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diff --git a/Applied_Thermodynamics/Chapter2.ipynb b/Applied_Thermodynamics/Chapter2.ipynb new file mode 100755 index 00000000..f774f7a6 --- /dev/null +++ b/Applied_Thermodynamics/Chapter2.ipynb @@ -0,0 +1,227 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:1c6a10e6b876d2730bb167805af2fccb3104db62a9988f5aa3ef9c4c86e9b481" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 2: Zeroth Law of Thermodynamics" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1, page no. 46" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "#Variable Declaration: \n", + "Tf = 98.6 #Temperature of human body in degree Fahrenheit:\n", + "\n", + "#Calculation:\n", + "Tc = (Tf-32)/1.8 #Temperature of the body in degree Celcius:\n", + "\n", + "#Results:\n", + "print \"Temperature of the human body \",Tc,\"\u00b0C\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Temperature of the human body 37.0 \u00b0C\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2, page no. 47" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "import math as m\n", + "import numpy as n\n", + "\n", + "#Variable Declaration: \n", + "p0 = 3.0 #Thermodynamic property at T = 0:\n", + "p100 = 8.0 #Thermodynamic property at T = 100:\n", + "p = 6.5 #Thermodynamic property at which t is to be found\n", + "\n", + "#Calculation:\n", + "#Solving two linear equation by linear Algebra using matrices AX = B\n", + "A = n.matrix([[m.log(p0),0.5],[m.log(p100),0.5]])\n", + "B = n.matrix([[0],[100]])\n", + "X = n.matrix.getI(A)*B\n", + "a = round(X[0],2) #Thermodynamic constant a from matrix solution\n", + "b = round(X[1]) #Thermodynamic constant b from matrix solution\n", + "t = a*m.log(p)-b/2 #At thermodynamic property p = 6.5:\n", + "\n", + "#Results:\n", + "print \"Temperature at the value of thermodynamic property (p = 6.5)\" ,round(t,2),\"\u00b0C\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Temperature at the value of thermodynamic property (p = 6.5) 302.83 \u00b0C\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3, page no. 47" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "#Variable Declaration:\n", + "T0 = 0 #Ice point (\u00b0C)\n", + "T100 = 100 #Steam Poiont (\u00b0C)\n", + "def E(t): #Function definition for above expression of EMF\n", + " return 0.003*t - 5*10**-7*t**2 + 0.5 *10**-3\n", + "\n", + "#Calculation:\n", + "t = (E(30)-E(0))/(E(100)-E(0))*(T100-T0) #Temperature shown by the thermometer at T = 30:\n", + "\n", + "#Results:\n", + "print \"!--Please check that there are calculation mistake done in the book \\nhence there is heavy difference in answer of book and the code--!\\n\"\n", + "print \"The temperature shown by thermometer: \",round(t,2),\"\u00b0C\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "!--Please check that there are calculation mistake done in the book \n", + "hence there is heavy difference in answer of book and the code--!\n", + "\n", + "The temperature shown by thermometer: 30.36 \u00b0C\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4, page no. 48" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "#Variable Declaration: \n", + "t1 = 50 #Temperature of gas using gas thermometer:\n", + "def E(t): #Function Definition as per question:\n", + " return 0.18*t - 5.2*10**-4*t**2\n", + " \n", + "#Calculation:\n", + "t = (100-0)*E(t1)/(E(100)-E(0))\t#Temperature at EMF = E50:\n", + "p = (t-t1)/t1*100\n", + "\n", + "#Results:\n", + "print \"Percentage variation: \",round(p,2),\"%\"\n", + " " + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Percentage variation: 20.31 %\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 5, page no. 48" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + " \n", + "import numpy as n\n", + "\n", + "#Variable Declaration: \n", + "#Solving the conversion relation X = aC + b using matrices and finding a and b\n", + "B = n.matrix([[0],[1000]])\n", + "A = n.matrix([[0,1],[100,1]])\n", + "\n", + "#Calculations:\n", + "X = n.matrix.getI(A)*B\n", + "a = round(X[0]) #Value of a of equation X = aC + B\n", + "b = round(X[1]) #Value of b of equation X = aC + B\n", + "X = a*-273.15+b #Absolute temperature in new temperature scale:\n", + "\n", + "#Results:\n", + "print \"Absolute temperature in new scale: \",X,\"\u00b0X\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Absolute temperature in new scale: -2731.5 \u00b0X\n" + ] + } + ], + "prompt_number": 5 + } + ], + "metadata": {} + } + ] +}
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