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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:234a7cd4eb239b4fead8bceff4c3350a039b4673e5cc1a175a4862ee9b56966f"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 8 : Third Law of Thermodynamics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 8.1 Page No : 138"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "%matplotlib inline\n",
+ "\n",
+ "import math\n",
+ "import matplotlib.pyplot as plt\n",
+ "import numpy\n",
+ "\n",
+ "#Given\n",
+ "C_ps = 0.1;#Molal heat capacity of copper at 20 K\n",
+ "Ti = 0.0;#Initial temperature in K\n",
+ "Tf = 20.0;#melting point in K\n",
+ "Tb = 300.0;#boiling point in K\n",
+ "\n",
+ "#To calculate the absolute entropy of copper at 300 K\n",
+ "#From equation 8.4(page no 164)\n",
+ "a = C_ps/(Tf**3);# a is the charateristic consmath.tant\n",
+ "C_p = [0.1,0.80,1.94,3.0,3.9,5.0];\n",
+ "#T1 = math.log(T);\n",
+ "T1 = [1.301,1.6021,1.7782,1.9031,2.000,2.1761];\n",
+ "plt.plot(T1,C_p)\n",
+ "plt.title(\"C_p vs T1\")\n",
+ "plt.xlabel(\"T1\")\n",
+ "plt.ylabel(\"Cp\")\n",
+ "plt.show()\n",
+ "# Area under the curve is given as\n",
+ "A = 7.82;\n",
+ "#From equation 8.5(page no 164)\n",
+ "S = (a*((Tf**3)/3))+A;\n",
+ "print \"The absolute entropy of copper is %f Kcal/Kgmole\"%(S);\n",
+ "#end\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "metadata": {},
+ "output_type": "display_data",
+ "png": 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+ "text": [
+ "<matplotlib.figure.Figure at 0x102f267d0>"
+ ]
+ },
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The absolute entropy of copper is 7.853333 Kcal/Kgmole\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file