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diff --git a/Analog_Integrated_Circuits_by_R.S._Tomar/Chapter2_1.ipynb b/Analog_Integrated_Circuits_by_R.S._Tomar/Chapter2_1.ipynb new file mode 100755 index 00000000..415497af --- /dev/null +++ b/Analog_Integrated_Circuits_by_R.S._Tomar/Chapter2_1.ipynb @@ -0,0 +1,531 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:08f6666963b63d68f1720253f0e8a698e5752723f4515bbc0a7b3ce6b79e7e0a" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter2 - Differential amplifiers" + ] + }, + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Ex 2.1 - page 31" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "v1=7 #mV\n", + "v2=9 #mV\n", + "Ad=80 #dB\n", + "CMRR=90 #dB\n", + "vid=v2-v1 #mV\n", + "vcm=(v1+v2)/2 #mV\n", + "Ad=10**(Ad/20) #unitless\n", + "CMRR=10**(CMRR/20) #unitless\n", + "vout=Ad*(vid+vcm/CMRR)/1000 #V\n", + "print \"Output Voltage is %0.2f V\" %vout" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Output Voltage is 20.00 V\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.2 - page 31" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "v1=50.0 #micro V\n", + "v2=55.0 #micro V\n", + "Ad=2*10**5 #unitless\n", + "CMRR=80 #dB\n", + "vid=v2-v1 #micro V\n", + "vcm=(v1+v2)/2 #mV\n", + "CMRR=10**(CMRR/20) #unitless\n", + "vout=Ad*(vid+vcm/CMRR)/10**6 #V\n", + "print \"Output Voltage is %0.3f V\" %vout \n", + "Verror=vout-Ad*vid/10**6 #V\n", + "print \"Error Voltage is %0.3f V\" %Verror\n", + "error_p=(Verror/vout)*100 #% error\n", + "print \"Percentage error is %0.3f %%\" %error_p \n", + "#Percentage error answer is not correct in the book." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Output Voltage is 1.001 V\n", + "Error Voltage is 0.001 V\n", + "Percentage error is 0.105 %\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.3 - page 38" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "IT=1.0 #mA\n", + "VCC=15 #V\n", + "RE=50 #kohm\n", + "RC=15 #kohm\n", + "Beta=120 #unitless\n", + "alfa=Beta/(Beta+1) #unitless\n", + "Vid=6 #mV\n", + "VT=26 #mV\n", + "#Part (a)\n", + "iC1=alfa*IT/(1+math.exp(-Vid/VT)) #mA\n", + "iC2=IT-iC1 #mA\n", + "print \"dc Collector current through transistors is %0.3f mA\" %iC2 \n", + "#Part (b)\n", + "iC=IT/2 #mA(let iC1=iC2=iC)\n", + "re=VT/iC #ohm(let re1=re2=re)\n", + "Ad=-RC*1000/re #unitless\n", + "Acm=-RC*1000/(re+2*RE*1000) #unitless\n", + "Acm=abs(Acm) ##unitless\n", + "CMRR=abs(Ad/Acm) ##unitless\n", + "print \"Ad is %0.2f\" %Ad \n", + "print \"Acm is %0.2f \" %Acm \n", + "CMRR=20*math.log10(CMRR) #dB\n", + "print \"CMRR is %0.1f dB\" %CMRR" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "dc Collector current through transistors is 0.447 mA\n", + "Ad is -288.46\n", + "Acm is 0.15 \n", + "CMRR is 65.7 dB\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.4 - page 44" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "RC=2 #kohm\n", + "RE=4.3 #kohm\n", + "VEE=5 #V\n", + "VBE=0.7 #V\n", + "IT=(VEE-VBE)/RE #mA\n", + "VT=26 #mV\n", + "re=2*VT/IT #ohm\n", + "Ad=-RC*1000/2/re #unitless\n", + "print \"Ad = \",round(Ad,2) \n", + "Acm=-RC*1000/(re+2*RE*1000) #unitless\n", + "print \"Acm = \",round(Acm,2)\n", + "CMRR=abs(Ad/Acm) ##unitless\n", + "print \"CMRR = \",round(CMRR,1)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Ad = -19.23\n", + "Acm = -0.23\n", + "CMRR = 83.2\n" + ] + } + ], + "prompt_number": 11 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.5 - page 45" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=100 #unitless\n", + "VBE=0.715 \n", + "VD1=0.715 #V\n", + "VZ=6.2 #V\n", + "VT=26 #mV\n", + "IZt=41 #mA\n", + "VCC=10 #V\n", + "VEE=10 #V\n", + "RE=2.7 #kohm\n", + "RC=4.7 #kohm\n", + "VB=-VEE+VZ+VD1 #V\n", + "VE=VB-VBE #V\n", + "IE3=(VE-(-VEE))/(RE) #mA\n", + "IT=IE3 #mA\n", + "ICQ=IT/2 #mA(let ICQ1=ICQ2=ICQ)\n", + "VCEQ=VCC+VBE-ICQ*RC #V\n", + "#Q=[ICQ,VCEQ] #[mA V](Q point)\n", + "print \"Q point (ICQ(mA), VCEQ(V)), ICQ is \",round(ICQ,2),\"mA & VCEQ is \",round(VCEQ,2),\"V\"\n", + "re=2*VT/IT #ohm\n", + "Ad=-RC*1000/re #unitless\n", + "Rid=2*Beta*re/1000 #kohm\n", + "print \"Ad = \",round(Ad)\n", + "print \"Rid is %0.2f kohm\" %Rid" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q point (ICQ(mA), VCEQ(V)), ICQ is 1.15 mA & VCEQ is 5.32 V\n", + "Ad = -208.0\n", + "Rid is 4.53 kohm\n" + ] + } + ], + "prompt_number": 13 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.6 - page 47" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=100 #unitless\n", + "VBE=0.7 #V\n", + "VCC=10 #V\n", + "VEE=10 #V\n", + "VT=26 #mV\n", + "RC=2.7 #kohm\n", + "R=2.2 #kohm\n", + "IExt=(VEE-VBE)/R #mA\n", + "IC3=IExt \n", + "IT=IExt #mA\n", + "ICQ=IT/2 #mA\n", + "re=2*VT/IT #ohm(let re1=re2=re)\n", + "Ad=-RC*1000/re #unitless\n", + "Rid=2*Beta*re/1000 #kohm(let Rid1=Rid2=Rid)\n", + "print \"Differntial mode gain, Ad = \", round(Ad,1) \n", + "print \"Differntial input resistance, Rid is %0.2f kohm\" %Rid" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Differntial mode gain, Ad = -219.5\n", + "Differntial input resistance, Rid is 2.46 kohm\n" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.7 - page 49" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=100 #unitless\n", + "VBE=0.7 #V\n", + "VD1=0.7 #V\n", + "VD2=0.7#V\n", + "VCC=15 #V\n", + "VEE=15 #V\n", + "VT=26 #mV\n", + "RE=560 #ohm\n", + "RC=6.8 #kohm\n", + "R=220 #ohm\n", + "VB=-VEE+VD1+VD2 #V\n", + "VE=VB-VBE #V\n", + "IE3=(VE-(-VEE))/RE*1000 #mA\n", + "IT=IE3 #mA\n", + "ICQ=IT/2 #mA\n", + "VCEQ=VCC+VBE-ICQ*RC #V\n", + "#Q=[ICQ VCEQ] #[mA V](Q point)\n", + "print \"Q point (ICQ(mA), VCEQ(V)), ICQ is \",round(ICQ,3),\"mA & VCEQ is \",round(VCEQ,2),\"V\"\n", + "re=2*VT/IT #ohm\n", + "Ad=-RC*1000/re #unitless\n", + "print \"Differntial mode gain, Ad = \",round(Ad,2) \n", + "#Answer in the book is wrong for Q point." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q point (ICQ(mA), VCEQ(V)), ICQ is 0.625 mA & VCEQ is 11.45 V\n", + "Differntial mode gain, Ad = -163.46\n" + ] + } + ], + "prompt_number": 17 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.8 - page 50" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "ICQ=200.0 #micro A\n", + "Beta=1000.0 #unitless\n", + "Ad=180.0 #unitless\n", + "CMRR=80.0 #dB\n", + "VT=26.0 #mV\n", + "re=VT/(ICQ/1000) #ohm(Let re=re1=re2)\n", + "RC=Ad*re/1000 #kohm\n", + "CMRR=10**(CMRR/20) #untless\n", + "RE=(CMRR-1)*re/2/1000 #kohm\n", + "print \"Value of RC is %0.2f kohm & RE is %0.f kohm\" %(RC,RE) \n", + "Rid=2*Beta*re/1000 #kohm(Let Rid=Rid1=Rid2)\n", + "print \"Differntial input resistance, Rid is %0.f kohm \" %Rid \n", + "Ric=(Beta+1)*(re+2*RE*1000)/10**6 #Mohm\n", + "print \"Common mode input resistance, Ric is %0.f Mohm \" %Ric\n", + "#Answer for last part is wrong in the textbook." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Value of RC is 23.40 kohm & RE is 650 kohm\n", + "Differntial input resistance, Rid is 260 kohm \n", + "Common mode input resistance, Ric is 1301 Mohm \n" + ] + } + ], + "prompt_number": 22 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.9 - page 51" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=110 #unitless\n", + "VBE=0.7 #V\n", + "VT=26 #mV\n", + "VCC=10 #V\n", + "VEE=10 #V\n", + "RC=1.8 #kohm\n", + "R=3.9 #kohm\n", + "IExt=(VCC-VBE-(-VEE))/R #mA\n", + "IT=IExt #mA\n", + "ICQ=IT/2 #mA\n", + "V1=0 \n", + "V2=0 #V\n", + "VE=-2*VBE #V\n", + "VC=VCC-ICQ*RC #V\n", + "VCEQ=VC-VE #V\n", + "# Q=[ICQ VCEQ] #[mA V](Q point)\n", + "print \"Q point (ICQ(mA), VCEQ(V)), ICQ is \",round(ICQ,2),\"mA & VCEQ is \",round(VCEQ,2),\"V\"\n", + "re=2*VT/IT #ohm(let re1=re2=re)\n", + "reD=2*re #ohm\n", + "Ad=-RC*1000/reD #unitless\n", + "print \"Differntial mode gain, Ad = \",round(Ad,1) \n", + "BetaD=Beta**2 #unitless\n", + "Rid=2*BetaD*reD/1000 #kohm(let Rid1=Rid2=Rid)\n", + "print \"Differntial input resistance, Rid is %0.1f kohm\" %Rid\n", + "#Answer for Ad is wrong(+ve) in the book while it is negative." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Q point (ICQ(mA), VCEQ(V)), ICQ is 2.47 mA & VCEQ is 6.95 V\n", + "Differntial mode gain, Ad = -85.7\n", + "Differntial input resistance, Rid is 508.6 kohm\n" + ] + } + ], + "prompt_number": 25 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.10 - page 54" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=100 #unitless\n", + "VBE=0.7 #V\n", + "R=18.6 #kohm\n", + "VT=26 #mV\n", + "VCC=5 #V\n", + "VEE=5 #V\n", + "IExt=(VCC-VBE-(-VEE))/R #mA\n", + "IT=IExt #mA\n", + "re=2*VT/IT #ohm(let re1=re2=re)\n", + "Rid=2*Beta*re/1000 #kohm(let Rid1=Rid2=Rid)\n", + "print \"Differntial input resistances, Rid1=Rid2 is %0.1f kohm\" %Rid" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Differntial input resistances, Rid1=Rid2 is 20.8 kohm\n" + ] + } + ], + "prompt_number": 27 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex 2.11 - page 55" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "Beta=100 #unitless\n", + "VBE=0.7 #V\n", + "RC=2.7 #kohm\n", + "R=2.2 #kohm\n", + "VT=26 #mV\n", + "VCC=10 #V\n", + "VEE=10 #V\n", + "IExt=(VEE-VBE)/R #mA\n", + "IT=IExt #mA\n", + "IE=IT/2 #mA(Let IE1=IE2=IE)\n", + "re=2*VT/IT \n", + "re1=re #ohm \n", + "re2=re #ohm \n", + "re3=re #ohm\n", + "re4=re #ohm\n", + "reD=re1+re2 #ohm\n", + "BetaD=Beta**2 #unitless\n", + "Ad=-RC*1000/reD #unitless\n", + "print \"Differential voltage gain, Ad = \",round(Ad,2)\n", + "Rid=2*BetaD*reD/1000 #kohm(let Rid1=Rid2=Rid)\n", + "print \"Differntial input resistances, Rid1=Rid2 is %0.2f kohm \" %Rid \n", + "#Answer in the book is not accurate." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Differential voltage gain, Ad = -109.75\n", + "Differntial input resistances, Rid1=Rid2 is 492.04 kohm \n" + ] + } + ], + "prompt_number": 28 + } + ], + "metadata": {} + } + ] +}
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