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diff --git a/Chemical_Engineering_Thermodynamics_by_Y._V._C._Rao/ch13.ipynb b/Chemical_Engineering_Thermodynamics_by_Y._V._C._Rao/ch13.ipynb new file mode 100755 index 00000000..8dc5f0be --- /dev/null +++ b/Chemical_Engineering_Thermodynamics_by_Y._V._C._Rao/ch13.ipynb @@ -0,0 +1,235 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 13 : Dilute solution laws" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 13.1 Page No : 478" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "weight = 10. \t\t\t #weight of NaCl in grams\n", + "volume = 1. \t \t\t #volume of water in litres\n", + "weight_water = 1000. \t\t\t # weight of water in grams (Weight = Volume*Density, density of water = 1g/cc = 1g/ml = 1000g/l)\n", + "molwt_NaCl = 58.5 \t\t\t #molecular weight of NaCl in grams\n", + "molwt_water = 18. \t\t\t #molecular weight of water in grams\n", + "hf = 6.002; \t\t\t #enthalpy change of fusion in kJ/mol at 0 degree celsius\n", + "P = 101.325; \t\t\t #pressure in kPa\n", + "T = 273.15; \t\t\t # freezing point temperature of water at the given pressure in K\n", + "R = 8.314; \t\t\t #universal gas constant in J/molK;\n", + "\n", + "# Calculations\n", + "x2 = (weight/molwt_NaCl)/((weight/molwt_NaCl)+(weight_water/molwt_water))\n", + "delt = (R*T**2*x2)/(hf*10**3)\n", + "\n", + "# Results\n", + "print ' The depression in freezing point of water when 10g of NaCl solute is added = %0.2f K'%(delt);\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The depression in freezing point of water when 10g of NaCl solute is added = 0.32 K\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 13.2 Page No : 480" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "weight = 10.; \t\t \t #weight of NaCl in grams\n", + "volume = 1.; \t\t\t #volume of water in litres\n", + "weight_water = 1000.; \t\t\t # weight of water in grams (Weight = Volume*Density, density of water = 1g/cc = 1g/ml = 1000g/l)\n", + "molwt_NaCl = 58.5; \t\t\t #molecular weight of NaCl in grams\n", + "molwt_water = 18; \t\t\t #molecular weight of water in grams\n", + "lat_ht = 2256.94; \t\t\t #latent heat of vaporization in kJ/kg at 100 degree celsius (obtained from steam tables)\n", + "P = 101.325; \t\t\t #pressure in kPa\n", + "T = 373.15; \t\t\t #boiling point temperature of water at the given pressure in K\n", + "R = 8.314; \t\t\t #universal gas constant in J/molK\n", + "\n", + "# Calculations\n", + "x2 = 0.0031\n", + "hv = (lat_ht*molwt_water)/1000\n", + "delt = (R*T**2*x2)/(hv*10**3)\n", + "\n", + "# Results\n", + "print ' The elevation in boiling point of water when 10g of NaCl solute is added = %0.2f K'%(delt);\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The elevation in boiling point of water when 10g of NaCl solute is added = 0.09 K\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 13.3 Page No : 481" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "weight = 10.; \t\t\t #weight of NaCl in grams\n", + "weight_water = 1000.; \t\t\t # weight of water in grams\n", + "molwt_NaCl = 58.5; \t\t\t #molecular weight of NaCl in grams\n", + "molwt_water = 18.; \t\t\t #molecular weight of water in grams\n", + "T = 300.; \t\t\t #prevailing temperature of water in K\n", + "R = 8.314; \t\t\t #universal gas constant in (Pa m**3)/(mol K);\n", + "v = 18*10**-6;\t\t\t #molar volume in m**3/mol\n", + "\n", + "# Calculations\n", + "x2 = 0.0031\n", + "pi = ((R*T*x2)/v)*10**-3\n", + "\n", + "# Results\n", + "print ' The osmotic pressure of a solution conatining 10g of NaCl in 1000g of water at 300K = %0.2f kPa'%(pi);\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The osmotic pressure of a solution conatining 10g of NaCl in 1000g of water at 300K = 429.56 kPa\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 13.4 Page No : 483" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "\n", + "# Variables\n", + "temp = 20. \t\t\t # prevailing tempearture in degree celsius\n", + "melt_temp = 80.05; \t\t\t # melting point of naphthalene in degree celsius\n", + "hf = 18.574 \t\t\t # enthalpy of fusion in kJ/mol\n", + "R = 8.314 \t\t\t # universal gas constant in J/molK\n", + "\n", + "# Calculations\n", + "t = temp+273.15\n", + "melt_t = melt_temp+273.15\n", + "x2 = math.exp(((hf*10**3)/R)*((1./melt_t)-(1./t)))\n", + "\n", + "# Results\n", + "print ' The ideal solubility of naphthalene at 20 degree celsius = %0.4f'%(x2);\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The ideal solubility of naphthalene at 20 degree celsius = 0.2737\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 13.5 Page No : 483" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "t = 295.43; \t\t\t #prevailing temperature in K\n", + "sat_p = 6.05; \t\t\t #Sasturation pressure of carbon dioxide at the prevailing temperature in MPa\n", + "p = 0.1; \t\t\t #pressure at which solubility has to be determined in MPa\n", + "\n", + "# Calculations\n", + "x2 = p/sat_p\n", + "\n", + "# Results\n", + "print ' The solubility of carbon dioxide expressed in mole fraction of carbon dioxide in solution\\\n", + " at 0.1MPa = %0.4f'%(x2);\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The solubility of carbon dioxide expressed in mole fraction of carbon dioxide in solution at 0.1MPa = 0.0165\n" + ] + } + ], + "prompt_number": 6 + } + ], + "metadata": {} + } + ] +}
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