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-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h1>Chapter 8: Electromagnetism</h1>"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 2, page no. 93</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the force acting on the conductor.\n",
- "#Determine also the value of the force\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "B = 0.9;# in tesla\n",
- "I = 20;# in Amperes\n",
- "l = 0.30;# in m\n",
- "alpha = 30;# in degree\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "F1 = B*I*l\n",
- "F2 = B*I*l*math.sin(alpha*math.pi/180)\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n (a)Force when the conductor is at right angles to the field = \",F1,\" N\\n\"\n",
- "print \"\\n (b)Force when the conductor is at 30\u00b0 angle to the field = \",F2,\" N\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " (a)Force when the conductor is at right angles to the field = 5.4 N\n",
- "\n",
- "\n",
- " (b)Force when the conductor is at 30\u00c2\u00b0 angle to the field = 2.7 N"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 3, page no. 94</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the current required?\n",
- "#what is the direction of the force?\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "F = 1.92;# in newton\n",
- "B = 1.2;# in tesla\n",
- "l = 0.40;# in m\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "I = F/(B*l)\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n (a)Current I = \",I,\" Amperes(A)\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " (a)Current I = 4.0 Amperes(A)"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 4, page no. 95</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the magnitude of the force exerted on the conductor.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "r = 0.06;# in m\n",
- "I = 10;# in Amperes\n",
- "l = 0.35;# in m\n",
- "Phi = 0.5E-3;# in Wb\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "A = math.pi*r*r\n",
- "B = Phi/A\n",
- "F = B*I*l\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n (a)Force F = \",round(F,2),\" N\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " (a)Force F = 0.15 N"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 6, page no. 95</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#determine the force on each coil side (a) for a single-turn coil,\n",
- "#(b) for a coil wound with 300 turns.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "N1 = 1;# for a single-turn coil\n",
- "N2 = 300;# no. of turns\n",
- "b = 0.024;# in m\n",
- "B = 0.8;# in Tesla\n",
- "I = 0.05;# in Amperes\n",
- "l = 0.030;# in m\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "#For a single-turn coil,\n",
- "F1 = N1*B*I*l\n",
- "#for a coil wound with 300 turns.\n",
- "F2 = N2*B*I*l\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n (a)For a single-turn coil, force on each coil side = \",F1,\" N\\n\"\n",
- "print \"\\n (b)For a 300-turn coil, force on each coil side = \",F2,\" N\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " (a)For a single-turn coil, force on each coil side = 0.0012 N\n",
- "\n",
- "\n",
- " (b)For a 300-turn coil, force on each coil side = 0.36 N"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 7, page no. 98</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the force exerted on the electron in the field.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "Q = 1.6E-19;# in Coulomb\n",
- "v = 3E7;# in m/s\n",
- "B = 18.5E-6;# in Tesla\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "F = Q*v*B\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Force exerted on the electron in the field. = \",(F/1E-17),\"E-17 N\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Force exerted on the electron in the field. = 8.88 E-17 N"
- ]
- }
- ],
- "prompt_number": 5
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file