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diff --git a/Chemical_Engineering_Thermodynamics_by_S._Sundaram/ch15_1.ipynb b/Chemical_Engineering_Thermodynamics_by_S._Sundaram/ch15_1.ipynb new file mode 100755 index 00000000..0fd672b5 --- /dev/null +++ b/Chemical_Engineering_Thermodynamics_by_S._Sundaram/ch15_1.ipynb @@ -0,0 +1,67 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:e134d729844fc5fc379f513b7f1e5b167020e513591a6ab49b7a3de0e1f6059e" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 15 : Fuel Cells" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 15.1 Page No : 321" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Given\n", + "del_F = -56.29;#Smath.radians(numpy.arcmath.tan(ard free energy change in Kcal/Kgmole\n", + "del_H = -68.317;#Smath.radians(numpy.arcmath.tan(ard heat of reaction in Kcal/kgmole\n", + "F = 23.06;#Electro-chemical equivalent in Kcal/volt\n", + "J = 2.0;#Valance for H2\n", + "\n", + "#To Calculate the emf of the cell, cell efficiency and heat to be removed to maintain isothermal conditions\n", + "#Basis: 1 Kgmole of H2\n", + "#From equation 15.4 (page no 355)\n", + "E = -del_F/(F*J);\n", + "print '1.The emf of the cell is %f volt.'%(E);\n", + "n = del_F/del_H*100;\n", + "print ' 2.The cell efficiency is %f percent.'%(n);\n", + "Q = del_H-del_F;\n", + "print ' 3.The heat to be removed is %f Kcal to maintain the temperature at 25 degree celsius.'%(Q);\n", + "#end\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "1.The emf of the cell is 1.220512 volt.\n", + " 2.The cell efficiency is 82.395304 percent.\n", + " 3.The heat to be removed is -12.027000 Kcal to maintain the temperature at 25 degree celsius.\n" + ] + } + ], + "prompt_number": 1 + } + ], + "metadata": {} + } + ] +}
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