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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 7: Solid State"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 1, Page no: 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Solution\n",
+ "print \"Weiss indices \\t\\t\\t1/2, 2/3, infinity \\t2/3, 2, 1/3\"\n",
+ "print \"Reciprocal of Weiss indices 2, 3/2, 1/infinity \\t3/2, 1/2, 3\"\n",
+ "print \"Clear fractions\\t\\t\\t4, 3, 0 \\t3, 1, 6\"\n",
+ "print \"Miller indices \\t\\t\\t (430) \\t (316)\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Weiss indices \t\t\t1/2, 2/3, infinity \t2/3, 2, 1/3\n",
+ "Reciprocal of Weiss indices 2, 3/2, 1/infinity \t3/2, 1/2, 3\n",
+ "Clear fractions\t\t\t4, 3, 0 \t3, 1, 6\n",
+ "Miller indices \t\t\t (430) \t (316)\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 2, Page no: 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from math import sqrt\n",
+ "\n",
+ "\n",
+ "# Variable\n",
+ "a = 450 # pm\n",
+ "\n",
+ "# Solution\n",
+ "d220 = a / sqrt(2 ** 2 + 2 ** 2 + 0)\n",
+ "print \"Interplanar spacing\", int(d220)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Interplanar spacing 159\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 3, Page no: 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Solution\n",
+ "print \"Intercept \\t(a, b ,c)\\t\\t(a, 2b, c) \\t\\t(a, 2b, 2c) \\t\\t(infi, b, -c)\"\n",
+ "print \"Weiss indices\\t 1, 1, 1 \\t\\t 1, 2, 1 \\t\\t 1, 2, 2 \\t\\t infi, 1, -1\"\n",
+ "print \"Reciprocals \\t 1, 1, 1 \\t\\t 1, 1/2, 1 \\t\\t 1, 1/2, 1/2\\t\\t 0, 1, -1\"\n",
+ "print \"Miller indicec\\t (111) \\t\\t (212) \\t\\t (211) \\t\\t (011)\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Intercept \t(a, b ,c)\t\t(a, 2b, c) \t\t(a, 2b, 2c) \t\t(infi, b, -c)\n",
+ "Weiss indices\t 1, 1, 1 \t\t 1, 2, 1 \t\t 1, 2, 2 \t\t infi, 1, -1\n",
+ "Reciprocals \t 1, 1, 1 \t\t 1, 1/2, 1 \t\t 1, 1/2, 1/2\t\t 0, 1, -1\n",
+ "Miller indicec\t (111) \t\t (212) \t\t (211) \t\t (011)\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 4, Page no: 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Variables\n",
+ "rNa = 0.98 * 10 ** - 10 # m\n",
+ "rCl = 1.81 * 10 ** - 10 # m\n",
+ "\n",
+ "# Solution\n",
+ "rr = rNa / rCl\n",
+ "print \"When the radius ration is\", \"{:.2f}\".format(rr),\n",
+ "print \", the coordination number is 6.\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "When the radius ration is 0.54 , the coordination number is 6.\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 5, Page no: 210"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Variables\n",
+ "rLi = 68 # pm\n",
+ "rF = 136. # pm\n",
+ "\n",
+ "# Solution\n",
+ "rr = rLi / rF\n",
+ "print \"Radius ratio =\", rr\n",
+ "print \"The structure of LiF is scc and C.N of Li+ = 6\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Radius ratio = 0.5\n",
+ "The structure of LiF is scc and C.N of Li+ = 6\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 6, Page no: 210"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from math import sin\n",
+ "\n",
+ "\n",
+ "# Variables\n",
+ "lamda = 2 * 10 ** - 10 # m\n",
+ "theta = 30 # degrees\n",
+ "\n",
+ "# Solution\n",
+ "print \"For first-order reflection\"\n",
+ "d = lamda / (2 * sin(theta))\n",
+ "dist = 2 * d\n",
+ "print \"Hence, distance between planes is\", \"{:.0e}\".format(abs(dist)), \"m\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For first-order reflection\n",
