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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 29 : Humidity Charts and their Uses"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 29.1 page no. 895\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# determining properties of moist air from the humidity chart\n",
+ "\n",
+ "# Variables\n",
+ "DBT = 90. ;\t\t\t# Dry bulb temperature - [degree F]\n",
+ "WBT = 70. ;\t\t\t# Wet bulb temperature - [degree F]\n",
+ "\n",
+ "#Get point A using DBT & WBT. Following information is obtained from humidity chart, fig. E29.1\n",
+ "# Results\n",
+ "print '(a) The Dew point is located at point B or about 60 degree F, using constant humidity line.'\n",
+ "print ' (b) By interpolation between 40%% and 30%% RH , you can find point A is at 37%% relative humidity .'\n",
+ "print ' (c) You can read humidity from the righthand ordinate as 0.0112 lb H2O/lb dry air .'\n",
+ "print ' (d) By interpolation again between 14.0 cubic feet/lb and 14.5 cubic feet/lb lines , you can find humid volume to be 14.1 cubic feet/lb dry air.'\n",
+ "print ' (e) The enthalpy value of saturated air with WBT 70 degree F is 34.1 Btu/lb dry air .'\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) The Dew point is located at point B or about 60 degree F, using constant humidity line.\n",
+ " (b) By interpolation between 40%% and 30%% RH , you can find point A is at 37%% relative humidity .\n",
+ " (c) You can read humidity from the righthand ordinate as 0.0112 lb H2O/lb dry air .\n",
+ " (d) By interpolation again between 14.0 cubic feet/lb and 14.5 cubic feet/lb lines , you can find humid volume to be 14.1 cubic feet/lb dry air.\n",
+ " (e) The enthalpy value of saturated air with WBT 70 degree F is 34.1 Btu/lb dry air .\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ " Example 29.2 page no. 897\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Heating at constant Humidity\n",
+ "\n",
+ "# Solution fig. E29.2\n",
+ "\n",
+ "# Variables\n",
+ "DBT1 = 38 ;\t\t\t# Initial dry bulb temperature - [degree C]\n",
+ "DBT2 = 86 ;\t\t\t# Final dry bulb temperature - [degree C]\n",
+ "RH1 = 49 ;\t\t\t# Relative humidity - [%]\n",
+ "\n",
+ "#A is initial and B is final point , see fig. E29.2 . Dew point is obtained graphically and it is 24.8 degree C,therefore\n",
+ "print 'The Dew point is unchanged in the process because humidity is unchanged, and it is located at 24.8 degree C.'\n",
+ "\n",
+ "# Calculations\n",
+ "# Additional data is obtained from humidity chart , according to book data is as follows\n",
+ "A_Hsat = 90.0 ;\t\t\t# Enthalpy of saturation at point A- [kJ/kg]\n",
+ "A_dH = -0.5 ;\t\t\t#Enthalpy deviation-[kJ/kg]\n",
+ "A_Hact = A_Hsat + A_dH ;\t\t\t# Actual enthalpy at point A -[kJ/kg]\n",
+ "B_Hsat = 143.3 ;\t\t\t# Enthalpy of saturation at point B- [kJ/kg]\n",
+ "B_dH = -3.3 ;\t\t\t#Enthalpy deviation -[kJ/kg]\n",
+ "B_Hact = B_Hsat + B_dH ;\t\t\t# Actual enthalpy at point B -[kJ/kg]\n",
+ "\n",
+ "\t\t\t# Energy balance reduces to Q = del_H \n",
+ "del_H = B_Hact - A_Hact ;\t\t\t# Total change in enthalpy - [kJ/kg]\n",
+ "v = 0.91 ;\t\t\t# Specific volume of moist air at point A -[cubic metre / kg]\n",
+ "Q = del_H/v ;\t\t\t# Heat added per cubic metre of inital moist air -[kJ]\n",
+ "\n",
+ "# Results\n",
+ "print ' Heat added per cubic metre of inital moist air is %.1f kJ.'%Q\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Dew point is unchanged in the process because humidity is unchanged, and it is located at 24.8 degree C.\n",
+ " Heat added per cubic metre of inital moist air is 55.5 kJ.\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ " Example 29.3 page no. 898\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Cooling and Humidification using a Water Spray\n",
+ "\n",
+ "# Solution fig. E29.3b\n",
+ "\n",
+ "# Variables\n",
+ "DBT1 = 40 ;\t\t\t# Initial dry bulb temperature - [degree C]\n",
+ "DBT2 = 27 ;\t\t\t# Final dry bulb temperature - [degree C]\n",
+ "\n",
+ "# Process is assumed to be adiabatic, therefore wet bulb temperature is constant\n",
+ "WBT1 = 22 ;\t\t\t# Initial wet bulb temperature - [degree C]\n",
+ "WBT2 = WBT1 ;\t\t\t# Final wet bulb temperature - [degree C]\n",
+ "\n",
+ "# Calculations\n",
+ "#A is initial and B is final point , see fig. E29.3b . Humidity is obtained from humidity chart, according to book the respective humidities are as follows\n",
+ "H_B = 0.0145 ;\t\t\t# Humidity at point B -[kg H2O/kg dry air]\n",
+ "H_A = 0.0093 ;\t\t\t# Humidity at point A -[kg H2O/kg dry air]\n",
+ "Diff = H_B - H_A ;\t\t\t# Moisture added in kg per kilogram of dry air going through humidifier -[kg H2O/kg dry air] \n",
+ "\n",
+ "# Results\n",
+ "print 'Moisture added per kilogram of dry air going through humidifier is %.4f kg H2O.'%Diff\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Moisture added per kilogram of dry air going through humidifier is 0.0052 kg H2O.\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ " Example 29.4 page no. 900\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Combined Material and Energy Balance for a Cooling Tower\n",
+ "\n",
+ "# Solution fig. E29.4\n",
+ "\n",
+ "# Variables\n",
+ "c_bl = 8.30 * 10**6 ;\t\t\t# Capacity of blower - [cubic feet/hr]\n",
+ "DBT_A = 80 ;\t\t\t# Initial dry bulb temperature of moist air - [degree F]\n",
+ "DBT_B = 95 ;\t\t\t# Final dry bulb temperature of exit air - [degree F]\n",
+ "WBT_A = 65 ;\t\t\t# Initial wet bulb temperature of moist air - [degree F]\n",
+ "WBT_B = 90 ;\t\t\t# Final wet bulb temperature of exit air - [degree F]\n",
+ "T1_H2O = 120 ;\t\t\t# Initial temperature of water - [degree F]\n",
+ "T2_H2O = 90 ;\t\t\t# Final temperature of water - [degree F]\n",
+ "\n",
+ "#A is initial and B is final point , see fig. E29.4 . Humidity is obtained from humidity chart, according to book the respective humidities are as follows\n",
+ "H_A = 0.0098; \t\t\t# Humidity of air at A - [lb H2O / lb dry air]\n",
+ "H1_A = 69 ;\t\t\t# Humidity of air at A - [grains H2O / lb dry air]\n",
+ "\n",
+ "# Calculations\n",
+ "delH_A = 30.05 - 0.12; \t\t\t# Enthalpy of entering air -[Btu/lb dry air]\n",
+ "v_A = 13.82 ;\t\t\t# Specific volume of entering air -[cubic feet/lb dry air]\n",
+ "H_B = 0.0297;\t\t\t# Humidity of air at B - [lb H2O / lb dry air]\n",
+ "H1_B = 208 ;\t\t\t# Humidity of air at B - [grains H2O / lb dry air]\n",
+ "delH_B = 55.93 - 0.10 ;\t\t\t# Enthalpy of exit air -[Btu/lb dry air]\n",
+ "v_B = 14.65 ;\t\t\t# Specific volume of exit air -[cubic feet/lb dry air]\n",
+ "Eq_A = c_bl /v_A ;\t\t\t# Entering dry air equivalent of capacity of blower -[lb dry air]\n",
+ "\n",
+ "# Reference temperature for water stream is 32 degree F \n",
+ "del_H1_H2O = 1*(T1_H2O - 32) ;\t\t\t#Enthalpy of entering water -[Btu/lb H2O]\n",
+ "del_H2_H2O = 1*(T2_H2O - 32) ;\t\t\t#Enthalpy of exit water -[Btu/lb H2O]\n",
+ "tr_H2O = H_B - H_A ;\t\t\t# Transfer of water to air -[lb H2O / lb dry air] \n",
+ "\n",
+ "# Energy balance around the entire process yields W -\n",
+ "W = (delH_B - del_H2_H2O*tr_H2O - delH_A)/(del_H1_H2O - del_H2_H2O) ;\t\t\t# Water entering tower - [lb H2O/lb dry air]\n",
+ "W1 = W - tr_H2O ;\t\t\t# Water leaving tower -[lb H2O/lb dry air]\n",
+ "Total_W1 = W1* Eq_A ;\t\t\t# Total water leaving tower -[lb/hr]\n",
+ "\n",
+ "# Results\n",
+ "print 'Amount of water cooled per hour is %.2e lb/hr .'%Total_W1\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Amount of water cooled per hour is 4.83e+05 lb/hr .\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ " Example 29.5 page no. 902\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Drying of Chlorella\n",
+ "\n",
+ "# Solution fig. E29.5\n",
+ "\n",
+ "# Variables\n",
+ "W = 100 ;\t\t\t# Amount of entering water -[lb/hr]\n",
+ "H1 = .020 ;\t\t\t# Humidity of entering air -[lb H2O / lb dry air]\n",
+ "T1 = 155 ;\t\t\t#Temperature of entering air -[degree F]\n",
+ "DTB = 110 ;\t\t\t# Dry bulb temperature of exit air -[degree F]\n",
+ "WTB = 100 ;\t\t\t# Wet bulb temperature of exit air -[degree F]\n",
+ "\n",
+ "# Additional data is obtained from humidity chart, it is as follows\n",
+ "H2 = .0405 ;\t\t\t#Humidity of exit air -[lb H2O / lb dry air]\n",
+ "\n",
+ "# Calculations\n",
+ "del_H = H2 - H1 ;\t\t\t# Change in humidity betwween two states -[lb H2O / lb dry air]\n",
+ "air_in = (W*1.02)/(del_H * 1) ;\t\t\t# Amount of wet air entering -[lb]\n",
+ "\n",
+ "mol_air = 29. ;\t\t\t# Molecular wt. of air -[lb]\n",
+ "Ref_T = 32 + 460. ;\t\t\t# Reference temperature - [ degree R]\n",
+ "gi_T = 90 + 460.; \t\t\t# Given temperature on which calculation is based - [degree R] \n",
+ "air = (air_in *359*gi_T)/( mol_air*Ref_T) ;\t\t\t# Air consumption of dryer at 90 degree F and 1 atm -[cubic feet]\n",
+ "\n",
+ "# Results\n",
+ "print 'Air consumption of dryer at 90 degree F and 1 atm is %.2e cubic feet .'%air\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Air consumption of dryer at 90 degree F and 1 atm is 6.89e+04 cubic feet .\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "code",
+ "collapsed": true,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": [],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file