Added(A)/Deleted(D) following books

 A  Concepts_Of_Physics_(Volume_-_1)_by_H._C._Verma/README.txt
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-10_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-11_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-12_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-13_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-14_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-15_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-16_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-17_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-18_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-19_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-20_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-21_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-22_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-23_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-24_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-25_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-26_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-27_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-28_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-29_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-2_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-31_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-32_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-33_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-34_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-3_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-5_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-7_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-8_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/Chapter-9_1.ipynb
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/README.txt
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/screenshots/29-6Penetration_1.png
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/screenshots/29-7MoleFraction_1.png
A  Fluid_Flow_For_The_Practicing_Chemical_Engineer_by_J._P._Abulencia_And_L._Theodore/screenshots/PressureDrop29_3_1.png
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/Chapter9_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter1_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter2_(1)_1.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter3_(1)_1.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter4_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter6_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter7_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter8_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/chapter_5_10.ipynb
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex1.2_5.png
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex3.7_2.png
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/screenshots/ex6.5_2.png
A  Linear_Integrated_Circuits_by_T._R._Ganesh_Babu/README.txt
A  Power_Plant_Engineering_by_P._K._Nag/README.txt
A  sample_notebooks/MaheshkumarEaga/Chapter_2.ipynb

1 files changed, 442 insertions, 0 deletions

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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 2 : Finite Sample Spaces\n",
+    "\n",
+    "\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.1 , Page number : 21"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Probability of p1 is : 4/7\n",
+      "Probability of p2 is : 2/7\n",
+      "Probability of p3 is : 1/7\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "# p1,p2 and p3 be the probabilities of events a1,a2 and a3\n",
+    "# Probalitity of p1+p2+p3=1 and p1=2*p2 , p2=2*p3\n",
+    "  \n",
+    "\n",
+    "#calculation\n",
+    "p2= 1.0/(2.0+1.0+1.0/2.0)            #p1+p2+p3=1 hence 2p2+p2+p3/3=1  \n",
+    "                                     #p2(2+1+1/3)=1\n",
+    "p1=2.0*p2\n",
+    "p3=1.0/2*p2\n",
+    "\n",
+    "#converstion of floating point value into Fraction and Result\n",
+    "print \"Probability of p1 is :\",Fraction(p1).limit_denominator(1000)\n",
+    "print \"Probability of p2 is :\",Fraction(p2).limit_denominator(1000)\n",
+    "print \"Probability of p3 is :\",Fraction(p3).limit_denominator(1000)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.2 , Page number : 22"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Probability of number greater than 4 in single throw of die :  1/3\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "S = {1,2,3,4,5,6}             #Sample space for single throw of die\n",
+    "A = { }                       #Event occurance of number >4 initially empty\n",
+    "\n",
+    "count=0\n",
+    "\n",
+    "for i in S:                   #counting the number of elements greater than 4\n",
+    " if i>4:\n",
