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Diffstat (limited to 'Concepts_of_Thermodynamics/Chapter16.ipynb')
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diff --git a/Concepts_of_Thermodynamics/Chapter16.ipynb b/Concepts_of_Thermodynamics/Chapter16.ipynb new file mode 100755 index 00000000..164da53c --- /dev/null +++ b/Concepts_of_Thermodynamics/Chapter16.ipynb @@ -0,0 +1,478 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 16 - Combustion"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 1 - Pg 448"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the molecule \n",
+ "#Initialization of variables\n",
+ "per=85.\n",
+ "#calculations\n",
+ "a=per/12.\n",
+ "b=100-per\n",
+ "ad=1.13*a\n",
+ "bd=1.13*b\n",
+ "#results\n",
+ "print '%s %d %s %d' %(\"Molecule is C\",ad, \"H\",bd+1)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Molecule is C 8 H 17\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 2 - Pg 448"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the Oxygen and Nitrogen compositions and also the molecule\n",
+ "#Initialization of variables\n",
+ "per=0.071\n",
+ "#calculations\n",
+ "O2=8.74\n",
+ "N2=per/2. + 3.76*O2\n",
+ "Nin=32.85\n",
+ "CO2=7.333\n",
+ "H2o=3\n",
+ "So2=0.0312\n",
+ "#results\n",
+ "print '%s %.2f %s %.2f'%(\"Oxygen =\",O2,\" and Nitrogen =\",N2)\n",
+ "print '%s %.3f %s %d %s %.2f %s %.2f %s %.3f %s %d %s %.5f %s %.2f %s' %(\"\\n Equation is C\",CO2, \"H\",2*H2o,\"+\",O2,\" O2 +\",Nin,\" N2 = \",CO2,\"CO2 +\",H2o,\"H2O +\",So2,\" SO2 +\",N2,\"N2\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Oxygen = 8.74 and Nitrogen = 32.90\n",
+ "\n",
+ " Equation is C 7.333 H 6 + 8.74 O2 + 32.85 N2 = 7.333 CO2 + 3 H2O + 0.03120 SO2 + 32.90 N2\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 4 - Pg 451"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the air fuel ratio\n",
+ "#Initialization of variables\n",
+ "N2=78.1\n",
+ "M=29\n",
+ "co2=8.7\n",
+ "co=8.9\n",
+ "x4=0.3\n",
+ "x5=3.7\n",
+ "x6=14.7\n",
+ "#calculations\n",
+ "O2=N2/3.76\n",
+ "Z=(co2+co+x4)/8.\n",
+ "AF=(O2+N2)*M/(Z*113.)\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Air fuel ratio =\",AF,\"lbm air/lbm fuel\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air fuel ratio = 11.3 lbm air/lbm fuel\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5 - Pg 452"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the air fuel ratio\n",
+ "#Initialization of variables\n",
+ "N2=78.1\n",
+ "M=29\n",
+ "ba=2.12\n",
+ "x4=0.3\n",
+ "x5=3.7\n",
+ "x6=14.7\n",
+ "#calculations\n",
+ "O2=N2/3.76\n",
+ "O2=N2/3.76\n",
+ "Z=(x4*4+x5*2+x6*2)/17.\n",
+ "AF=(O2+N2)*M/(Z*113.)\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Air fuel ratio =\",AF,\"lbm air/lbm fuel\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air fuel ratio = 11.4 lbm air/lbm fuel\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 6 - Pg 452"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the air fuel ratio\n",
+ "#Initialization of variables\n",
+ "N2=78.1\n",
+ "M=29\n",
+ "ba=2.12\n",
+ "x4=0.3\n",
+ "x5=3.7\n",
+ "x6=14.7\n",
+ "#calculations\n",
+ "O2=N2/3.76\n",
+ "c=14.7\n",
+ "b= x4*4 + x5*2 + x6*2\n",
+ "a=b/ba\n",
+ "AF=(O2+N2)*M/(a*12 + b)\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Air fuel ratio =\",AF,\"lbm air/lbm fuel\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air fuel ratio = 11.3 lbm air/lbm fuel\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 7 - Pg 453"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the air fuel ratio\n",
