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-{
- "metadata": {
- "name": "",
- "signature": "sha256:5389b8ee7db605c2b6709900953f8acf2763d42f0399c64611452653d4ee8704"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "UNIT-4:Electrostatics"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.1,Page no:103"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "q=1.0 #no of coulomb\n",
- "e=1.6*10**-19 #charge on an electron\n",
- "\n",
- "#Calculation\n",
- "n=(q/e) #calculating no of electrons\n",
- "\n",
- "#Result\n",
- "print\"No of electrons =\",n\n",
- "print\"NOTE:Calculation mistake in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "No of electrons = 6.25e+18\n",
- "NOTE:Calculation mistake in book\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.2,Page no:103"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "g=9.8\n",
- "m=4.5 #Massin [kg]\n",
- "r=0.03 #radius in [m]\n",
- "\n",
- "#Calculation\n",
- "F=m*g #in Newton\n",
- "q=math.sqrt(((r**2)*m*g)/(9*10**9)) #calculating q using F=(1/4*3.14*eo)*((q1*q2)/(r**2))\n",
- "\n",
- "#Result\n",
- "print\"Charge = \",q,\"C\"\n",
- "print\"\\nNOTE:Calculation mistake in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge = 2.1e-06 C\n",
- "\n",
- "NOTE:Calculation mistake in book\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.3,Page no:103"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "q1=2*10**-7 #charge in C\n",
- "q2=3*10**-7 #charge in C\n",
- "r=30*10**-2 #r in m\n",
- "\n",
- "#Calculation\n",
- "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
- "\n",
- "#Result\n",
- "print\"Force = %.e\"%F,\"N\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Force = 6e-03 N\n"
- ]
- }
- ],
- "prompt_number": 70
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.4,Page no:104"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "q1=1 #charge in C\n",
- "q2=1 #charge in C\n",
- "r=1 #r in m\n",
- "\n",
- "#Calculation\n",
- "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
- "\n",
- "#Result\n",
- "print\"Force = %.e\"%F,\"N\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Force = 9e+09 N\n"
- ]
- }
- ],
- "prompt_number": 71
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.5,Page no:104"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "m=9*10**-31 #mass of electron in kg\n",
- "q=-3.2*10**-7 #charge in C\n",
- "e=-1.6*10**-19 #charge on electron in C\n",
- "\n",
- "#Calculation\n",
- "n=(q/e) #calculating n\n",
- "M=n*m #calculating mass transfered\n",
- "\n",
- "#Result\n",
- "print\"(a):No. of electrons = \",n\n",
- "print\"(b):Mass transfered to polythene= \",M,\"kg\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a):No. of electrons = 2e+12\n",
- "(b):Mass transfered to polythene= 1.8e-18 kg\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.6,Page no:105"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "q1=1.6*10**-19 #charge in C\n",
- "q2=-1.6*10**-19 #charge in C\n",
- "r=10**-9 #r in m\n",
- "\n",
- "#Calculation\n",
- "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n",
- "\n",
- "#Result\n",
- "print\"Force=\",F,\"N\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Force= -2.304e-10 N\n"
- ]
- }
- ],
- "prompt_number": 54
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.7,Page no:110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "Va=-10 #voltage in volts\n",
- "W=100 #work in Joule\n",
- "q=2 #charge in Coulomb\n",
- "\n",
- "#Calculation\n",
- "v=(Va)+(W/q) #calculating v\n",
- "\n",
- "#Result\n",
- "print\"Voltage = \",v,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage = 40 V\n"
- ]
- }
- ],
- "prompt_number": 55
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.8,Page no:111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "eo=(8.854*10**-12) #constant\n",
