n",
+        "Writing KCL Equation at t=0+\n",
+        "0.25*va(0+) = 0.75\n",
+        "va(0+) =  3.00  V\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file