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diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_04-checkpoint_2.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_04-checkpoint_2.ipynb
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--- a/Electrical_Circuit_Theory_And_Technology/chapter_04-checkpoint_2.ipynb
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@@ -1,185 +0,0 @@
-{
- "metadata": {
-  "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "markdown",
-     "metadata": {},
-     "source": [
-      "<h1>Chapter 4: Chemical effects of\n",
-      "electricity</h1>"
-     ]
-    },
-    {
-     "cell_type": "markdown",
-     "metadata": {},
-     "source": [
-      "<h3>Example 1, page no. 35</h3>"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#Determine the e.m.f. and the internal resistance of the batteries formed by (a)Series arrangement and (b)Parallel Arrangement.\n",
-      "from __future__ import division\n",
-      "#initializing the variables:\n",
-      "R = 0.2; # in ohms\n",
-      "n = 8; # no. of cells\n",
-      "e = 2.2; # in volts\n",
-      "\n",
-      "#calculation:\n",
-      "es = n*e\n",
-      "ep = e\n",
-      "Rs = n*R\n",
-      "Rp = R/n\n",
-      "\n",
-      "#results\n",
-      "print \"(a)Resistance\", Rs,\"ohms; e.m.f\", es,\"Volts(V)\"\n",
-      "print \"(b)Resistance\", Rp,\"ohms; e.m.f\", ep,\"Volts(V)\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(a)Resistance 1.6 ohms; e.m.f 17.6 Volts(V)\n",
-        "(b)Resistance 0.025 ohms; e.m.f 2.2 Volts(V)"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "markdown",
-     "metadata": {},
-     "source": [
-      "<h3>Example 2, page no. 35</h3>"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#Calculate its terminal p.d. if it delivers (a) 5 A, (b) 50 A\n",
-      "from __future__ import division\n",
-      "#initializing the variables:\n",
-      "r = 0.02; # in ohms\n",
-      "e = 2; # in volts\n",
-      "I1 = 5; # in Amperes\n",
-      "I2 = 50; # in Amperes\n",
-      "\n",
-      "#calculation:\n",
-      "pd1 = e - (I1*r)\n",
-      "pd2 = e - (I2*r)\n",
-      "\n",
-      "#results\n",
-      "print \"(a)p.d\", pd1,\"Volts(V)\"\n",
-      "print \"(b)p.d\", pd2,\"Volts(V)\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(a)p.d 1.9 Volts(V)\n",
-        "(b)p.d 1.0 Volts(V)"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "markdown",
-     "metadata": {},
-     "source": [
-      "<h3>Example 3, page no. 36</h3>"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#Determine the internal resistance of the battery.\n",
-      "from __future__ import division\n",
-      "#initializing the variables:\n",
-      "e1 = 25; # in volts\n",
-      "e2 = 24; # in volts\n",
-      "I2 = 10; # in Amperes\n",
-      "\n",
-      "#calculation:\n",
-      "r = (e1 - e2)/I2\n",
-      "\n",
-      "#results\n",
-      "print \"Resistance\", r,\"Ohms\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Resistance 0.1 Ohms"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "markdown",
-     "metadata": {},
-     "source": [
-      "<h3>Example 4, page no. 36</h3>"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#Determine (a) the current flowing in the circuit and (b) the p.d. at the battery terminals.\n",
-      "from __future__ import division\n",
-      "#initializing the variables:\n",
-      "r = 0.2; # in ohms\n",
-      "n = 10; # no. of cells\n",
-      "e = 1.5; # in volts\n",
-      "R = 58; # in ohms\n",
-      "\n",
-      "#calculation:\n",
-      "es = n*e\n",
-      "rs = n*r\n",
-      "I = es/(rs + R)\n",
-      "pd = es - (I*rs)\n",
-      "\n",
-      "#results\n",
-      "print \"(a)Current\", I,\"Amperes(A)\"\n",
-      "print \"(b)p.d\", pd,\"Volts(V)\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "(a)Current 0.25 Amperes(A)\n",
-        "(b)p.d 14.5 Volts(V)"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file