- "E=2 #magnitude of electric field in N/C\n",
- "r=0.5 #r in m\n",
- "\n",
- "#Calculation\n",
- "q=E*4*(math.pi)*(eo)*(r**2) #calculating charge\n",
- "\n",
- "#Result\n",
- "print\"Charge= %.2e\"%q,\"C\"\n",
- "print\"\\nNOTE:Calcualtion mistake in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge= 5.56e-11 C\n",
- "\n",
- "NOTE:Calcualtion mistake in book\n"
- ]
- }
- ],
- "prompt_number": 73
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.9,Page no:111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "e=-1.6*10**-19 #charge on electron in Coulomb\n",
- "q=20*10**-6 #charge in Coulomb\n",
- "r1=0.1 #r1 in m\n",
- "r2=0.05 #r2 in m\n",
- "\n",
- "#Calculation\n",
- "Va=9*10**9*(q/r1) #calculating voltage at A\n",
- "Vb=9*10**9*(q/r2) #calculating voltage at B\n",
- "V=Va-Vb #potential difference\n",
- "W=V*e #calculating work done in joule\n",
- "\n",
- "#Result\n",
- "print\"Work done to take the electron from A to B = \",W,\"Joule\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Work done to take the electron from A to B = 2.88e-13 Joule\n"
- ]
- }
- ],
- "prompt_number": 69
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.10,Page no:112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "q1=(2.0*10**-8) #charge in coulomb\n",
- "q2=(-2.0*10**-8) #charge in coulomb\n",
- "q3=(3.0*10**-8) #charge in coulomb\n",
- "q4=(6.0*10**-8) #charge in coulomb\n",
- "s=1.0 #side in m\n",
- "\n",
- "#Calculation\n",
- "V=(9.0*10**9)*(1.0/s)*(q1+q2+q3+q4) #calculating voltage\n",
- "\n",
- "#Result\n",
- "print\"Voltage in Volts = \",V,\"Volts\"\n",
- "print\"\\nNOTE:Calculation mistake in book\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage in Volts = 810.0 Volts\n",
- "\n",
- "NOTE:Calculation mistake in book\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.11,Page no:123"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "eo=8.85*10**-12 #constant\n",
- "q=2*10**-6 #charge in coulomb\n",
- "l=9 #length in cm\n",
- "\n",
- "#Calculation\n",
- "fi=(q/eo) #calcualting flux in (N m square)/c\n",
- "\n",
- "#Result\n",
- "print\"Flux through the surface=%2e\"%fi,\"N m^2/c\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Flux through the surface=2.259887e+05 N m^2/c\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.12,Page no:124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "eo=8.85*10**-12 #constant\n",
- "r=1.2 #r in m\n",
- "t=80*10**-6 #surface sharge density in c/m square\n",
- "\n",
- "#Calculation\n",
- "q=t*4*(math.pi)*(r**2) #calculating charge\n",
- "fi=q/eo #calculating flux\n",
- "\n",
- "#Result\n",
- "print\"Flux=%g\"%fi,\"N c^-1 m^2\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Flux=1.63576e+08 N c^-1 m^2\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.13,Page no:124"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "eo=8.85*10**-12 #constant\n",
- "E=9*10**4 #Electric field in N/C\n",
- "r=2*10**-2 #r in m\n",
- "\n",
- "#Calculation\n",
- "L=2*(math.pi)*E*eo*r #calculating linear charge density\n",
- "\n",
- "#Result\n",
- "print\"Linear charge density = \",round(L,7),\"cm^-1\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Linear charge density = 1e-07 cm^-1\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.14,Page no:125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "o=17*10**-22 #surface charge density in cm**-2\n",
- "eo=8.85*10**-12 #constant\n",
- "\n",
- "#Calculation\n",
- "E=o/eo #calculating electric intensity in region III\n",
- "\n",
- "#Result\n",
- "print\"Electric Intensity in regions I and II = 0\" \n",
- "print\"Electric Intensity in region III = \",round(E,12),\"N/C\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric Intensity in regions I and II = 0\n",
- "Electric Intensity in region III = 1.92e-10 N/C\n"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.15,Page no:125"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "r=0.05 # in m\n",
- "eo=8.85*10**-12 #constant\n",
- "q=10.0**-9 #charge at point P in Coulomb\n",
- "\n",
- "#Calculation\n",
- "E=q/(4*(math.pi)*eo*(r**2)) #calculating electric field\n",
- "r1=0.2 #in m\n",
- "V1=q/(4*(math.pi)*eo*r1) #calculating potential difference\n",
- "\n",
- "#Result\n",
- "print\"Electric field= \",round(E),\"v/m\"\n",
- "print\"\\nNOTE:Approximate answer is calculated in book\\n\\n\"\n",
- "print\"Potential difference between two points = \",round(V1),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric field= 3597.0 v/m\n",
- "\n",
- "NOTE:Approximate answer is calculated in book\n",
- "\n",
- "\n",
- "Potential difference between two points = 45.0 V\n"
- ]
- }
- ],
- "prompt_number": 65
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.16,Page no:126"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "eo=8.85*10**-12 #constant\n",
- "o=80.0*10**-6 #surface charge density in c/ square\n",
- "r=1.2 #in m\n",
- "\n",
- "#Calculation\n",
- "q=o*(math.pi)*(r**2) #calculating charge in Coulomb\n",
- "fi=q/eo #calculating electric flux\n",
- "\n",
- "#Result\n",
- "print\"Charge= \",q,\"C\"\n",
- "print\"Electric flux = \",fi,\"N m^2/c\"\n",
- "print\"\\nNOTE:Wrong answers in book\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge= 0.000361911473694 C\n",
- "Electric flux = 40893951.8298 N m^2/c\n",
- "\n",
- "NOTE:Wrong answers in book\n",
- "\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.17,Page no:138"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "V=250 #potential difference in Volt\n",
- "C=10**-11 #capacitance in farad\n",
- "\n",
- "#Calculation\n",
- "q=C*V #calculating charge\n",
- "\n",
- "#Result\n",
- "print\"Charge = \",q,\"C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge = 2.5e-09 C\n"
- ]
- }
- ],
- "prompt_number": 68
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.18,Page no:138"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "r=6.4*10**6 #in m\n",
- "\n",
- "#Calculation\n",
- "C=r/(9*10**9) #calculating charge\n",
- "\n",
- "#Result\n",
- "print\"Capacitance = \",round(C*10**6),\"mu F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance = 711.0 mu F\n"
- ]
- }
- ],
- "prompt_number": 67
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.19,Page no:138"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "C=2 #capacitance in Farad\n",
- "d=0.5*10**-2 #distance in m\n",
- "eo=8.85*10**-12 #constant\n",
- "\n",
- "#Calculation\n",
- "A=(C*d)/(eo) #calculating area\n",
- "\n",
- "#Result\n",
- "print\"Area=%.2e\"%A,\"m^2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Area=1.13e+09 m^2\n"
- ]
- }
- ],
- "prompt_number": 66
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.20,Page no:139"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "import math \n",
- "\n",
- "#Variable declaration\n",
- "A=0.02 #area in m square\n",
- "r=0.5 #r in m\n",
- "\n",
- "#Calculation\n",
- "d=(A/(4*(math.pi)*r)) #calculating distance\n",
- "\n",
- "#Result\n",
- "print\"Distance between the plates = \",round(d*1000,2),\"mm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Distance between the plates = 3.18 mm\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.21,Page no:139"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "eo=8.85*10**-12 #constant\n",
- "A=1 #area in m square\n",
- "d=2*10**-3 #r in m\n",
- "K=4 #constant\n",
- "\n",
- "#Calculation\n",
- "C=(K*eo*A)/d #calculating capacitance\n",
- "\n",
- "#Result\n",
- "print\"Capacitance = \",C,\"Farad\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance = 1.77e-08 Farad\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.22,Page no:140"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "cm=10*10**-6 #capacitance in Farad\n",