+    "  count=count+1\n",
+    "\n",
+    "x= float (count)/len(S)       # Probability of A\n",
+    "\n",
+    "#Result\n",
+    "print \"Probability of number greater than 4 in single throw of die : \",Fraction(x).limit_denominator(1000)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.3 , Page number : 22"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Probability of number of Heads are 1 in single throw of two coins :  1/2\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "mylist=[0,0,0]                #Initially posiions of list represents number of occurances of H in event\n",
+    "count=0                       #to count total number of possible events\n",
+    "for i in range(0,2):          #method to generate the 2 elemets unordered pairs H and T and 0 represents Head and 1 represents TAIL\n",
+    " for j in range(0,2):\n",
+    "  count=count+1               #counting the total number of order pairs\n",
+    "  if i+j==0:\n",
+    "   mylist[0]=mylist[0]+1\n",
+    "  if i+j==1:\n",
+    "   mylist[1]=mylist[1]+1\n",
+    "  if i+j==2:\n",
+    "   mylist[2]=mylist[2]+1\n",
+    "\n",
+    "x= float(mylist[1])/count     #probability of number of heads are 1\n",
+    "\n",
+    "#Result\n",
+    "print \"Probability of number of Heads are 1 in single throw of two coins : \",Fraction(x).limit_denominator(1000)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.4 , Page number : 24"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "number of ways to select 5 items from 20 items :  15504.0\n",
+      "number of ways to select 5 items from 80 items :  24040016.0\n",
+      "number of ways to select 10 items from 100 items :  1.73103094564e+13\n",
+      "Required probability is :  1/719598\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "#lot has 20 defective and 80 non defective items\n",
+    "#ten items choosen withour replacement such half 5 are defective and 5 are non defective\n",
+    "\n",
+    "def factorial(value):               #Function to calculate factorial\n",
+    " result=1\n",
+    " for i in range(1,value+1):\n",
+    "  result=result*i\n",
+    " return result\n",
+    "  \n",
+    "x=factorial(20);\n",
+    "y=factorial(15);\n",
+    "z=factorial(5);\n",
+    "\n",
+    "slection_from_20=float(x)/(y*z)     #calculating 20!/(15!*5!)\n",
+    " \n",
+    "x=factorial(80);\n",
+    "y=factorial(75);\n",
+    "z=factorial(5);\n",
+    "\n",
+    "slection_from_80=float(x)/(y*z)      #calculating 80!/(75!*5!)\n",
+    "\n",
+    "x=factorial(100);\n",
+    "y=factorial(90);\n",
+    "z=factorial(10);\n",
+    "\n",
+    "slection_from_100=float(x)/(y*z)     # calculating 100!/(90!*10!)\n",
+    "print \"number of ways to select 5 items from 20 items : \",slection_from_20\n",
+    "print \"number of ways to select 5 items from 80 items : \",slection_from_80\n",
+    "print \"number of ways to select 10 items from 100 items : \",slection_from_100\n",
+    "\n",
+    "probability= (slection_from_20+slection_from_80)/slection_from_100\n",
+    "\n",
+    "#Result\n",
+    "print \"Required probability is : \",Fraction(probability).limit_denominator(1000000)\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.5 , Page number : 24"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "number of ways to select 5 items from 20 items :  15504.0\n",
+      "number of ways to select 5 items from 80 items :  24040016.0\n",
+      "number of ways to select 10 items from 100 items :  1.73103094564e+13\n",
+      "Required probability is :  1/719598\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "#lot has 20 defective and 80 non defective items\n",
+    "#ten items choosen withour replacement such half 5 are defective and 5 are non defective\n",
+    "\n",
+    "def factorial(value):              #Function to calculate factorial\n",
+    " result=1\n",
+    " for i in range(1,value+1):\n",
+    "  result=result*i\n",
+    " return result\n",
+    "  \n",
+    "x=factorial(20);\n",
+    "y=factorial(15);\n",
+    "z=factorial(5);\n",
+    "\n",
+    "selection_from_20=float(x)/(y*z)     # calculating 20!/(15!*5!)\n",
+    " \n",
+    "x=factorial(80);\n",
+    "y=factorial(75);\n",
+    "z=factorial(5);\n",
+    "\n",
+    "selection_from_80=float(x)/(y*z)      # calculating 80!/(75!*5!)\n",
+    "\n",
+    "x=factorial(100);\n",
+    "y=factorial(90);\n",
+    "z=factorial(10);\n",
+    "\n",
+    "selection_from_100=float(x)/(y*z)     # calculating 100!/(90!*10!)\n",
+    "probability= (selection_from_20+selection_from_80)/selection_from_100\n",
+    "\n",
+    "#Result\n",
+    "print \"number of ways to select 5 items from 20 items : \",selection_from_20\n",
+    "print \"number of ways to select 5 items from 80 items : \",selection_from_80\n",
+    "print \"number of ways to select 10 items from 100 items : \",selection_from_100\n",
+    "print \"Required probability is : \",Fraction(probability).limit_denominator(1000000)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.7 , Page number : 28"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Subproblem 1 : Number of ways of forming committee of 3 members is :  56\n",
+      "Subproblem 2 : Numberof signals made up of 3 flags are :  336\n",
+      "Subproblem 3 : Total number of committes formed are :  30\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "def factorial(value):\t\t\t#Function to calculate factorial\n",
+    " result=1\n",
+    " for i in range(1,value+1):\n",
+    "  result=result*i\n",
+    " return result\n",
+    "  \n",
+    "#subproblem a  Committee selection problem\n",
+    "\n",
+    "x=factorial(8);\t\n",
+    "y=factorial(5);\t\n",
+    "z=factorial(3);\n",
+    "selecting_3_from_8 = x/(y*z)\n",
+    "#Result\n",
+    "print \"Subproblem 1 : Number of ways of forming committee of 3 members is : \",selecting_3_from_8\n",
+    "\n",
+    "\n",
+    "\n",
+    "#subproblem b flag problem\n",
+    "\n",
+    "x=factorial(8);\t\n",
+    "y=factorial(5);\t\n",
+    "\n",
+    "number_of_ways = x/y\n",
+    "#Result\n",
+    "print \"Subproblem 2 : Numberof signals made up of 3 flags are : \",number_of_ways\n",
+    "\n",
+    "\n",
+    "#Sub problem 3 : committee\n",
+    "x=factorial(5);\t\n",
+    "y=factorial(3);\t\n",
+    "z=factorial(2);\n",
+    "selecting_2_men_from_5 = x/(y*z)\n",
+    "\n",
+    "x=factorial(3);\t\n",
+    "y=factorial(1);\t\n",
+    "z=factorial(2);\n",
+    "selecting_1_women_from_3 = x/(y*z)\n",
+    "\n",
+    "total_committes=selecting_2_men_from_5*selecting_1_women_from_3\n",
+    "\n",
+    "#Result\n",
+    "print \"Subproblem 3 : Total number of committes formed are : \",total_committes"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Example 2.9, Page number : 29"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Listing the number of ways of selecting 2 objects from 4 objects without repetition or ordered \n",
+      "a b\n",
+      "a c\n",
+      "a d\n",
+      "b c\n",
+      "b d\n",
+      "c d\n",
+      "Probability of object c is choosen without repetition is :  1/2\n",
+      "Listing the number of ways of selecting 2 objects from 4 objects with repetition OR unordered\n",
+      "a a\n",
+      "a b\n",
+      "a c\n",
+      "a d\n",
+      "b a\n",
+      "b b\n",
+      "b c\n",
+      "b d\n",
+      "c a\n",
+      "c b\n",
+      "c c\n",
+      "c d\n",
+      "d a\n",
+      "d b\n",
+      "d c\n",
+      "d d\n",
+      "Probability of object c is choosen without repetition is :  7/16\n"
+     ]
+    }
+   ],
+   "source": [
+    "from fractions import Fraction\n",
+    "\n",
+    "mylist=['a','b','c','d']                     #Objects in sample space\n",
+    "c_count_with_repeat=0\n",
+    "c_count_without_repeat=0\n",
+    "totalways=0\n",
+    "\n",
+    "print \"Listing the number of ways of selecting 2 objects from 4 objects without repetition or ordered \"\n",
+    "for i in range(0,4):\n",
+    " for j in range (i+1,4):\n",
+    "  totalways=totalways+1                     #counting number of ways of orderd listing\n",
+    "  print mylist[i],mylist[j]                 #Listing ordered pairs\n",
+    "  if(mylist[i]=='c' or mylist[j]=='c'):     #checking the object c selected or not while selection atleast once\n",
+    "   c_count_without_repeat=c_count_without_repeat+1\n",
+    "\n",
+    "probability_c_without_repeat=float( c_count_without_repeat)/totalways     #calculating probability of object c selected without repetition \n",
+    "\n",
+    "#Result\n",
+    "print \"Probability of object c is choosen without repetition is : \",Fraction(probability_c_without_repeat).limit_denominator(1000)\n",
+    "\n",
+    "\n",
+    "totalways=0\n",
+    "print \"Listing the number of ways of selecting 2 objects from 4 objects with repetition OR unordered\"\n",
+    "for i in range(0,4):\n",
+    " for j in range (0,4):\n",
+    "  totalways=totalways+1                     #counting number of ways of unorderd listing\n",
+    "  print mylist[i],mylist[j]                 #Listing unordered pairs\n",
+    "  if(mylist[i]=='c' or mylist[j]=='c'):     #checking the object c selected or not while selection atleast once\n",
+    "   c_count_with_repeat=c_count_with_repeat+1\n",
+    "\n",
+    "probability_c_with_repeat=float( c_count_with_repeat)/totalways      #calculating probability of object c selected with repetition\n",
+    "\n",
+    "#Result\n",
+    "print \"Probability of object c is choosen without repetition is : \",Fraction(probability_c_with_repeat).limit_denominator(1000)"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.11"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}