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diff --git a/Applied_Physics-II_by_I_A_Shaikh/chapter3.ipynb b/Applied_Physics-II_by_I_A_Shaikh/chapter3.ipynb new file mode 100755 index 00000000..714dfad3 --- /dev/null +++ b/Applied_Physics-II_by_I_A_Shaikh/chapter3.ipynb @@ -0,0 +1,836 @@ +{ + "metadata": { + "celltoolbar": "Raw Cell Format", + "name": "", + "signature": "sha256:5f637d4fa0aa8bb3bc54a28134ac85a937c06f0d3a591f536de2719824a41f5c" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 3: Optical Fibre" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.1,Page number 3-19" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.61 #Core index\n", + "n2=1.55 #Cladding index\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(n1**2-n2**2) #Formula\n", + "\n", + "print\"Numerical Aperture of Fibre is = \",NA\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.435430821142\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.2,Page number 3-19" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.65 #Core index\n", + "n2=1.53 #Cladding index\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(n1**2-n2**2) #Formula\n", + "\n", + "print\"Numerical Aperture of Fibre is =\",NA\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.617737808459\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.3,Page number 3-19" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.48 #R.I. of Core\n", + "n2=1.39 #R.I. of Cladding\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(n1**2-n2**2) #Formula to find NA\n", + "phi=math.asin(NA)*180/(3.1472) #Acceptance angle\n", + "\n", + "print\"Numerical Aperture of Fibre is =\",NA\n", + "print\"Acceptance angle of Fibre is =\",phi,\"degrees\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.508232230383\n", + "Acceptance angle of Fibre is = 30.491727191 degrees\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.4,Page number 3-20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#given data:\n", + "u1=3.6 #Refractive Index of the Substance at 850 nm\n", + "u2=3.4 #Refractive Index of the Substance at 1300 nm\n", + "Vv=3*10**8 #Velocity of light in free space\n", + "\n", + "#Calculations:\n", + "# i)Finding wavelength at 850 nm\n", + "Vs1=Vv/u1 #Velocity of light in substance at 850 nm\n", + "print\"Velocity of light in substance at 850 nm =\" ,Vs1,\"m/sec\"\n", + "\n", + "lam1=850*10**-9/u1 #Wavelength of light in substance at 850nm\n", + "print\" Wavelength of light in substance at 850nm =\",lam1,\"m\"\n", + "\n", + "\n", + "#ii)Finding wavelength at 1300 nm\n", + "Vs2=Vv/u2 #Velocity of light in substance at 1300 nm\n", + "print\"Velocity of light in substance at 1300 nm =\",Vs2,\" m/sec\"\n", + "\n", + "lam2=1300*10**-9/u2 #Wavelength of light in substance at 1300nm\n", + "print\"Wavelength of light in substance at 1300nm =\" ,lam2,\"m \"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Velocity of light in substance at 850 nm = 83333333.3333 m/sec\n", + " Wavelength of light in substance at 850nm = 2.36111111111e-07 m\n", + "Velocity of light in substance at 1300 nm = 88235294.1176 m/sec\n", + "Wavelength of light in substance at 1300nm = 3.82352941176e-07 m \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.5,Page number 3-20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.5 #R.I. of Core\n", + "u2=1.45 #R.I.of Cladding\n", + "delta= (u1-u2)/u1 #Fractional Refractive index\n", + "\n", + "#Calculations:\n", + "NA=u1*sqrt(2*delta) #Formula to find NA\n", + "theta0=math.asin(NA)*180/(3.1472) #Acceptance angle\n", + "thetac=math.asin(u2/u1)*180/(3.1472) #Critical angle\n", + "\n", + "print\"Numerical Aperture of Fibre is =\",NA\n", + "print\"Acceptance angle of Fibre is =\",theta0,\"degrees\" \n", + "print\" Critical angle of Fibre is =\",thetac,\"degrees\" \n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.387298334621\n", + "Acceptance angle of Fibre is = 22.7458994397 degrees\n", + " Critical