+ "#Initialization of variables\n",
+ "N2=78.1\n",
+ "M=29\n",
+ "ba=2.12\n",
+ "co2=8.7\n",
+ "co=8.9\n",
+ "x4=0.3\n",
+ "x5=3.7\n",
+ "x6=14.7\n",
+ "#calculations\n",
+ "O2=N2/3.76\n",
+ "c=14.7\n",
+ "Z=2.238\n",
+ "X=(Z*17-x4*4-x5*2)/2\n",
+ "a=co2+co/2+x4+x6/2\n",
+ "b=3.764*a\n",
+ "AF=(O2+N2)*M/(Z*113)\n",
+ "#results\n",
+ "print '%s %.1f %s' %(\"Air fuel ratio =\",AF,\"lbm air/lbm fuel\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air fuel ratio = 11.3 lbm air/lbm fuel\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8 - Pg 454"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the air fuel ratio\n",
+ "#Initialization of variables\n",
+ "x1=8.7\n",
+ "x2=8.9\n",
+ "x3=0.3\n",
+ "N=78.1\n",
+ "z=113\n",
+ "M=29\n",
+ "#calculations\n",
+ "co2=(x1+x2+x3)*100/(N+x1+x2+x3)\n",
+ "a=2.325\n",
+ "AF=103*M/(a*z)\n",
+ "#results\n",
+ "print '%s %.2f %s' %(\"Air fuel ratio =\",AF,\"lbm air/lbm fuel\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air fuel ratio = 11.37 lbm air/lbm fuel\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 9 - Pg 457"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the higher heating value\n",
+ "#Initialization of variables\n",
+ "dH=-2369859. #Btu\n",
+ "r=1.986\n",
+ "dn=5.5\n",
+ "T=536.7 #R\n",
+ "#calculations\n",
+ "dQ=dH+dn*r*T\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Higher heating value =\",dQ,\"Btu\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Higher heating value = -2363996 Btu\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 10 - Pg 457"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the lower heating value\n",
+ "#Initialization of variables\n",
+ "y=13.\n",
+ "x=12.\n",
+ "M2=18.\n",
+ "M=170.\n",
+ "p=0.4593\n",
+ "vfg=694.9\n",
+ "J=778.2\n",
+ "m=9*18\n",
+ "u1=-2363996 #Btu\n",
+ "#calculations\n",
+ "z=y*M2/M\n",
+ "hfg=1050.4 #Btu/lbm\n",
+ "ufg= hfg- p*vfg*144/J\n",
+ "dU=ufg*m \n",
+ "Lhv=u1+dU\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Lower heating value =\",Lhv,\" Btu/lbm\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Lower heating value = -2203398 Btu/lbm\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 11 - Pg 457"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the heat of reaction\n",
+ "#Initialization of variables\n",
+ "n1=8.\n",
+ "n2=9.\n",
+ "n3=1.\n",
+ "n4=12.5\n",
+ "U11=3852.\n",
+ "U12=115.\n",
+ "U21=3009.\n",
+ "U22=101.\n",
+ "U31=24773.\n",
+ "U32=640.\n",
+ "U41=2539.\n",
+ "U42=83.\n",
+ "H=-2203389.\n",
+ "#calculations\n",
+ "dU1=n1*(U11-U12)+n2*(U21-U22)\n",
+ "dU2=n3*(U31-U32)+n4*(U41-U42)\n",
+ "Q=H+dU1-dU2\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Heat of reaction =\",Q,\"Btu\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Heat of reaction = -2202154 Btu\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12 - Pg 459"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate the final temperature\n",
+ "#Initialization of variables\n",
+ "n1=8\n",
+ "n2=9\n",
+ "n3=47\n",
+ "h1=118\n",
+ "h2=104\n",
+ "h3=82.5\n",
+ "Q=2203279 #Btu\n",
+ "#calculations\n",
+ "U11=n1*h1+n2*h2+n3*h3\n",
+ "U12=U11+Q\n",
+ "T2=5271 #R\n",
+ "#results\n",
+ "print '%s %d %s' %(\"Upon interpolating, T2 =\",T2,\" R\")\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Upon interpolating, T2 = 5271 R\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |