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diff --git a/sample_notebooks/MohitChauhan/Chapter_5.ipynb b/sample_notebooks/MohitChauhan/Chapter_5.ipynb new file mode 100644 index 00000000..d93530be --- /dev/null +++ b/sample_notebooks/MohitChauhan/Chapter_5.ipynb @@ -0,0 +1,284 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:40246af5736342db0b706a17990458bf898d0d1dfd632473c65bf3a52df25d34" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 05 - Bipolar Junction Transistors" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.1 : Page No - 243" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "I_C= 5.10;# in mA\n", + "I_E= 5.5;# in mA\n", + "alpha= I_C/I_E;\n", + "alpha_dc= alpha;\n", + "print \"The common-base d.c. current gain = %0.2f \" %alpha_dc\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The common-base d.c. current gain = 0.93 \n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.2 : Page No - 243" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "# Given data\n", + "alpha= 0.987;\n", + "I_E= 10.;# in mA\n", + "# Formula alpha= I_C/I_E;\n", + "I_C= alpha*I_E;# in mA\n", + "I_B= I_E-I_C;# in mA\n", + "print \"The base current = %0.2f mA \" %I_B\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The base current = 0.13 mA \n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.4 : Page No - 249" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "alpha= 0.967;\n", + "I_E= 10.;# in mA\n", + "# Formula alpha= I_C/I_E;\n", + "I_C= alpha*I_E;# in mA\n", + "I_B= I_E-I_C;# in mA\n", + "print \"The collector current = %0.2f mA\" %I_C\n", + "print \"The base current = %0.2f mA \" %I_B\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The collector current = 9.67 mA\n", + "The base current = 0.33 mA \n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.5 : Page No - 250" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "Beta= 100.;\n", + "I_E= 10.;# in mA\n", + "alpha= Beta/(1+Beta);\n", + "print \"The value of alpha = %0.2f\" %alpha\n", + "# Formula alpha= I_C/I_E;\n", + "I_C= alpha*I_E;# in mA\n", + "I_B= I_E-I_C;# in mA\n", + "print \"The collector current = %0.1f mA \" %I_C\n", + "print \"The base current = %0.1f mA\" %I_B" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The value of alpha = 0.99\n", + "The collector current = 9.9 mA \n", + "The base current = 0.1 mA\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.6 : Page No - 258" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "alpha= 0.950;\n", + "Beta= alpha/(1.-alpha);\n", + "print \"For alpha = 0.950, the value of beta = %0.f\" %Beta\n", + "Beta= 100.;\n", + "alpha= Beta/(1.+Beta);\n", + "print \"For beta = 100, the value of alpha = %0.2f\" %alpha\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "For alpha = 0.950, the value of beta = 19\n", + "For beta = 100, the value of alpha = 0.99\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.7 : Page No - 259" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "I_E= 10.;# in mA\n", + "Beta= 100.;\n", + "alpha= Beta/(1.+Beta);\n", + "# Formula alpha= I_C/I_E;\n", + "I_C= alpha*I_E;# in mA\n", + "I_B= I_E-I_C;# in mA\n", + "print \"The base current = %0.3f mA \" %I_B\n", + "print \"The collector current = %0.3f mA\" %I_C" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The base current = 0.099 mA \n", + "The collector current = 9.901 mA\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example No -5.8 : Page No - 263" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given data\n", + "%matplotlib inline\n", + "import math\n", + "import numpy as np\n", + "import matplotlib.pyplot as plt\n", + "V_CC= 12.;# in V\n", + "R_C= 3.;# in kohm\n", + "V_CE= np.linspace(0,12,num=120);# in V\n", + "I_C= np.zeros(120)\n", + "for i in range(0,120):\n", + "\tI_C[i]= (V_CC-V_CE[i])/R_C;# in mA\n", + "\n", + "plt.plot(V_CE,I_C);\n", + "plt.xlabel(\"V_CE in volts\")\n", + "plt.ylabel(\"I_C in mA\")\n", + "plt.title(\"DC load line\")\n", + "plt.show()\n", + "print \"DC load line shown in figure.\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "metadata": {}, + "output_type": "display_data", + "png": 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+ "text": [ + "<matplotlib.figure.Figure at 0x7f6d25333a90>" + ] + }, + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "DC load line shown in figure.\n" + ] + } + ], + "prompt_number": 22 + } + ], + "metadata": {} + } + ] +}
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