- "K=2 #constant\n",
- "\n",
- "#Calculation\n",
- "co=cm/K #calculating co\n",
- "\n",
- "#Result\n",
- "print\"capacity of capacitor with air between the plates= \",co*10**6,\"muF\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "capacity of capacitor with air between the plates= 5.0 muF\n"
- ]
- }
- ],
- "prompt_number": 37
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.23,Page no:140"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "v=100.0 #v in volt\n",
- "c1=8.0*10**-6 #capacitance in Farad\n",
- "c2=12.0*10.0**-6 #capacitance in Farad\n",
- "c3=24.0*10.0**-6 #capacitance in Farad\n",
- "cs=4.0/(10.0**6) #calculating series capacitance\n",
- "\n",
- "#Calculation\n",
- "cp=(c1+c2+c3) #calculating parallel capacitance\n",
- "qs=cs*v #calculating charge\n",
- "\n",
- "#Result\n",
- "print\"Equivalent Series capacitance,C= \",cs*10**6,\"muF\"\n",
- "print\"Equivalent parallel capacitance,Cp= \",cp*10**6,\"muF\" \n",
- "print\"charge on plate=%.e\"%qs,\"C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Equivalent Series capacitance,C= 4.0 muF\n",
- "Equivalent parallel capacitance,Cp= 44.0 muF\n",
- "charge on plate=4e-04 C\n"
- ]
- }
- ],
- "prompt_number": 48
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.24,Page no:141"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "C=9*10**-10 #capacitance in farad\n",
- "V=100.0 #in volt\n",
- "\n",
- "#Calculation\n",
- "U=(1/2.0)*(C*(V**2)) #calculating energy stored\n",
- "\n",
- "#Result\n",
- "print\"Energy stored = \",U,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy stored = 4.5e-06 J\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.25,Page no:141"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "\n",
- "#Variable declaration \n",
- "eo=8.85*10**-12 #constant\n",
- "A=90.0*10**-4 #area in m square\n",
- "d=2.5*10**-3 #distance in m\n",
- "V=400.0 #in volt\n",
- "\n",
- "#Calculation\n",
- "C=(eo*A)/d #calculating capacitance\n",
- "W=(1/2.0)*(C*(V**2)) #calculating electrical energy stored\n",
- "\n",
- "#Result\n",
- "print\"Capacitance = \",C,\"Farad\"\n",
- "print\"Electrical Energy stored in capacitor =%.2e\"%W,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance = 3.186e-11 Farad\n",
- "Electrical Energy stored in capacitor =2.55e-06 J\n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.26,Page no:142"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "v=100 #v in volt\n",
- "c1=1*10**-6 #capacitance in Farad\n",
- "c2=2*10**-6 #capacitance in Farad\n",
- "c3=3*10**-6 #capacitance in Farad\n",
- "cs=6/11.0 #calculating series capacitance\n",
- "\n",
- "#Calculation\n",
- "cp=(c1+c2+c3) #calculating parallel capacitance\n",
- "\n",
- "#Result\n",
- "print\"Equivalent Series capacitance = \",cs,\"muF\"\n",
- "print\"Equivalent parallel capacitance= \",cp*10**6,\"muF\"\n",
- "print\"Therefore Cp=(11*Cs)\" "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Equivalent Series capacitance = 0.545454545455 muF\n",
- "Equivalent parallel capacitance= 6.0 muF\n",
- "Therefore Cp=(11*Cs)\n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example no:4.27,Page no:143"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "#Variable declaration \n",
- "eo=8.85*10**-12 #constant\n",
- "V=6 #v in volt\n",
- "A=25*10**-4 #area in m square\n",
- "d=10**-3 #distance in m\n",
- "\n",
- "#Calculation\n",
- "q=(eo*A*V)/d #calculating charge\n",
- "W=q*V #calculating work done\n",
- "\n",
- "#Result\n",
- "print\"Charge through battery =%.3g\"%q,\"C\"\n",
- "print\"Work done by Battery=%.e\"%W,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge through battery =1.33e-10 C\n",
- "Work done by Battery=8e-10 J\n"
- ]
- }
- ],
- "prompt_number": 63
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file
generated by cgit (git 2.34.1) at 2025-01-25 03:25:06 +0000