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diff --git a/Basic_Electronics_and_Linear_Circuits/ch2_1.ipynb b/Basic_Electronics_and_Linear_Circuits/ch2_1.ipynb new file mode 100755 index 00000000..cdec3a81 --- /dev/null +++ b/Basic_Electronics_and_Linear_Circuits/ch2_1.ipynb @@ -0,0 +1,187 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:d04dc734c5bc464767e0da96b38331e03b832b88f0bd8644b242b3682feeb9d9"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 2:Current and Voltage Source"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 2.1 Page no.39"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "Vs=2 #V open circuit voltage\n",
+ "Rs=1 #ohm . internal impedence\n",
+ "#Current Source or Norton's Representaion (Parallel Current Source & Resistor\n",
+ "Is=Vs/Rs #Ampere, short circuit current\n",
+ "#result\n",
+ "print \"The Short Circuit Current Value is \",Is,\"A\"\n",
+ "print \"The Source Impedence Value is \",Rs,\"ohm\"\n",
+ "print \"The Current Source & Source Impedance are connected in Parallel.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Short Circuit Current Value is 2 A\n",
+ "The Source Impedence Value is 1 ohm\n",
+ "The Current Source & Source Impedance are connected in Parallel.\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 2.2 Page no.40"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "Is=0.2 #Amperes\n",
+ "Zs=100 #Ohms\n",
+ "#Voltage Source or Thevenin's Representaion (Series Voltage Source & Resistor)\n",
+ "Vs=Is*Zs #Volts\n",
+ "# Results \n",
+ "print \"The Open Circuit Voltage is \",Vs,\"V\"\n",
+ "print \"The Source Impedence Value is \",Zs,\"ohm\"\n",
+ "print \"The Voltage Source & Source Impedance are connected in Series.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Open Circuit Voltage is 20.0 V\n",
+ "The Source Impedence Value is 100 ohm\n",
+ "The Voltage Source & Source Impedance are connected in Series.\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 2.3 Page no.40"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "Is=1.5*10**(-3) #Amperes ,source current\n",
+ "Zs=2000 #Ohms, resistance connected to the loads\n",
+ "Z1=10000 #Ohms , load resistance 1\n",
+ "Z2=40000 #Ohms load resistance 2\n",
+ "#Calculation for Current Source Representation\n",
+ "Zl=Z1*Z2/(Z1+Z2)\n",
+ "I2=Is*Zs/(Zs+Zl)\n",
+ "I4I=I2*Z1/(Z1+Z2) #Using Current Divider Rule\n",
+ "\n",
+ "#Calculation for Current Source Representation\n",
+ "Vs=Is*Zs #Open Circuit Volatge\n",
+ "I=Vs/(Zs+Zl)\n",
+ "I4V=I*Z1/(Z1+Z2) #Using Current Divider Rule\n",
+ "# Results \n",
+ "print \"The Load Current using Current Source Representaion is I4I = \",I4I,\"A\"\n",
+ "print \"The Load Current using Voltage Source Representaion is I4V = \",I4V,\"A\"\n",
+ "print \"I4I==I4V so\"\n",
+ "print \" Both Results are same.\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Load Current using Current Source Representaion is I4I = 6e-05 A\n",
+ "The Load Current using Voltage Source Representaion is I4V = 6e-05 A\n",
+ "I4I==I4V so\n",
+ " Both Results are same.\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 2.4 Page no.45"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " \n",
+ "Vs=0.01 #V ,dc voltage\n",
+ "Rs=1000 # ohm, resistance\n",
+ "#Output Side resistance\n",
+ "Ro1=20000 #ohm, 20 kOhms\n",
+ "Ro2=2000 # Ohms\n",
+ "\n",
+ "#Calculation\n",
+ "i=Vs/Rs #Input Current\n",
+ "Io=100*i #Output Current\n",
+ "Il=Io*Ro1/(Ro1+Ro2) #Using Current Divider Rule\n",
+ "Vo=Il*Ro2 #Output Volatge\n",
+ "\n",
+ "# Result\n",
+ "print \"The Output Voltage Vo = \",round(Vo,3),\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Output Voltage Vo = 1.818 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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