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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 4 : Temperature"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "\n",
+ "Example 4.1 Page no. 92\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Temperature Conversion\n",
+ "# Solution\n",
+ "\n",
+ "# Variable\n",
+ "#(a)\n",
+ "Temp_c=100. ; #[degree Celsius]\n",
+ "\n",
+ "# Calculation and Result\n",
+ "Temp_k=Temp_c+273 ; #[K]\n",
+ "print '(a) Temperature in kelvin is %.2f K'%Temp_k\n",
+ "\n",
+ "#(b)\n",
+ "Temp_f=(100*(1.8/1)) +32 ; #[degree Fahrenheit]\n",
+ "print ' (b) Temperature in degree Fahrenheit is %.2f '%Temp_f\n",
+ "\n",
+ "#(c)\n",
+ "Temp_r= Temp_f + 460 ; #[degree Rankine ]\n",
+ "print ' (c) Temperature in degree Rankine is %.2f '%Temp_r"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Temperature in kelvin is 373.00 K\n",
+ " (b) Temperature in degree Fahrenheit is 212.00 \n",
+ " (c) Temperature in degree Rankine is 672.00 \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 4.2 Page no. 93\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Temperature Conversion\n",
+ "# Solution\n",
+ "\n",
+ "# Variables\n",
+ "c = 139.1 + (1.56*10**-1)*(-460-32)/1.8 ;\n",
+ "d = (1.56*10**-1)/1.8;\n",
+ "\n",
+ "# Calculation\n",
+ "#Now convert c +dTR to (Btu/lb mol*degree R) to get answer of form a + bTR,where\n",
+ "a = c*(454/(1055*1.8)) ;\n",
+ "b = d*(454/(1055*1.8)) ;\n",
+ "\n",
+ "# Result\n",
+ "print 'The required answer is %.2f + (%.2e)T Btu/(lb mol*degree R) , where T is in degree R . '%(a,b)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The required answer is 23.06 + (2.07e-02)T Btu/(lb mol*degree R) , where T is in degree R . "
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "code",
+ "collapsed": true,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file