angle of Fibre is = 75.0309676099 degrees\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.6,Page number 3-20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "NA=0.22 # Numerical Aperture of Fibre\n", + "delta=0.012 #Fractional index\n", + "\n", + "#Calculations:\n", + "#Delta=(u1-u2)/u1\n", + "u1=NA/math.sqrt(2*delta) #Formula\n", + "u2=u1-(u1*delta) #Formula\n", + "\n", + "print\"Refractive Index of core of fibre is =\",u1\n", + "print\"Refractive Index of cladding of fibre is =\",u2\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Refractive Index of core of fibre is = 1.42009389361\n", + "Refractive Index of cladding of fibre is = 1.40305276689\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.7,Page number 3-21" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.466 #R.I. of Core\n", + "u2=1.46 #R.I.of Cladding\n", + "V=2.4 #Cut off parameter\n", + "lamda=0.8*10**-6 #wavelength in meter\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(u1**2-u2**2) #Formula to find Numerical Aperture\n", + "print\"Numerical Aperture of Fibre is =\",NA\n", + "#(printing mistake in book)printed answer is 1.13 but correct answer is 0.13\n", + "print\"(printing mistake in book)\"\n", + "\n", + "# V = 2*3.142*a*NA / lamda\n", + "a=V*lamda/(2*3.142*NA) #core radius\n", + "print\"Core radius of Fibre is (a) =\",a,\"m\"\n", + "\n", + "#w/a= 1.1\n", + "w=1.1*a #Spot size\n", + "print\"Spot size of Fibre is =\",w,\"m\"\n", + "\n", + "theta=2*lamda*180/3.142/(3.142*w) #Divergence angle\n", + "print\"Divergence angle of Fibre is =\",theta,\"degrees\"\n", + "\n", + "w10=lamda*10/(3.142*w) #Spot size at 10 m\n", + "print\"Spot size at 10 m of Fibre is =\",w10,\"m\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.1324990566\n", + "(printing mistake in book)\n", + "Core radius of Fibre is (a) = 2.30596263706e-06 m\n", + "Spot size of Fibre is = 2.53655890076e-06 m\n", + "Divergence angle of Fibre is = 11.5009886523 degrees\n", + "Spot size at 10 m of Fibre is = 1.00378073182 m\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.8,Page number 3-21" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "w=98 #Spot size in meter\n", + "d=50*10**-6 #Core diameter in meter\n", + "a=d/2 #core radius\n", + "u1=1.47 #R.I. of Core\n", + "u2=1.45 #R.I.of Cladding\n", + "lamda=0.85*10**-6 #Wavlength in meter\n", + "NA=math.sqrt(u1**2-u2**2) #Formula to find NA\n", + "\n", + "#Calculations:\n", + "V=2*3.142*a*NA/lamda #cut off parameter\n", + "N=(V**2)/2 #Number of modes\n", + "\n", + "print\"Cut off parameter of Fibre is =\",V\n", + "print\"Number of modes of Fibre is =\",N\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Cut off parameter of Fibre is = 44.6646240577\n", + "Number of modes of Fibre is = 997.464321107\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.9,Page number 3-21" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.47 #R.I. of Core\n", + "u2=1.46 #R.I.of Cladding\n", + "lamda=1.3*10**-6 #wavelength in meter\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(u1**2-u2**2) #Formula to find Numerical Aperture\n", + "\n", + "#The condition for single mode is V<2.405\n", + "#2*3.142*a*NA/lamda < 2.405\n", + "\n", + "a=2.405*lamda/(2*3.142*NA) #Maximum radius of fibre\n", + "\n", + "print\"Maximum radius of Fibre is =\",a,\"meter\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Maximum radius of Fibre is = 2.90662126448e-06 meter\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.10,Page number 3-22" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.465 #R.I. of Core\n", + "u2=1.46 #R.I.of Cladding\n", + "lamda=1.25*10**-6 #operating wavelength\n", + "\n", + "#Calculations:\n", + "delta=(u1-u2)/u1 #Fractional Refractive index\n", + "print\"Fractional Refractive index of Fibre is =\",delta\n", + "\n", + "#For single mode propagation codition is \n", + "# a/lamda < 1.4/(3.142*sqrt(u1(u1-u2)))\n", + "\n", + "a=lamda*1.4/(3.142*u1*math.sqrt(delta)) #core