+ "Hence, distance between planes is 2e-10 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 7, Page no: 210"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from math import sqrt\n",
+ "\n",
+ "\n",
+ "# Variables\n",
+ "r = 174.6 # pm\n",
+ "\n",
+ "# Solution\n",
+ "a = r * sqrt(8)\n",
+ "print \"For 200 plane: h = 2, k = 0, l = 0\"\n",
+ "d200 = a / sqrt(2 ** 2)\n",
+ "print \"d200 =\", \"{:.1f}\".format(d200), \"pm\"\n",
+ "print \"For 200 plane: h = 2, k = 2, l = 0\"\n",
+ "d220 = a / sqrt(2 ** 2 + 2 ** 2)\n",
+ "print \"d220 =\", d220, \"pm\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For 200 plane: h = 2, k = 0, l = 0\n",
+ "d200 = 246.9 pm\n",
+ "For 200 plane: h = 2, k = 2, l = 0\n",
+ "d220 = 174.6 pm\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 8, Page no: 210"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Constant\n",
+ "N = 6.023 * 10 ** 23\n",
+ "\n",
+ "# Variables\n",
+ "wt = 55.6\n",
+ "p = 0.29 # nm\n",
+ "n = 2\n",
+ "\n",
+ "# Solution\n",
+ "print \"For BCC pattern,\"\n",
+ "print \"number of atoms per unit cell = 2\"\n",
+ "d = n * (wt * 10 ** -3) / (N * (p * 10 ** - 9) ** 3)\n",
+ "print \"Density of the metal is\", \"{:.2e}\".format(d), \"kg / m^3\"\n",
+ "print \"Number of nearest enighbour for BCC = 8\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For BCC pattern,\n",
+ "number of atoms per unit cell = 2\n",
+ "Density of the metal is 7.57e+03 kg / m^3\n",
+ "Number of nearest enighbour for BCC = 8\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 9, Page no: 210"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Solution\n",
+ "print \"Intercept \\t2a/2, 2b, c/3\"\n",
+ "print \"Weiss indices\\t1, 2, 1/3\"\n",
+ "print \"Reciprocals \\t1, 1/2, 3\"\n",
+ "print \"Miller indices\\t (216)\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Intercept \t2a/2, 2b, c/3\n",
+ "Weiss indices\t1, 2, 1/3\n",
+ "Reciprocals \t1, 1/2, 3\n",
+ "Miller indices\t (216)\n"
+ ]
+ }
+ ],
+ "prompt_number": 19
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 10, Page no: 211"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Constant\n",
+ "N = 6.023 * 10 ** 23\n",
+ "\n",
+ "# Variables\n",
+ "D = 0.53 # g / cm ^ 3\n",
+ "MM = 6.94 # g / mol\n",
+ "n = 2\n",
+ "\n",
+ "# Solution\n",
+ "print \"For BCC pattern,\"\n",
+ "print \"number of atoms per unit cell = 2\"\n",
+ "V = D * N / (n * MM)\n",
+ "V = 1 / V\n",
+ "print \"Volume of a unit cell of lithium metal is\", \"{:.2e}\".format(V), \"cc\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For BCC pattern,\n",
+ "number of atoms per unit cell = 2\n",
+ "Volume of a unit cell of lithium metal is 4.35e-23 cc\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 11, Page no: 211"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from math import sqrt\n",
+ "\n",
+ "\n",
+ "print \"AB remain in BCC structure if the edge length is a then body diagonal\",\n",
+ "print \"is root(3)a\"\n",
+ "print \"root(3)a = 2(r+ + r-)\"\n",
+ "A = (sqrt(3) * 0.4123 - 2 * 0.81) / 2\n",
+ "print \"A+ =\", \"{:.2f}\".format(A), \"nm\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "AB remain in BCC structure if the edge length is a then body diagonal is root(3)a\n",
+ "root(3)a = 2(r+ + r-)\n",
+ "A+ = -0.45 nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 25
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file
generated by cgit (git 2.34.1) at 2024-12-20 07:46:19 +0000