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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 10 - The pvT relationships"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "    Example 1 - Pg 230"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the pressure of the gas using both ideal and vanderwaals cases\n",
+      "#Initialization of variables\n",
+      "m=1 #lbm\n",
+      "T1=212+460. #R\n",
+      "sv=0.193 #ft^3/lbm\n",
+      "M=44\n",
+      "a=924.2 #atm ft^2 /mole^2\n",
+      "b=0.685 #ft^3/mol\n",
+      "R=0.73 #atm ft^3/R mol\n",
+      "#calculations\n",
+      "v=sv*M\n",
+      "p=R*T1/v\n",
+      "p2=R*T1/(v-b) -a/v/v\n",
+      "#results\n",
+      "print '%s %.1f %s' %(\"In ideal gas case, pressure =\",p,\"atm\")\n",
+      "print '%s %.1f %s' %(\"\\n In vanderwaals equation, pressure =\",p2,\"atm\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "In ideal gas case, pressure = 57.8 atm\n",
+        "\n",
+        " In vanderwaals equation, pressure = 50.0 atm\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2 - Pg 232"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the volume of the gas\n",
+      "#Initialization of variables\n",
+      "m=1 #lbm\n",
+      "p=50.9 #atm\n",
+      "t=212+460. #R\n",
+      "R=0.73\n",
+      "#calculations\n",
+      "pc=72.9 #atm\n",
+      "tc=87.9 +460 #R\n",
+      "pr=p/pc\n",
+      "Tr=t/tc\n",
+      "z=0.88\n",
+      "v=z*R*t/p\n",
+      "#results\n",
+      "print '%s %.3f %s' %(\"volume =\",v,\"ft^3/mole\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "volume = 8.481 ft^3/mole\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3 - Pg 233"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the pressure of the gas\n",
+      "#Initialization of variables\n",
+      "t=212+460. #R\n",
+      "v=0.193 #ft^3/lbm\n",
+      "M=44\n",
+      "R=0.73\n",
+      "#calculations\n",
+      "tc=87.9+460. #F\n",
+      "zc=0.275\n",
+      "vc=1.51 #ft^3/mol\n",
+      "tr=t/tc\n",
+      "vr=v*M/vc\n",
+      "vrd=vr*zc\n",
+      "z=0.88\n",
+      "p=z*R*t/(M*v)\n",
+      "#results\n",
+      "print '%s %.1f %s' %(\"Pressure =\",p,\"atm\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Pressure = 50.8 atm\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
+\ No newline at end of file