radius\n", + "\n", + "u=u1-(math.sqrt(2*delta)/(2*3.142*(a/lamda))) #effective refractive index\n", + "print\"Effective Refractive index for lowest mode propagation is =\",u\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Fractional Refractive index of Fibre is = 0.00341296928328\n", + "Effective Refractive index for lowest mode propagation is = 1.46247461864\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.11,Page number 3-22" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.54 #R.I. of Core\n", + "u2=1.5 #R.I.of Cladding\n", + "lamda=1.3*10**-6 #wavelength in meter\n", + "a=25*10**-6 #core radius in meter\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(u1**2-u2**2) #Formula to find Numerical Aperture\n", + "\n", + "V=2*3.142*a*NA/lamda #cut off parameter\n", + "print\"Cut off parameter of Fibre is =\",V\n", + "\n", + "N=(V**2)/2 #Number of modes\n", + "print\" Number of modes of Fibre is =\",N\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Cut off parameter of Fibre is = 42.1404937865\n", + " Number of modes of Fibre is = 887.910608284\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.11.1,Page number 3-25" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.52 #R.I. of Core\n", + "u2=1.5189 #R.I.of Cladding\n", + "lamda=1.3*10**-6 #wavelength in meter\n", + "d=29*10**-6 #core diameter in meter\n", + "a=d/2\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(u1**2-u2**2) #Formula to find Numerical Aperture\n", + "V=2*3.142*a*NA/lamda #Normalised frequency\n", + "Nm=(V**2)/2 #Number of modes\n", + "\n", + "print\"Normalised frequency of Fibre is (V)=\",V\n", + "print\"The Maximum Number of modes the Fibre will support is (Nm) =\",Nm\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Normalised frequency of Fibre is (V)= 4.05242861605\n", + "The Maximum Number of modes the Fibre will support is (Nm) = 8.2110888441\n" + ] + } + ], + "prompt_number": 11 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.12,Page number 3-22" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "u1=1.5 #R.I. of Core\n", + "d=10*10**-6 #diameter of core\n", + "a=d/2 #core radius\n", + "lamda=1.3*10**-6 #wavelength\n", + "V=2.405 #cut off parameter for single mode\n", + "\n", + "#Calculations:\n", + "\n", + "#We know, V=2*3.142*a*NA/lamda\n", + "NA=V*lamda/(2*3.142*a) #Numerical Aperture\n", + "\n", + "theta=math.asin(NA)*180/3.142 #Acceptance angle\n", + "print\"Acceptance angle of Fibre is =\",theta,\"Degrees\"\n", + "\n", + "#Also, NA=u1*sqrt(2*delta)\n", + "delta=(NA/u1)**2/2 #Fractional index\n", + "print\"Maximum Fractional Refractive index of Fibre is =\",delta\n", + "\n", + "#delta=(u1-u2)/u1\n", + "u2=u1*(1-delta) #R.I.of cladding\n", + "print\"Refractive index of cladding of Fibre is =\",u2\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Acceptance angle of Fibre is = 5.71002346964 Degrees\n", + "Maximum Fractional Refractive index of Fibre is = 0.00220035113094\n", + "Refractive index of cladding of Fibre is = 1.4966994733\n" + ] + } + ], + "prompt_number": 13 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.13,Page number 3-23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.5 #R.I. of core\n", + "delta=0.0005 #Fractional index difference\n", + "\n", + "#Calculations:\n", + "#(a):\n", + "#Delta=(u1-u2)/u1\n", + "n2=n1-(n1*delta) #R.I. of cladding\n", + "print\"(a)Refractive Index of cladding of fibre is =\",n2\n", + "\n", + "#(b):\n", + "phi=math.asin(n2/n1)*180/3.142 #Critical internal reflection angle\n", + "print\"(b)Critical internal reflection angle of Fibre is =\",phi,\"degrees\"\n", + "\n", + "#(c):\n", + "theta0=math.asin(math.sqrt(n1**2-n2**2))*180/3.142 #External critical Acceptance angle\n", + "print\"(c)External critical Acceptance angle of Fibre is =\",theta0,\"degrees\"\n", + "\n", + "#(d):\n", + "NA=n1*math.sqrt(2*delta) #Formula to find Numerical Aperture\n", + "print\"(d)Numerical Aperture