diff options
Diffstat (limited to 'Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb')
| -rwxr-xr-x | Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb | 525 |
1 files changed, 0 insertions, 525 deletions
diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb deleted file mode 100755 index f79d1396..00000000 --- a/Electrical_Circuit_Theory_And_Technology/chapter_03-checkpoint.ipynb +++ /dev/null @@ -1,525 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h1>Chapter 3: Resistance variation</h1>"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 1, page no. 24</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine (a) the resistance of an 8 m length of the same wire,\n",
- "#and (b) the length of the same wire when the resistance is 420\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R = 600; # in ohms\n",
- "L = 5; # in meter\n",
- "L1 = 8; # in meter\n",
- "R2 = 420; # in ohms\n",
- "\n",
- "#calculation:\n",
- "R1 = R*L1/L\n",
- "L2 = R2*L/R\n",
- "\n",
- "#results\n",
- "print \"a)Resistance\", R1,\"Ohms\"\n",
- "print \"b)Length:\", L2,\"meters(m)\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "a)Resistance 960.0 Ohms\n",
- "b)Length: 3.5 meters(m)"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 2, page no. 24</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Find (a) the resistance of a wire of the same length and material if the cross-sectional area is 5 mm2,\n",
- "#(b) the cross-sectional area of a wire of the same length and material of resistance 750 \n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R = 300; # in ohms\n",
- "A = 2; # in mm2\n",
- "A1 = 5; # in mm2\n",
- "R2 = 750; # in ohms\n",
- "\n",
- "#calculation:\n",
- "R1 = R*A/A1\n",
- "A2 = R*A/R2\n",
- "\n",
- "#results\n",
- "print \"(a)Resistance\", R1,\"Ohms\"\n",
- "print \"(b)C.S.A:\", A2,\"mm^2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a)Resistance 120.0 Ohms\n",
- "(b)C.S.A: 0.8 mm^2"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 3, page no. 25</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#determine the resistance of the wire.\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R = 0.16; # in ohms\n",
- "A = 3; # in mm2\n",
- "L = 8; # in m\n",
- "A1 = 1; # in mm2\n",
- "\n",
- "#calculation:\n",
- "L1 = L*3\n",
- "R1 = R*A*L1/(A1*L)\n",
- "\n",
- "#results\n",
- "print \"Resistance\", R1,\"Ohms\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance 1.44 Ohms"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 4, page no. 25</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the resistance.\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "A = 100E-6; # in m2\n",
- "L = 2000; # in m\n",
- "p = 0.03E-6; # in ohm m\n",
- "\n",
- "#calculation:\n",
- "R = p*L/A\n",
- "\n",
- "#results\n",
- "print \"Resistance\", R,\"Ohms\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance 0.6 Ohms"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 5, page no. 25</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the cross-sectional area\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R = 0.25; # in ohms\n",
- "L = 40; # in m\n",
- "p = 0.02E-6; # in ohm m\n",
- "\n",
- "#calculation:\n",
- "A = p*L*1E6/R\n",
- "\n",
- "#results\n",
- "print \"C.S.A \", A,\"mm^2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "C.S.A 3.2 mm^2"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 6, page no. 25</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the resistivity of the wire.\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R = 150; # in ohms\n",
- "L = 1500; # in m\n",
- "A = 0.17E-6; # in m2\n",
- "\n",
- "#calculation:\n",
- "p = R*A*1E6/L\n",
- "\n",
- "#results\n",
- "print \"resistivity\", p,\"uOhm.m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistivity 0.017 uOhm.m"
- ]
- }
- ],
- "prompt_number": 18
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 7, page no. 26</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the resistance\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "d = 0.012; # in m\n",
- "L = 1200; # in m\n",
- "p = 1.7E-8; # in ohm m\n",
- "\n",
- "#calculation:\n",
- "A = math.pi*d*d/4\n",
- "R = p*L/A\n",
- "\n",
- "#results\n",
- "print \"resistance\", round(R,3),\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance 0.18 Ohm"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 8, page no. 27</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine its resistance\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R0 = 100; # in ohms\n",
- "T0 = 0; # in \u00b0C\n",
- "T1 = 70; # in \u00b0C\n",
- "a0 = 0.0043; # in per\u00b0C\n",
- "\n",
- "#calculation:\n",
- "R70 = R0*(1 + (a0*T1))\n",
- "\n",
- "#results\n",
- "print \"Resistance\", R70,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance 130.1 Ohm"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 9, page no. 27</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine its resistance\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R1 = 27; # in ohms\n",
- "T0 = 0; # in \u00b0C\n",
- "T1 = 35; # in \u00b0C\n",
- "a0 = 0.0038; # in per\u00b0C\n",
- "\n",
- "#calculation:\n",
- "R0 = R1/(1 + (a0*T1))\n",
- "\n",
- "#results\n",
- "print \"resistance\", round(R0,2),\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance 23.83 Ohm"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 10, page no. 27</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine its resistance\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R0 = 1000; # in ohms\n",
- "T0 = 0; # in \u00b0C\n",
- "T1 = 80; # in \u00b0C\n",
- "a0 = -0.0005; # in per\u00b0C\n",
- "\n",
- "#calculation:\n",
- "R80 = R0*(1 + (a0*T1))\n",
- "\n",
- "#results\n",
- "print \"resistance\", R80,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance 960.0 Ohm"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 11, page no. 28</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#determine the resistance of the coil\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R20 = 10; # in ohms\n",
- "T0 = 20; # in \u00b0C\n",
- "T1 = 100; # in \u00b0C\n",
- "a20 = 0.004; # in per\u00b0C\n",
- "\n",
- "\n",
- "#calculation:\n",
- "R100 = R20*(1 + (a20)*(T1 - T0))\n",
- "\n",
- "#results\n",
- "print \"resistance\", R100,\"Ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resistance 13.2 Ohm"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 12, page no. 28</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#determine the temperature to which the coil has risen\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R18 = 200; # in ohms\n",
- "R1 = 240; # in ohms\n",
- "T0 = 18; # in \u00b0C\n",
- "a18 = 0.0039; # in per\u00b0C\n",
- "\n",
- "\n",
- "#calculation:\n",
- "T1 = (((R1/R18)-1)/a18) + T0\n",
- "\n",
- "#results\n",
- "print \"Temperature\", round(T1,2),\"degC\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Temperature 69.28 degC"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "<h3>Example 13, page no. 29</h3>"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the resistance of the wire\n",
- "from __future__ import division\n",
- "#initializing the variables:\n",
- "R20 = 200; # in ohms\n",
- "T0 = 20; # in \u00b0C\n",
- "T1 = 90; # in \u00b0C\n",
- "a0 = 0.004; # in per\u00b0C\n",
- "\n",
- "\n",
- "#calculation:\n",
- "R90 = R20*(1 + (a0*T1))/(1 + (a0*T0))\n",
- "\n",
- "#results\n",
- "print \"Resistance\", round(R90,0),\"ohms\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resistance 252.0 ohms"
- ]
- }
- ],
- "prompt_number": 7
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |