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diff --git a/sample_notebooks/kartiksankhla/Chapter2_WEIco2c.ipynb b/sample_notebooks/kartiksankhla/Chapter2_WEIco2c.ipynb new file mode 100644 index 00000000..f12ee152 --- /dev/null +++ b/sample_notebooks/kartiksankhla/Chapter2_WEIco2c.ipynb @@ -0,0 +1,250 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:44c6b2962e60454059ed8ab0f850fa5cf7fde8b83f0146551b8d869bf0ff197f"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter2-Basic Thermodynamics, Fluid\n",
+ "Mechanics: Definitions\n",
+ "of Efficiency"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg39"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate the polyefficency and overall total to total efficiency\n",
+ "\n",
+ "##given data\n",
+ "gamma = 1.4;\n",
+ "pi = 8.;##pressure ratio\n",
+ "T01 = 300.;##inlet temperature in K\n",
+ "T02 = 586.4;##outlet temperature in K\n",
+ "\n",
+ "##Calculations\n",
+ "##Calculation of Overall Total to Total efficiency\n",
+ "Tot_eff = ((pi**((gamma-1.)/gamma))-1.)/((T02/T01)-1.);\n",
+ "\n",
+ "##Calculation of polytropic efficiency\n",
+ "Poly_eff = ((gamma-1.)/gamma)*((math.log(pi))/math.log(T02/T01));\n",
+ "\n",
+ "##Results\n",
+ "print'%s %.2f %s'%('The Overall total-to-total efficiency is ',Tot_eff,'');\n",
+ "print'%s %.2f %s'%('The polytropic efficiency is ',Poly_eff,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The Overall total-to-total efficiency is 0.85 \n",
+ "The polytropic efficiency is 0.89 \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg44"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate the\n",
+ "\n",
+ "##given data\n",
+ "T01 = 1200.;##Stagnation temperature at which gas enters in K\n",
+ "p01 = 4.;##Stagnation pressure at which gas enters in bar\n",
+ "c2 = 572.;##exit velocity in m/s\n",
+ "p2 = 2.36;##exit pressure in bar\n",
+ "Cp = 1.160*1000.;##in J/kgK\n",
+ "gamma = 1.33\n",
+ "\n",
+ "##calculations\n",
+ "T2 = T01 - 0.5*(c2**2)/Cp;##Calculation of exit temperature in K\n",
+ "Noz_eff = ((1.-(T2/T01))/(1.-(p2/p01)**((gamma-1.)/gamma)));##Nozzle efficiency\n",
+ "\n",
+ "##Results\n",
+ "print'%s %.2f %s'%('Nozzle efficiency is ',Noz_eff,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Nozzle efficiency is 0.96 \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex3-pg51"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate the\n",
+ "\n",
+ "##given data\n",
+ "cp = 0.6;##coefficient of pressure\n",
+ "AR = 2.13;##Area ratio\n",
+ "N_R1 = 4.66;\n",
+ "\n",
+ "##calculations\n",
+ "cpi = 1. - (1./(AR**2));\n",
+ "Diff_eff = cp/cpi;##diffuser efficiency\n",
+ "theta = 2.*(180./math.pi)*math.atan((AR**0.5 - 1.)/(N_R1));##included cone angle\n",
+ "\n",
+ "##Results\n",
+ "print'%s %.2f %s'%('cpi = \\n',cpi,'');\n",
+ "print'%s %.2f %s'%('The included cone angle can be found = ',theta,' deg.');\n",
+ "\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "cpi = \n",
+ " 0.78 \n",
+ "The included cone angle can be found = 11.26 deg.\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4-pg52"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate the\n",
+ "\n",
+ "##given data\n",
+ "AR = 1.8;##Area ratio\n",
+ "cp = 0.6;##coefficient of pressure\n",
+ "N_R1 = 7.85;\n",
+ "\n",
+ "##calculations\n",
+ "Theta = 2.*(180./math.pi)*math.atan((AR**0.5 - 1.)/(N_R1));##included cone angle\n",
+ "cpi = 1.-(1./(AR**2));\n",
+ "Diff_eff = cp/cpi;##diffuser efficeincy\n",
+ "\n",
+ "##Results\n",
+ "print'%s %.2f %s'%('The included cone angle can be found = ',Theta,' deg.\\n');\n",
+ "print'%s %.2f %s'%('cpi = \\n',cpi,'');\n",
+ "print'%s %.2f %s'%('Diffuser efficiency = ',Diff_eff,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The included cone angle can be found = 4.98 deg.\n",
+ "\n",
+ "cpi = \n",
+ " 0.69 \n",
+ "Diffuser efficiency = 0.87 \n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex5-pg53"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#calculate the\n",
+ "\n",
+ "##given data\n",
+ "AR = 2.0;##Area ratio\n",
+ "alpha1 = 1.059;\n",
+ "B1 = 0.109;\n",
+ "alpha2 = 1.543;\n",
+ "B2 = 0.364;\n",
+ "cp = 0.577;##coefficient of pressure\n",
+ "\n",
+ "##calculations\n",
+ "cp = (alpha1 - (alpha2/(AR**2))) - 0.09;\n",
+ "Diff_eff = cp/(1.-(1./(AR**2)));##Diffuser efficiency\n",
+ "\n",
+ "##Results\n",
+ "print'%s %.2f %s'%('The diffuser efficiency = ',Diff_eff,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The diffuser efficiency = 0.78 \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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