of Fibre is =\",NA\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(a)Refractive Index of cladding of fibre is = 1.49925\n", + "(b)Critical internal reflection angle of Fibre is = 88.1766396681 degrees\n", + "(c)External critical Acceptance angle of Fibre is = 2.71810509125 degrees\n", + "(d)Numerical Aperture of Fibre is = 0.0474341649025\n" + ] + } + ], + "prompt_number": 14 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.14,Page number 3-24" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "NA1=0.20 #Numerical Aperture of Fibre\n", + "n2=1.59 #R.I. of cladding\n", + "\n", + "#Calculations:\n", + "#NA=sqrt(n1**2-n2**2)\n", + "#In air, n0=1\n", + "n1=math.sqrt(NA1**2+n2**2) #R.I.of core\n", + "\n", + "#Now, in water \n", + "n0=1.33\n", + "NA2=math.sqrt(n1**2-n2**2)/n0 #Numerical Aperture in water\n", + "theta0=math.asin(NA2)*180/3.142 #Acceptance angle of fibre in water\n", + "print\"Acceptance angle of Fibre in water is =\",theta0,\"degrees\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Acceptance angle of Fibre in water is = 8.6475921767 degrees\n" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.15,Page number 3-24" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.45 #R.I.of core\n", + "n2=1.40 #R.I. of cladding\n", + "\n", + "#Calculations:\n", + "NA=math.sqrt(n1**2-n2**2) #Numerical Aperture\n", + "print\"Numerical Aperture of Fibre is =\",NA\n", + "\n", + "theta0=math.asin(NA)*180/3.142 #Acceptance angle of fibre\n", + "print\"Acceptance angle of Fibre is =\",theta0,\"degrees\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.377491721764\n", + "Acceptance angle of Fibre is = 22.1755250876 degrees\n" + ] + } + ], + "prompt_number": 16 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.16,Page number 3-24" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "NA=0.16 #Numerical Aperture of Fibre\n", + "n1=1.45 #R.I. of core\n", + "d=90*10**-6 #Core diameter\n", + "\n", + "#Calculations:\n", + "#NA=sqrt(n1**2-n2**2)\n", + "n2=math.sqrt(n1**2-NA**2) #R.I.of cladding\n", + "print\"(a)Refractive Index of cladding of fibre is =\",n2\n", + "\n", + "theta0=math.asin(NA)*180/3.142 #Acceptance angle of fibre\n", + "print\"(b)Acceptance angle of Fibre is =\",theta0,\"degrees\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(a)Refractive Index of cladding of fibre is = 1.44114537782\n", + "(b)Acceptance angle of Fibre is = 9.20570258795 degrees\n" + ] + } + ], + "prompt_number": 18 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3.17,Page number 3-25" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "\n", + "#Given Data:\n", + "n1=1.48 #R.I. of core\n", + "delta=0.055 #Realtive R.I.\n", + "lamda=1*10**-6 #Wavelength of light\n", + "a=50*10**-6 #core radius\n", + "\n", + "#Calculations:\n", + "#Delta=(u1-u2)/u1\n", + "n2=n1-(n1*delta) #R.I. of cladding\n", + "NA=n1*math.sqrt(2*delta) #Formula to find Numerical Aperture\n", + "print\"Numerical Aperture of Fibre is =\",NA\n", + "\n", + "\n", + "theta0=math.asin(NA)*180/3.142 #Acceptance angle of fibre\n", + "print\"Acceptance angle of Fibre is =\",theta0,\"degrees\"\n", + "\n", + "V=2*3.142*a*NA/lamda #V number\n", + "N=(V**2)/2 #Number of guided modes\n", + "\n", + "#In book,instead of NA , value of delta is taken into calculation.\n", + "#Thus there is calculation mistake in values of V and N.\n", + "\n", + "print\"V number of Fibre is =\",V\n", + "print\"Number of guided mode of Fibre is =\",N\n", + "print\"(Calculation mistake in book)\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Numerical Aperture of Fibre is = 0.490860468973\n", + "Acceptance angle of Fibre is = 29.3933421943 degrees\n", + "V number of Fibre is = 154.228359351\n", + "Number of guided mode of Fibre is = 11893.1934141\n", + "(Calculation mistake in book)\n" + ] + } + ], + "prompt_number": 19 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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