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Diffstat (limited to 'Applied_Physics/Chapter_02_Crystal_Structure.ipynb')
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diff --git a/Applied_Physics/Chapter_02_Crystal_Structure.ipynb b/Applied_Physics/Chapter_02_Crystal_Structure.ipynb deleted file mode 100755 index 2d0b7a14..00000000 --- a/Applied_Physics/Chapter_02_Crystal_Structure.ipynb +++ /dev/null @@ -1,291 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:f14517ab3de72640bce8c38f7d46947caa54ae7067bb37477a81849b7b917982"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 2:Crystal Structure"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1 , Page no:40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "N=6.02*10**26; #in /Kg-molecule (Avogadro's number)\n",
- "n=4; #number of molecules per unit cell ofr NaCl\n",
- "M=58.5; #in Kg/Kg-molecule (molecular weight of NaCl)\n",
- "p=2189; #in Kg/m^3 (density)\n",
- "\n",
- "#calculate\n",
- "a=pow(((n*M)/(N*p)),0.3333333);\n",
- "a1=a*10**10; #changing unit to Angstrom\n",
- "\n",
- "#result\n",
- "print\"The lattice constant is a=\",a,\"m\";\n",
- "print\"\\t\\t\\ta=\",a1,\"Angstrom\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The lattice constant is a= 5.62072226997e-10 m\n",
- "\t\t\ta= 5.62072226997 Angstrom\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2 , Page no:41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "from __future__ import division\n",
- "\n",
- "#given\n",
- "N=6.02*10**23; #in /gram-atom (Avogadro's number)\n",
- "n=4; #number of atom per unit cell for fcc structure\n",
- "M=63.5; #in gram/gram-atom (atomic weight of Cu)\n",
- "p=8.96; #in g/cm^3 (density)\n",
- "\n",
- "#calculate\n",
- "a=pow((n*M/(N*p)),0.3333333);\n",
- "a=a*1E8; #changing unit from cm to Angstrom\n",
- "d=a/math.sqrt(2); #distance infcc lattice\n",
- "\n",
- "#result\n",
- "print\"lattice constant is a=\",a,\"E-08 cm\";\n",
- "print\"\\t\\t a=\",round(a,4),\"Angstrom\";\n",
- "print\"distance between two nearest Cu atoms is d=\",round(d,2),\"Angstrom\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "lattice constant is a= 3.61113576149 E-08 cm\n",
- "\t\t a= 3.6111 Angstrom\n",
- "distance between two nearest Cu atoms is d= 2.55 Angstrom\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 , Page no:41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "from __future__ import division\n",
- "\n",
- "#given\n",
- "N=6.02E26; #in /Kg-atom (Avogadro's number)\n",
- "n=2; #number of molecules per unit cell for bcc lattice\n",
- "M=55.85; #in Kg/Kg-atom (atomic weight of Iron)\n",
- "p=7860; #in Kg/m^3 (density)\n",
- "\n",
- "#calculate\n",
- "a=pow((n*M/(N*p)),0.33333);\n",
- "a1=a*1E10; #changing unit to Angstrom\n",
- "\n",
- "#result\n",
- "print\"The lattice constant is a=\",a,\"m\";\n",
- "print\"\\t\\t\\ta=\",round(a1,3),\"Angstrom\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The lattice constant is a= 2.86928355016e-10 m\n",
- "\t\t\ta= 2.869 Angstrom\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.4 , Page no:42"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "from __future__ import division\n",
- "\n",
- "#given\n",
- "N=6.02*10**26; #in /Kg-atom (Avogadro's number)\n",
- "n=2; #number of molecules per unit cell for bcc lattice\n",
- "M=6.94; #in Kg/Kg-atom (atomic weight of Iron)\n",
- "p=530; #in Kg/m^3 (density)\n",
- "\n",
- "#calculate\n",
- "a=pow((n*M/(N*p)),0.33333);\n",
- "a1=a*1E10; #changing unit to Angstrom\n",
- "\n",
- "#result\n",
- "print\"The lattice constant is a=\",a,\"m\";\n",
- "print\"\\t\\t\\ta=\",round(a1,3),\"Angstrom\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The lattice constant is a= 3.51776567326e-10 m\n",
- "\t\t\ta= 3.518 Angstrom\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5 , Page no:42"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "from __future__ import division\n",
- "\n",
- "#given\n",
- "N=6.02*10**23; #in /gram-molecule (Avogadro's number)\n",
- "M=58.5; #in gram/gram-molecule (atomic weight of NaCl)\n",
- "p=2.17; #in g/cm^3 (density)\n",
- "\n",
- "#calculate\n",
- "#since V=M/p\n",
- "#(1/d)^-3=2N/V=2Np/M\n",
- "#therefore d= (M/2Np)^-3\n",
- "d=pow((M/(2*N*p)),0.33333333);\n",
- "d1=d*1*10**8; #changing unit from cm to Angstrom\n",
- "\n",
- "#result\n",
- "print\"The distance between two adjacent atoms of NaCl is d=\",d,\"m\";\n",
- "print\"\\t\\t\\t\\t\\t\\t d=\",round(d1,3),\"Angstrom\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The distance between two adjacent atoms of NaCl is d= 2.81853408124e-08 m\n",
- "\t\t\t\t\t\t d= 2.819 Angstrom\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 , Page no:43"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "from __future__ import division\n",
- "\n",
- "#given\n",
- "r_Na=0.98; #in Angstrom (radius of sodium ion)\n",
- "r_Cl=1.81; #in Angstrom (radius of chloride ion)\n",
- "M_Na=22.99; #in amu (atomic mass of sodium)\n",
- "M_Cl=35.45; #in amu (atomic mass of chlorine)\n",
- "\n",
- "#calculate\n",
- "a=2*(r_Na+r_Cl); #lattice parameter\n",
- "#PF=volume of ions present in the unit cell/volume of unit cell\n",
- "PF=((4*(4/3)*3.14)*r_Na**3+(4*(4/3)*3.14)*r_Cl**3)/a**3;\n",
- "#Density=mass of unit cell/volume of unit cell\n",
- "p=4*(M_Na+M_Cl)*1.66E-27/(a*1E-10)**3;\n",
- "p1=p*1E-3; #changing unit to gm/cm^-3\n",
- "\n",
- "#result\n",
- "print\"Lattice constant is a=\",round(a,3),\"Angstrom\";\n",
- "print\"Packing fraction is =\",round(PF,3); \n",
- "print\"Density is p=\",round(p),\"Kg/m^3\";\n",
- "print\"Density is p=\",round(p1,2),\"g/cm^3\";"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Lattice constant is a= 5.58 Angstrom\n",
- "Packing fraction is = 0.662\n",
- "Density is p= 2233.0 Kg/m^3\n",
- "Density is p= 2.23 g/cm^3\n"
- ]
- }
- ],
- "prompt_number": 6
- }
- ],
- "metadata": {}
- }
- ]
-}
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