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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h1>Chapter 1: Units Associated with Basic Electrical Quantities</h1>"
+     ]
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 1, page no. 4</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#find the quantity of electricity transferred.\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "I = 5;   # in Ampere\n",
+      "t = 120; # in sec\n",
+      "\n",
+      "#calculation:\n",
+      "Q = I*t\n",
+      "\n",
+      "#results\n",
+      "print \"Charge, Q = \", Q,\"coulomb(C)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Charge, Q =  600 coulomb(C)"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 2, page no. 5</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Determine the force needed.\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "M = 5; # in Kg\n",
+      "a = 2; # in m/s2\n",
+      "\n",
+      "#calculation:\n",
+      "F = M*a\n",
+      "\n",
+      "#results\n",
+      "print \"Force:\", F,\"Newton(N)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Force: 10 Newton(N)"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 3, page no. 5</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Find the force acting vertically downwards\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "M = 0.2; # in Kg\n",
+      "g = 9.81; # in m/s2\n",
+      "\n",
+      "#calculation:\n",
+      "F = M*g\n",
+      "\n",
+      "#results\n",
+      "print \"Force:\", F,\"Newton(N)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Force: 1.962 Newton(N)"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 4, page no. 6</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Calculate Work Done and Average Power?\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "F = 200; # in Newton\n",
+      "d = 20; # in m\n",
+      "t = 25; # in sec\n",
+      "\n",
+      "#calculation:\n",
+      "W = F*d\n",
+      "P = W/t\n",
+      "\n",
+      "#results\n",
+      "print \"Power:\", P,\"watt(W)\"\n",
+      "print \"Work Done:\", W,\"Nm\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Power: 160.0 watt(W)\n",
+        "Work Done: 4000 Nm"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 5, page no. 6</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#What is (a) the work done and (b) the power developed?\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "M = 1000; # in Kg\n",
+      "h = 10; # in m\n",
+      "t = 20; # in sec\n",
+      "g = 9.81 # in m/s2\n",
+      "\n",
+      "#calculation:\n",
+      "W = M*g*h\n",
+      "P = W/t\n",
+      "\n",
+      "#results\n",
+      "print \"Work Done:\", W,\"Joule(J)\"\n",
+      "print \"Power:\", P,\"watt(W)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Work Done: 98100.0 Joule(J)\n",
+        "Power: 4905.0 watt(W)"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 6, page no. 7</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Find the conductance of a conductor of resistances\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "R1 = 10; # in ohm\n",
+      "R2 = 5000; # in ohm\n",
+      "R3 = 0.1; # in ohm\n",
+      "#calculation:\n",
+      "G1 = 1/R1\n",
+      "G2 = 1/R2\n",
+      "G3 = 1/R3\n",
+      "\n",
+      "#results\n",
+      "print \"conductance(G1):\", G1,\"seimen(S)\"\n",
+      "print \"conductance(G2):\", G2,\"seimen(S)\"\n",
+      "print \"conductance(G3):\", G3,\"seimen(S)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "conductance(G1): 0.1 seimen(S)\n",
+        "conductance(G2): 0.0002 seimen(S)\n",
+        "conductance(G3): 10.0 seimen(S)"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 7, page no. 7</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#How much energy is provided in this time?\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "V = 5; # in Volts\n",
+      "I = 3; # in Ampere\n",
+      "t = 600; # in sec\n",
+      "#calculation:\n",
+      "P = V*I\n",
+      "E = P*t\n",
+      "\n",
+      "#results\n",
+      "print \"Energy(E):\", E,\"Joule(J)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Energy(E): 9000 Joule(J)"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "markdown",
+     "metadata": {},
+     "source": [
+      "<h3>Example 8, page no. 8</h3>"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Find the power rating of the heater and the current taken from the supply.\n",
+      "from __future__ import division\n",
+      "#initializing the variables:\n",
+      "E = 18E5; # in Joule\n",
+      "V = 250; # in Volts\n",
+      "t = 1800; # in sec\n",
+      "\n",
+      "#calculation:\n",
+      "P = E/t\n",
+      "I = P/V\n",
+      "\n",
+      "#results\n",
+      "print \"Power(P):\", P,\"Watt(W)\"\n",
+      "print \"Current(I):\", I,\"Ampere(A)\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Power(P): 1000.0 Watt(W)\n",
+        "Current(I): 4.0 Ampere(A)"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file